PHYSICS HIGH SCHOOL

Why do you think sound travels faster in steel than it does in wood? (Hint: Think about the densities of the two materials, and how the particles might be arranged.)

Answers

Answer 1
Answer:

Answer:

If sound waves of the same energy were passed through a block of wood and a block of steel, which is more dense than the wood, the molecules of the steel would vibrate at a slower rate. Sound moves faster through denser air because the molecules are closer together in dense air and sound can be more easily passed on.

Explanation:

Related Questions

Which pair of terms best describes a wooden table?
I have three questions. John has to hit a bottle with a ball to win a prize. He throws a 0.4 kg ball with a velocity of 18 m/s. It hits a 0.2 kg bottle, and the bottle flies forward at 25 m/s. How fast is the ball traveling after hitting the bottle? 2. Someone fires a 0.04 kg bullet at a block of wood that has a mass of 0.5 kg. (The block of woof is sitting on a frictionless surface, so it moves freely when the bullet hits it). The wood block is initially at rest. The bullet is traveling 300 m/s when it hits the wood block and sticks inside it. Now the bullet and the woof block move together as one object. How fast are they traveling? 3. A big league hitter attacks a fastball. The ball has a mass of 0.16 kg. It is pitched at 38 m/s. After the player hits the ball, it is now traveling 44 m/s in the opposite direction. The impact lasted 0.002 seconds. How big of a force did the ballplayer put on that ball?
A jeep-like vehicle has a canvas top that seals around all sides. When the jeep is at rest, the canvas roof is flat and level. If all the windows of the jeep are rolled up, and the jeep is traveling along the road at high speed, how does the canvas roof react?
Which shows the correct order of forces, from weakest to strongest?o weak, strong, gravitational, electromagneticO electromagnetic, weak, strong, gravitationalO gravitational, weak, electromagnetic, strongO weak, electromagnetic, gravitational, strong
A bartender slides a beer mug at 1.7 m/s towards a customer at the end of a frictionless bar that is 1.0 m tall. The customer makes a grab for the mug and misses, and the mug sails off the end of the bar. (a) How far away from the end of the bar does the mug hit the floor? m (b) What are the speed and direction of the mug at impact?

The weight of a body floating in a liquid is​

Answers

Answer:

The apparent weight is the weight of the body minus the weight of the liquid displaced. The body will float only when both the weights are same. In this case, the given body of weight W is floating and hence the apparent weight is zero.

Answer:

Zero

Explanation:

The apparent weight is the weight of the body minus the weight of the liquid displaced. The body will float only when both the weights are same. In this case, the given body of weight W is floating and hence the apparent weight is zero.

When magnesium (Mg2+) and fluorine (F1-) combine in an ionic bond, the resulting formula will be A) Mg2F.


B) Mg2F2.


C) MgF.


D) MgF2.

Answers

Answer is: D) MgF₂.

Magnesium fluoride is salt, ionic compound.

1) Magnesium (Mg) is metal from 2. group of Periodic table of elements and has low ionisation energy and electronegativity, which means it easily lose valence electons (two valence electrons).

Magnesium has atomic number 12, which means it has 12 protons and 12 electrons. It lost two electrons to form magnesium cation (Mg²⁺) with stable electron configuration like closest noble gas neon (Ne) with 10 electrons.

Electron configuration of magnesium ion: ₁₂Mg²⁺ 1s² 2s² 2p⁶.

2) Fluorine (F) is nonmetal with greatest electronegativity, which meand it easily gain electrons.

Fluorine jas atomic number 9, which means it has 9 protons and 9 electrons. It gain one electron to form fluorine anion (F⁻) with stable electron configuration like closest noble gas neon (Ne) with 10 electrons.

Electron configuration of fluorine ion: ₉F⁻ 1s² 2s² 2p⁶.
The fluorine has one spare electron per atom and the magnesium has a need for 2. This means for one magnesium you need two fluorine atoms making the formula MgF2.

Parallel light waves hit the surface of a still lake and reflect in the same direction. Which interaction of light and matter does this illustrate?

Answers

Parallel light waves hit the surface of a still lake and reflect in the same direction and the interaction of light and matter that it illustrates is called regular reflection. Regular reflection occurs whenever the reflecting surface is very smooth. The surface of the still lake is smooth. I hope the answer helps you.

Answer:

regular reflection

Explanation:

Gradpoint

How much force is needed to accelerate a 1000-kg car at a rate of 3 m/s2

Answers

In the given question we already know the mass of the car. The mass of the car is 1000 kg. The acceleration at which the car needs to reach is 3 m/s^2. Based on these information's, the required answer can be easily deduced. We already know that
Force = Mass * Acceleration
           = (1000 * 3) newton
           = 3000 newton
So the amount of force that is required to move give the car an acceleration of 3m/s^2 is 3000 Newton.

The acceleration due to gravity on the surface of Jupiter is about 2.5 times the acceleration due to gravity on Earth’s surface. What would be the weight of a space probe on the surface of Jupiter?A.2.5 times lighter than on Earth
B.6.25 times heavier than on Earth
C.2.5 times heavier than on Earth
D.6.25 times lighter than on Earth

Answers

Answer: The correct answer is option C.

Explanation:

Weight = Mass × Acceleration

Let the mass of the space probe be m

Acceleration due to gravity on the earth = g

Weight of the space probe on earth = W

W=m* g

Acceleration due to gravity on the Jupiter = g' = 2.5g

Weight of the space probe on earth = W'

W'=mg'=m* 2.5g

(W')/(W)=(m* 2.5g)/(m* g)

W'=2.5* W

The weight of the space probe on the Jupiter will be 2.5 times the weight of the space probe on earth.

Hence, the correct answer is option C.

Answer:

2.5 times heavier than on Earth

Explanation:

two pendulums of lengths 100cm and 110.25cm start oscillating in phase. after how many oscillations will they again be in same phase?

Answers

Angular frequency of pendulum is given by

\omega = \sqrt{(g)/(l)}

for both pendulum we have

\omega_1 = \sqrt{(9.81)/(1.00)}

\omega_1 = 3.13 rad/s

For other pendulum

\omega_2 = \sqrt{(9.81)/(1.1025)}

\omega_2 = 2.98 rad/s

now we have relate angular frequency given as

[tex\omega_1 - \omega_2 = 3.13 - 2.98 = 0.15 rad/s[/tex]

now time taken to become in phase again is given as

t = (2\pi)/(\omega_1 - \omega_2)

t = (2\pi)/(0.15) = 41.88 s

now number of oscillations complete in above time

N = (t)/((2\pi)/(\omega_1))

N = (41.88)/((2\pi)/(3.13))

N = 21 oscillation
Other Questions
A 60 W light bulb at 120 V is left on in your house to prevent burglary, and the power charges 10 cents per kilowatt-hour, how much will it cost to leave the bulb on for 30 days?
Which of the following is the best example of a proper hypothesis? Orange popsicles taste sweeter than grape popsicles. If two objects are dropped at the same height, the heavier object will hit the ground first. Children who wear backpacks do better academically. I think there is no effect on hearing if you listen to loud music only three hours a day.
Which wave top or bottom has the larger frequency
pulls a wagon a distance of 32 meters the handle is above an angle of 20 degrees above horizontal if you pull on it with a force of 27 N what work is it