Mr. Zero bought a number of gold pieces for $60. He kept 15 of them and sold the rest for $54. He made a profit of $0.10 on each of those he sold. How many gold pieces did he buy? a) 60 b) 120 c) 75 d) 150
WILL AWARD BRAINLIEST !!!!!!!!

Answers

Answer 1
Answer:

Answer:

c

Step-by-step explanation:


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Find two numbers the exact answer is between 6×7,381

Answers

the answer is 44286 hopes this helps and always good luck

Gerardo says that a cube with edges measure 10 centimeters has a volume that is twice as much as a cube with sides that measure 5 centimeters. Explainand correct Gerardo's error.

Answers

V=LWH
cube
V=L^3
if it is doubled, then each dimention (LWH) is dobubled
since L=W=H
V=(2L)^3
V=8L^3
compared to orignal
L^3 vs 8L^3 it is 8 times more


demonstarte

10^3=1000
5^3=125
1000/125=8, not 2

10. the quotient is 58 and the remainder is 3. What is the number​

Answers

Answer:

Step-by-step explanation: 58 - 3 = 55.

Dianna earns $8.50 an hour working as a lifeguard write an equation to find Dianna’s money earned?

Answers

y = 8.50h

h is for number of hours, can be changed to different letter if preferred

How many times can 80 go into 103

Answers

1 with a remainder of 23
       it is              1r.23
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the base of a regular pyramid is a hexagon whose perimeter is 84 feet. the volume of the pyramid is approximately 4,677.85 cubic feet. find the height of the pyramid.

Answers

Answer:

The height of the pyramid is 27.56\ ft

Step-by-step explanation:

we know that

The volume of the pyramid is equal to

V=(1)/(3)BH

where

B is the area of the base of the pyramid

H is the height of the pyramid

step 1

Find the area B of the regular hexagonal base

we know that

The perimeter of a regular hexagon is

P=6b

where

b is the length side of the hexagon

we have

P=84\ ft

substitute

84=6b

solve for b

b=14\ ft

Remember that the area of a regular hexagon is the same that the area of six equilateral triangles

Determine the area of the six equilateral triangles, applying the formula of the law of sines

B=6[(1)/(2)b^2sin(60\°)]

substitute the value of b

B=6[(1)/(2)(14)^2sin(60\°)]

B=509.22\ ft^2

step 2

Find the height of the pyramid

V=(1)/(3)BH

we have

V=4,677.85\ ft^3

B=509.22\ ft^2

substitute

4,677.85=(1)/(3)(509.22)H

solve for H

14,033.55=(509.22)H

H=14,033.55/(509.22)H

H=27.56\ ft