Multiply (x + 3)(x – 3). A. x2 + 6x + 9
B. x2 – 9
C. x2 + 6x – 9
D. x2 – 6x + 9
I can't focus.
Answers
Answer:
The answer is B.
Step-by-step explanation:
This problem represents a "the Sum and Difference of the same two terms".
If you encounter the same two terms and just the sign between them changes, rest assured that the result is the square of those two terms. Also, the second term will always be negative.
For example:
So, in this case:
Therefore, the answer is B.
Related Questions
Nelson Middle school raised 19,950 on ticket sales for its carnival fundraiser last year at $15 per ticket. If the school sells the same number of tickets this year but charges $20 per ticket,how much money will the school make
The sum of two integers is -123.If one of them is 325 , what is the other?
URGENT PLEASE HELP ME WITH THIS MATH QUESTION
Can someone help me??
Answers
(
x
)
=
3
x
−
7
and
g
(
x
)
=
3
x
, evaluate
f
(
g
(
−
1
)
)
Answers
Answer: f(g(-1)) = -16
Step-by-step explanation:
First, we need to find g(−1), which means we substitute -1 in place of x in the function g(x):
g(-1) = 3(-1) = -3
Next, we substitute g(-1) into f(x):
f(g(-1)) = f(-3) = 3(-3) - 7 = -16
Therefore, f(g(-1)) = -16.
Answers
Answer:To solve the equation 4x + 17/18 - 13x - 2/17x - 32 + x/3 = 7x/12 - x + 16/36, we can follow these steps:
1. Combine like terms on each side of the equation.
On the left side, we have 4x - 13x + x/3. Simplifying this, we get -8x + x/3.
On the right side, we have 7x/12 - x + 16/36. Simplifying this, we get -5x/12 - x + 4/9.
2. Get rid of any fractions by multiplying each term by the least common denominator (LCD).
The LCD of 3, 12, and 36 is 36. Multiply each term on both sides of the equation by 36 to eliminate the fractions.
3. Simplify and combine like terms.
On the left side, we have -8x + x/3, which becomes -24x + x^2/3 after multiplying by 36.
On the right side, we have -5x/12 - x + 4/9, which becomes -15x - 3x + 16 after multiplying by 36.
4. Move all terms to one side of the equation.
Combining like terms, we get -24x + x^2/3 = -18x + 16.
5. Multiply the entire equation by 3 to eliminate the fraction.
This gives us -72x + x^2 = -54x + 48.
6. Move all terms to one side of the equation again.
Combining like terms, we get x^2 + 18x - 48 = 0.
At this point, the equation is a quadratic equation. To solve it, we can either factor or use the quadratic formula.
(SHOW ALL YOUR WORK)
Answers
Answer:
Part a) The value of x is 10
Part b) The perimeter of triangle JKL is
Step-by-step explanation:
Part a) Find the value of x
we know that
The Triangle Proportionality Theorem, states that if a line parallel to one side of a triangle intersects the other two sides of the triangle, then the line divides these two sides proportionally
Part b) we know that
The perimeter of triangle JKL is equal to
substitute the values
substitute the value of x
Answers
Answer:
The area of one rectangle is 15 cm²
Step-by-step explanation:
The given parameters are;
The area of the square = 64 cm²
The length of the rectangles = 5 cm
The formula for the area of a square = (Side length)² = S²
Therefore, whereby the side length of the given square = S, we have;
Area of the square = 64 = S × S = S²
S = √(64 cm²) = 8 cm
The side length of the square = 8 cm
The perimeter of a square = The length of the string = Side length × 4 = 8 cm × 4 = 32 cm
∴ The perimeter of a square = The length of the string = 32 cm
The length of the string = The perimeter of the two congruent rectangle = 32 cm
Therefore;
The perimeter of each rectangle = 32/2 cm = 16 cm
Given that the length, L of the side of each rectangle is L = 5 cm, we have;
The perimeter of a rectangle = 2 × L + 2 × W
Where;
W = The width
The perimeter of the rectangle = 16 = 2 × 5 + 2 × W
2 × W = 16 - 2 × 5 = 6
W = 6/2 = 3
W = 3 cm
The width, W, of each rectangle is W = 3 cm
The area of one rectangle = W × L = 3 cm × 5 cm = 15 cm²
The area of one rectangle = 15 cm².
3x-4y=12
2x+4Y=-12