Answer:
2
Step-by-step explanation:
Because the base of the first is 6 and the second is 3 so 6/3 = 2
Answer:
1/2
Step-by-step explanation:
scale factor=(3 horizontal squares)/(6 horizontal squares)=1/2
B. If the item was marked up by 1/2 before it was placed on the sales floor, what was the price that the store paid for the digital player?
C. What is the difference between the discount price and the price that the store paid for the digital player?
A. OriginalPrice of music player = $170.67
B. The price that store paid for the player = $256
C. Difference between the discount price and price that the store paid = $128
Markup refers to the value that a payer adds to the cost price of a product. The value added is called the mark-up. The mark-up added to the cost price usually equals retailprice.
Markdown represents the difference between the original or full price of an item and the current price that's reduced. It's typically expressed as a percentage. Markdown allows retailers to sell their products at a lower rate.
Given, A hand-held digital music player was marked down by 1/4 of the original price.
Let the original price be x.
Then discount = x/4
So, Sale price = x- x/4 = 3x/4.
A. sale price given = $128
⇒ 3x/4 = 128
⇒ x = 128 × 4/3
⇒ x = 512/3 = 170.67
The original price $170.67
B. The item was marked up by 1/2 before it was placed on the sales floor.
then cost = $170.67 + $170.67 × 1/2
cost = $ 170.67 + $85.335
cost = $256.005 = $256
C. Difference between the discount price and price the store paid for the digital player
= cost - sales price = $256 - $128
= $128
Hence,
A. $170.67 is the originalprice of the digital music player.
B. Store paid price of $256 before it was placed on sales floor.
C. There was difference of $128 between discount price and the price store paid for the digital player.
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It was marked down 1/4 of the original price to $128. That means $128 is equal to 3/4 of the original price. So the original price would be 4/3 of $128. I get $170.67 (rounded to the nearest cent).
Answer:
A:a , s:soon ,A : as,P: possible
Answer:
Equation 3
Step-by-step explanation:
Lets see which of the functions has -2 as a zero root. We will go in order:
(1) (-2)^4 - 3(-2)^3 + 3(-2)^2 -3(-2) + 2 = 16 - 3(-8) + 3(4) + 6 +2 = 16 +24 +12 + 6 +2 =60 >0
So, (1) is wrong!
(2) (-2)^4 + 3(-2)^3 + 3(-2)^2 - 3(-2) - 2 = 16 - 24 + 12 + 6 - 2 =34 - 26 = 8 > 0
(2) is also wrong!
(3) (-2)^4 + 3(-2)^3 + 3(-2)^2 +3(-2) + 2 = 16 - 24 + 12 - 6 + 2 = 30 -30 = 0
The zero root x=-2 fits, what about x=-1?
(-1)^4 + 3(-1)^3 + 3(-1)^2 +3(-1) + 2 = 1 - 3 + 3 - 3 + 2 = 6 - 6 = 0
So, equation (3) fits both!
Finally, lets see (4):
(-2)^4 - 3(-2)^3 - 3(-2)^2 + 3(-2) + 2 = 16 + 24 - 12 - 6 + 2 = 42 - 18 = 24 > 0
So, (4) is also wrong.
Only equation 3 fits both zero roots!
The quartic function with x=-1 and x=-2 real roots is x^4+6x^3 +12x^2+12x+4. Quartic functions are polynomial functions of degree 4; quadratic equations resources also help understand the concept. In essence, finding roots of quartic functions follow the same logic as that of quadratic functions.
The subject matter pertains to quartic functions in mathematics. Quartic functions are polynomial functions with a degree of 4. From the question, the given zeros are x=-1 and x=-2, having multiplicity of 2 each (since there are only two real zeros). Thus, the quartic function with these zeros will be (x+1)^2*(x+2)^2. This can be expanded to x^4+6x^3 +12x^2+12x+4.
Exemplifying the relevance of The Solution of Quadratic Equations, normally known as second-order polynomials or quadratic functions, such equations can also be used to find zeros of the functions when set to equal zero. In this scenario, quartic functions are a degree higher, but the same principle applies in finding the roots when the equation is set equal to zero.
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