A normal curve with a mean of 500 and a standard deviation of 100 is shown. Shade the region under the curve within one standard deviation of the mean. How much of the data falls within the shaded region?
A normal curve with a mean of 500 and a - 1

Answers

Answer 1
Answer:

Answer:

The region between one standard deviation from the mean is (400,600) which should be 68.27% of the data.

Step-by-step explanation:

The mean of this data set is 500 and the standard deviation is 100. The data that are within one standard deviation of the mean, must be in the range between 400 and 600, which according to the normal curve should be about 68.27% of the samples. The shaded region is shown in red on the attached figure.


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Mike can cut a 40 foot by 20 foot yard with a push mower in 25 minutes. At this rate, how many more minutes would it take him to cut a 40 foot by 30 foot yard?

Answers

The time required to cut the area of 40 feet by 30 feet will be 37.5 minutes.

What is an expression?

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that Mike can cut a 40-foot by 20-foot yard with a push mower in 25 minutes. The time required for 40 foot x 30-foot area will be calculated as:-

40 x 20 foot yard = 25 minutes

800-foot yard = 25 minutes

1 foot yard = 25 / 800

( 40 x 30 ) foot yard = ( 25 / 800 ) x ( 40 x 30 )

1200 foot yard = ( 25 / 800 ) x ( 1200)

1200-foot yard = 37.5 minutes

Therefore, the time required to cut the area of 40 feet by 30 feet will be 37.5 minutes.

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area of the yard is  40 .20  =  800sq ft
time taken = 25 mins
time taken to mow 1sq ft  =      25/800 mins
time taken to mow  40 .30 =1200sq ft  =      ( 25 .1200)/800 =    371/2 mins
thus the extra time  taken will be      371/2-25 =    121/2 mins

The distance you travel while hiking is a function of how fast you hike and how long you hike at this rate. You usually maintain a speed of three miles per hour while hiking. Write a statement that describes how the distance that you travel is determined. Then identify the independent and dependent variables of this function.

Answers

If hours is represented as h, your distance is therefore 3*h (due to that for every hour, you walk 3 miles. For example, in one hour you'd walk 3 miles, in 2 hours you'd walk 3+3=3*2=6 miles,etc.). If distance is represented by d, we get 3*h=d. Since you have to figure out the distance from the equation (that's the purpose of it!), the distance is the dependent variable. In addition, since you can't have 2 separate variables in one equation, h is the independent variable due to that you have to put a number for h in to figure out the distance 

Answer:d

Step-by-step explanation:

PLEASE HELP MEEEEEEEEEEEEE

Answers

Answer: 20 ft

Step-by-step explanation:

The mirror is set away from the flagpole on the same scale set away from her.

The distance she stand's away from the mirror is 1/4 of the length of the distance between the mirror and the flag pole because she's 1/4 of the flagpole's size.

This means her size x4 is the size for the flag pole. This checks out because 12x4=48

So to find the height we must do 5x4

5x4=20

Convert 2000 g/l to the unit g/ml

Answers

(2 \000 g)/(l) = \ ? \ (g)/(ml) \n \n 1 \ l = 1 \ 000 \ ml \n \n(2\ 000 \ g)/(l) =(2 \000 \ g)/(1 \000\ ml) = 2.0 \ \ (g)/(ml)


(2000\ g)/(l) =(2000\ g)/(1000\ ml) = (2\ g)/(l) =2\ (g)/(l)

The formula below gives D, the demand for concert tickets when the price of each ticket is P dollars. D(p)=2000-4p-p^2
What's the value if D(15)

Answers

D(15)=1715
D(15)=2000-4(15)-15^2
You do this because p=15 and you know this because 15 is inside the parentheses by d (D(p)) 

Yall please hurry i WILL MARK BRAINLEST IF CORRECT OR FOR FIRST PERSONWhich statement is correct? StartFraction 3.56 times 10 Superscript 2 Baseline Over 1.09 times 10 Superscript 4 Baseline EndFraction less-than-or-equal-to (4.08 times 10 Superscript 2 Baseline) (1.95 times 10 Superscript negative 6 baseline) StartFraction 3.56 times 10 Superscript 2 Baseline Over 1.09 times 10 Superscript 4 Baseline EndFraction less-than (4.08 times 10 Superscript 2 Baseline) (1.95 times 10 Superscript negative 6 baseline) StartFraction 3.56 times 10 Superscript 2 Baseline Over 1.09 times 10 Superscript 4 Baseline EndFraction greater-than (4.08 times 10 Superscript 2 Baseline) (1.95 times 10 Superscript negative 6 baseline) StartFraction 3.56 times 10 Superscript 2 Baseline Over 1.09 times 10 Superscript 4 Baseline EndFraction = (4.08 times 10 Superscript 2 Baseline) (1.95 times 10 Superscript negative 6 baseline)

Answers

Answer:

A EDGE 2021!

Step-by-step explanation: