MATHEMATICS HIGH SCHOOL

The minimum of a parabola is located at (-1,-3).the point (9,1) Is also on the graph which equation can be solved to determine the value in the function representing the parabola?

Answers

Answer 1
Answer:

Answer:

(8,-2)

Step-by-step explanation:

9-1 and 1-3

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Suppose the Cote family truly enjoys digestive biscuits.Late one night, Papa Cote ate one-sixth of the family's digestives.Early the next morning, Mama Cote ate one-fifth of the remaining biscuits.Shortly thereafter, Brother Cote consumed one-quarter of the delicious snacks left.At lunchtime, Sister Cote devoured one-third of the remaining tasty treats.Finally, Baby Cote ate one-half of the remaining digestive biscuits.How many delightful digestive biscuits were at first?I can't quite figure out how to solve this... I would imagine that there should be an end amount or some value from in between... I just don't know. Please help?
Multiply your answer should be a monomial in standard form (-4x^2)(7x^3)
A local cinema found that if the price of admission was $17the attendance was about 1900 customers per weekWhen the price of admission was dropped to $9. Attendance increased to about 3050 per week. Write a equation for the attendance in terms of the price. P i (A=mp+b )
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Set up a proportion to solve for x in the following similar triangles.

Please help I have this due by tomorrow

Answers

Answer:

1) Linear Pair

2) Adjacent

3) Complmentary

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What are two different decimals that when rounded to the nearest thousandth would give 5.24 as an answer

Answers

Answer: 5.2387 and 5.2437

Step-by-step explanation:

2/5 / 2/3 how to divide fractions?

Answers

you use KCF- keep change flip 
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What is the solution to the quadratic equation 8m^2+7m-15=-7 ?

Answers

make equal to zero
add7 both sides
8m^2+7m-8=0
quadratic fomrula

if you have
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^(2)-4ac} }{2a}

8m^2+7m-8=0
a=8
b=7
c=-8

x=\frac{-7+/- \sqrt{7^(2)-4(8)(-8)} }{2(8)}
x=(-7+/- √(49+256) )/(16)
x=(-7+/- √(305) )/(16)

x=(-7+ √(305) )/(16) or x=(-7- √(305) )/(16)

aprox
x=-1.52902 or 0.654016

Darnell’s house was valued at $134,670 and it appreciated 3 percent per year. What is its value after 2 year? Round to the nearest dollar. A: $8,201 B:$142,871 C:$126,939 D:$277,541

Answers

Answer:

Option B is correct.

Step-by-step explanation:

Given: Value of House, P = $ 134,670

           Rate of depreciation, R = 3% per year

           Time, T = 2 years   ⇒ n = 2

To find: value of house after 2 year that is A.

We know that

A=P(1-(R)/(100))^n

A=134670(1+(3)/(100))^2

A=134670*1.0609

A = 142871.403

A = $ 142871

Therefore, Option B is correct.
134,670×(1+0.03)^(2)=142,871

Square root of 4+2 root 3

Answers

(a+b)^2=a^2+2ab+b^2\ \ \ (*)\n\n\n√(4+2\sqrt3)=√(3+2\sqrt3+1)=\sqrt{\underbrace{(\sqrt3)^2+2\cdot\sqrt3\cdot1+1^2}_((*))}\n\n=√((\sqrt3+1)^2)=|\sqrt3+1|=\sqrt3+1
(a+b)^2=a^2+2\cdot a\cdot b+b^2\n \n4+2 √(3)=1^2+2\cdot1\cdot √(3)+ √(3) ^2\ \ \ \Rightarrow\ \ \ a=1\ \ \ \wedge\ \ \ b= √(3) \n \n4+2 √(3) =(1+ √(3) )^2\n \n \sqrt{4+2 √(3)} = \sqrt{(1+ √(3) )^2} =|1+ √(3) |=1+ √(3)
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