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Answers

Answer 1
Answer:

Answer:

a= domain = 3x range = 21-3 = 18

b= $200 As 0(B) = Point of origin balance = midway to $400

= 0 < 200 > 400 = midway 200.

c=function notation =  3x -3x + 6 = 21  we change the 3x to cancel out any balance.

d= 4th segment shows day 12 to day 15 across the x axis.

ok we see and count after reading this it has 21 days in total approx and 12th day it shows the function went to 12 days.

We can write F(x) = 12x+6 to equal the change in value then we need to distribute 12 x = 6

Which is the same as 9 days money = 6 days money

As 3 days was made reference to day 12- day 15 where she had zero in account. We can minus - 3 also to represent her last savings before adding the balance of 6.

ok no interest the maximum was $400 the zero y intercept (0.0)= $200

This makes everything so easy now.

We count 21 days =  21 this is what we will end with

Let 4 be x

4x -3 + 6  

We count 5 change $  values 0, 1 , 2, 3, 4 on the graph and also 4 in repeat which makes the 400.

or could mean she started with 400 and the rest is interest. Now we know this we cna start writing a domain and i will keep this open and edit and try work this out for you.

Step-by-step explanation:

The last step for question one is converting 12 into 12

This means 4x = 3 so we change it to

3x -3 +6 = 21

Then you now can recognize and accept x = 4

Answer 2
Answer:

Answer:

(a)

Domain: 0 to 21

Range: 0 to 400

(b)

B(0) = 200.

(c)

B(12) = 0

(d)

Segment 4. The value of B(d) in Segment 4 is 0.

Step-by-step explanation:

(a) The domain is the number of days. The range is the amount of money which is the number of dollars. The account was open for 3 weeks, and the graph shows the entire 3 weeks. 3 weeks = 21 days; the highest amount of money was $400.

Domain: 0 to 21

Range: 0 to 400

(b) B(0) is very close to half of the maximum value of B(d). Since the maximum value of B(d) = 400, B(0) = 200. B(0) means the value of the function at time 0. The account was opened with an initial deposit at time = 0. B(0) is the value of the account at time = 0 which is the initial deposit made to open the account.

(c)

B(12) = 0

(d)

There are 6 segments:

Segment 1: B(d) goes from $200 to $400.

Segment 2: B(d) remains at $400.

Segment 3: B(d) goes from $400 to $0.

Segment 4: B(D) remains at $0.

Segment 5: B(d) goes from $0 to $100.

Segment 6: B(d) goes from $100 to $300.

In Segment 4, the value of B(d) is 0, so Segment 4 represents days 12 through 15.


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The areas of two similar polygons are in the ratio 64:81. find the ratio of the corresponding sides.

Answers

If the areas of two similar polygons are in the ration 64:81, then the ratio of their corresponding sides are (8)/(9)

What are polygons?

"A polygon, in geometry, any closed curve consisting of a set of line segments (sides) connected such that no two segments cross."

The simple polygons are triangles (3 sides), quadrilaterals (4 sides), and pentagons (5 sides).

Now if we take the given polygon as square (4 sides).

Then,

Let the sides of squares are a and b.

(a^(2) )/(b^(2) )=(64)/(81) \n(a)/(b)=\sqrt{(64)/(81) } \n(a)/(b)=(8)/(9)

Hence, the ratio of the corresponding sides of polygon is (8)/(9)

Learn more about the polygons here

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Answer is 8:9. The easiest example is a square. If the polygons are squares with areas of 64 and 81 then the sides of the squares are 8 and 9. Therefore, the ratio of the corresponding sides is 8:9

-4(4x+4)=2(2-7x) how do u do this and you have to use WHO and check your answer by plugging it in the original equation.SHOW ALL WORK

Answers

-4(4x+4)=2(2-7x) \n-16x-16=4-14x\n-2x=20\nx=-10\n\n-4(4\cdot(-10)+4)=2(2-7\cdot(-10))\n-4(-40+4)=2(2+70)\n-4\cdot(-36)=4+140\n144=144

Tony has $727.29 in his checking account. He must maintain a $500 balance to avoid a fee. He wrote a check for $248.50 today. Write and solve an inequality to solve for the least amount of money he needs to deposit to avoid a fee.

Answers

The required inequality for the least amount of money he needs to deposit to avoid a fee is 727.29 - 248.50 + x ≥ 500 and he needs to deposit at least $21.21 in her account to avoid a fee.

What is inequality?

A statement of an order relationship-greater than, greater than or equal to, less than, less than or equal to- between two numbers or algebraic equations.

Now it is given that,

Amount in the account = $727.29

Amount in the check = $248.50

Amount need to maintain = $500

Now let x be the Tony needs to deposit.

So, total balance in the account =  727.29 - 248.50 + x

Since, he must maintain a $500 balance to avoid a fee. That means the balance can be greater than or equal to $500.

Thus the required inequality is:

727.29 - 248.50 + x ≥ 500

Adding alike terms,

468.79 + x ≥ 500

Subtracting 468,79 both the side we get,

x ≥ 500 - 468.79

Solving we get,

x ≥ 21.21

Therefore, he needs to deposit at least $21.21 in her account to avoid a fee.

Thus,the required inequality for the least amount of money he needs to deposit to avoid a fee is 727.29 - 248.50 + x ≥ 500 and he needs to deposit at least $21.21 in her account to avoid a fee.

To learn more about inequality:

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inequality is
727.29-248.50+x>500
x=how much she needs to deposit
478.79+x>500
subtract 478.79 from both sides
x>21.21


at least $21.21

What is the LCD of thw fractions 1/3 and 11/15?

Answers

Least common denominator of those two fractions is 15

Because 15 cant go any less

3 × 1 = 3                  15 × 1 = 15
3 × 2 = 6
3 × 3 = 9 
3 × 4 = 12
3 × 5 = 15

Let f be the function defined by f(x) =x^4 -3x^2 +2A)find the zeros of f
B)write an equation of the line tangent to the graph of f at the point where x=1
C) find the x coordinate of each point at which the line tangent to the graph of f is parallel to the line y=-2x+4

Answers

A convenient way to find the zeros of  f(x)=x^4-3x^2 +2 is by factoring.

a) The equation,

x^4-3x^2 +2=0

can be rewritten as,

(x^2)^2-3(x^2) +2=0

We can think of this equation as a quadratic equation in  x^2, with a=1,b=-3\:\: and \:\: c=2.

Observe that ac=1 * 2=2.

We find two factors of 2 that adds up to -3. These are, -2,-1.


Now let us split the middle term. to obtain;

(x^2)^2-(x^2) -2(x^2)+2=0

We can factor to get,

(x^2)(x^2-1)-2((x^2-1)=0

We factor further to obtain;

(x^2-1)((x^2-2)=0

\Rightarrow (x-1)(x+1((x- √(2))(x+ √(2))=0

Hence the zeroes of f(x) are;

x=1,x=-1,x= √(2),x=- √(2)

b) To find the line tangent, we must first, find the slope using differentiation. That is,

Slope\:\: function=f'(x)=4x^3-6x

At x=1,

Slope=f'(1)=4(1)^3-6(1)=-2

Also, we need to determine the y value at x=1. That is;

f(1)=(1)^4-3(1)^2+2=0

Now we can use the slope m=-2 and the point (1,0) to write ythe equation of the line tangent.

y-y_1 =m(x-x_1)

\Rightarrow y-0 =-2(x-1)

\Rightarrow y=-2x+2


c)

If the line tangent is parallel to the line y=-2x+4, then

f'(x)=-2

Since parallel lines have the same slope.

\Righarrow 4x^3-6x=-2

\Righarrow 4x^3-6x+2=0

\Righarrow (x-1)(2x- ( √(3)-1)(2x+ ( √(3)-1)=0

Hence the x-coordinates are,

x=1,x= ( √(3)-1)/(2),x= -(√(3)-1)/(2)











The zeros of the function can be determined by equating the equation to zero and determining the values of x. 
 0 = x4  - 3x2 + 2 the roots are x1 = sqrt 2 x2 = -sqrt 2x3 = 1x4 = -1
The tangent line is determined by differentiating the polynomial and substituting x by 1 to get the slope. That is,  m  = 4x^3 - 6 x = 4*1 - 6 = -2y-y1 = m(x-x1)when x =1 , y = 1-3+2 = 0 
y - 0 = -2*(x-1)y = -2x + 2
c. y = -2x + 4  m = -2 -2 = 4x3 - 6x  x= -1.3666 ; y =-0.1160 x= 1.3666 ; y =--0.1160
x =1 ; y = 0

What is the surface area of a sphere with the given dimension? Express your answer to nearest hundredth. Use 3.14 for pi. Radius = 5cm.

Answers

Surface area of a sphere can be calculated as:

Surface Area = 4πr²

r = 5cm
π = 3.14

Using the values we get:

Surface Area = 4(3.14)(5²) = 314 cm²

Thus, the surface area of the sphere is 314 cm²
Okay. The equation for a sphere's surface area is A = 4 * pi * r^2. Let's plug 5 in for r. 
4 \pi (5^2) = 4(3.14)*25 = 100 * 3.14 = 314
I got 314 cm^2 is the surface area, but it always helps to double check work! Hope this helps!