Although expensive, platinum is used as a catalyst to break down harmful gases in car exhaust into less harmful gases. Which statement best describes platinum in this use? a.It is a homogeneous catalyst, so only a small amount is needed even though it exits with the products.

b.It is a heterogeneous catalyst, so only a small amount is needed and it is easily separated from the products.

c.It is a homogeneous catalyst, so although a large amount is needed, it is easily separated from the products.

d.It is a heterogeneous catalyst, so a large amount is needed and it exits with the products.

Answers

Answer 1

Answer: Platinum is solid at room temperature. SInce the catalyst is solid while the medium involves gases, this catalyst is characterized as heterogenous. Because they are different states of matter, they can be easily separated through physical means. So, the answer is B.

Answer 2

Answer:

Answer:

B EDGE 2022

Explanation:

Related Questions

Semantics is the study of:
A mixture consists of sand and an aqueous saltsolution. Which procedure can be used to separatethe sand, salt, and water from each other?(1) Evaporate the water, then filter out the salt.(2) Evaporate the water, then filter out the sand.(3) Filter out the salt, then evaporate the water.(4) Filter out the sand, then evaporate the water.
Consider the following equilibrium:4KO2(s) + 2H2O(g) 4KOH(s) + 3O2(g)Which of the following is a correct equilibrium expression?A. `"K"_("eq") = (["KOH"]^4["O"_2]^3)/(["KO"_2]^4["H"_2"O"]^2)`B. `"K"_("eq") = (["H"_2"O"]^2)/(["O"_2]^3)`C. `"K"_("eq") = (["KO"_2]^4["H"_2"O"]^2)/(["KOH"]^4["O"_2]^3)`D. `"K"_("eq") = (["O"_2]^3)/(["H"_2"O"]^2)`
Help me with 23 fast
in a molecule of methane, carbon (having four valence electrons) binds to four hydrogen atoms. how many lone pairs of electrons will be represented in the lewis structure of methane? a. four b. two c. one d. zero

All parts of the rock cycle are connected, whether directly or indirectly. Which statementbest shows how sedimentary rocks are related to igneous rocks?
1.Under pressure, sedimentary rocks form from igneous rock.
2.Igneous rocks can weather, creating sediments that form sedimentary rocks.
3. During weathering, sedimentary rocks melt and form igneous rock.
4.Under pressure, igneous rock undergoes changes that form sedimentary rock.

Answers

Answer:

2. Igneous rocks can weather, creating sediments that form sedimentary rocks

Explanation:

Sedimentary rocks are formed from Igneous rocks when rocks are broken down by weathering.

how many milliliters of 1.50 m hno3 contain enough nitric acid to dissolve an old copper penny with a mass of 3.94 g?

Answers

Molar mass HNO₃ = 63.0 g/mol

number of moles = 3.94 / 63.0 => 0.0625 moles

Volume = moles / molarity

V = 0.0625 / 1.50

V = 0.04166 L x 1000 = 41.66 mL

hope this helps!

Final answer:

To dissolve a 3.94g copper penny, we would need approximately 331 milliliters of 1.50 M HNO3, taking into consideration the stoichiometry of the copper-nitric acid reaction.

Explanation:

Stoichiometry is required to solve this chemistry problem. The balanced equation for the reaction between copper and nitric acid is: 3Cu(s) + 8HNO3(aq) → 2NO(g) + 3Cu(NO3)2(aq) + 4H2O(l)

From this, we can conclude that every mole of copper reacts with eight moles of nitric acid. The molecular weight of copper is approximately 63.546 g/mole, so the moles of copper in an old penny can be calculated by mass (3.94 g) divided by the molar mass (63.546 g/mol).

This calculation shows that there are approximately 0.062 moles of copper in a penny. Since we determined that eight moles of nitric acid are required to react with one mole of copper, eight times the moles of copper gives the moles of nitric acid required, which is 0.496 moles.

Since molarity (M) = moles/liters, we can find out the volume of 1.50 M HNO3 required by rearranging the formula to be Liters= moles/Molarity. So, 0.496 moles divided by 1.50 M gives roughly 0.331 liters, which can be converted to approximately 331 milliliters.

Learn more about Stoichiometry here:

brainly.com/question/30218216

#SPJ12

What is the mass of an electron?A. Electrons do not have mass.
B. -1.0 amu
C. 0.0005 amu

Answers

Option C: 0.0005 amu (i.e. atomic mass units), approx.

How many grams of oxygen are required to react with 10.0 grams of octane (C8H18) in the combustion of octane in gasoline?

Answers

Oh fun, stoichiometry. So the equation for this is C8H18+O2----> CO2+H2O, or
2C8H18+25O2----> 16CO2+18H2O when balanced. 10/114.229 g/mol = .087543... mol, converting to moles by dividing by molar mass. The ratio is 25/2, using the integers in front of the molecules in the balanced equation. so you just multiply .087543... by the ratio. That's 1.09429, which you multiply by the molar mass of O2, 31.9988 g/mol. The answer is 35.02 g O2

35.2 grams of oxygen are required to react with 10.0 grams of octane

$\boxed{\boxed{\bold{Further~explanation}}}$

Complete combustion of Hydrocarbons with Oxygen will be obtained by CO₂ and H₂O compounds.

If O₂ is insufficient there will be incomplete combustion produced by CO and H and O

Hydrocarbon combustion reactions (specifically alkanes)

$\large{\boxed {\bold {C_nH _ (_2_n _ + _ 2_) + \frac {3n + 1} {2} O_2 ----> nCO_2 + (n + 1) H_2O}}}$

For gas combustion reaction which is a reaction of hydrocarbons with oxygen produces CO₂ and H₂O (water vapor). can use steps:

Balancing C atoms, H and last atoms O atoms

Octane combustion reaction

C₈H₁₈ + O₂ ---> CO₂ + H₂O

To equalize the reaction equation we give the reaction coefficients with variables a, b and c while the most complex compounds, namely Octane, we give the number 1

So the reaction becomes

C₈H₁₈ + aO₂ ---> bCO₂ + cH₂O

C atom on the left 8, right b, so b = 8

left H atom = 18, right 2c so 2c = 18 ---> c = 9

Atom O on the left 2a, right 2b + 2c, so 2a = 2b + 2c

2a = 2.8 + 9

2a = 16 + 9

2a = 25

a = 25/2

The equation becomes:

C₈H₁₈ + 25/2O₂ ---> 8CO₂ + 9H₂O or be

2C₈H₁₈ + 25O₂ ---> 16CO₂ + 18H₂O

To find the mass O2, we find the mole first from the mole ratio with Octane

1. We are looking for the octane mole

Mr. octane = 8.Ar C + 18.Ar H

Mr. octane = 8.12 + 18.1

Mr octane = 96 + 18

Mr octane = 114

known octane mass: 10 grams then the mole:

mol = gram / Mr

mol = 10/ 114

mol = 0.088

2. We look for the O₂ mole

because of the ratio of the reaction coefficient between O2 and octane = 25: 2 then the mole of O₂ =

25/2 x 0.088 = 1,1

So that the mass O₂ =

mole. Mr = 1.1 32

mass = 35.2 grams

$\boxed{\boxed{\bold{Learn~more}}}$

a combustion reaction

brainly.com/question/12079874

the type of chemical reaction

brainly.com/question/2846778

The combustion of alkanes, alkenes, and alkynes

brainly.com/question/6818114

Complete combustion of a sample of a hydrocarbon

brainly.com/question/5636208

Keywords: Complete combustion of Hydrocarbons, alkanes, equalize the reaction equation

What is the molarity of a solution where 1.00 gram of NaCl (MM 58.5 g/mol)is dissolved in enough water to make 415 mL of solution?
a. 4.12 x 10-5 M

b. 7.09 x 10-3 M

c. 4.12 x 10-2 M

d. 2.41 M

Answers

To find the molarity of the solution, we need to use the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

First, let's calculate the number of moles of NaCl using its molar mass (MM):

Mass of NaCl = 1.00 gram

Molar mass of NaCl = 58.5 g/mol

Moles of NaCl = Mass of NaCl / Molar mass of NaCl

= 1.00 g / 58.5 g/mol

≈ 0.0171 mol

Next, we need to convert the volume of the solution from milliliters (mL) to liters (L):

Volume of solution = 415 mL = 415 / 1000 L

= 0.415 L

Now, we can calculate the molarity:

Molarity (M) = moles of solute / volume of solution

= 0.0171 mol / 0.415 L

≈ 0.0412 M

Therefore, the molarity of the solution is approximately 0.0412 M.

The closest answer option is c. 4.12 x 10^-2 M.

I hope this explanation helps! Let me know if you have any further questions.

A material you are testing conducts electricity but cannot be pulled into wires. It is most likely a _____. metal nonmetal metalloid

Answers

The correct answer for the question that is being presented above is this one: "metal." A material you are testing conducts electricity but cannot be pulled into wires. It is most likely a metal. This metal is a good testing for conductivity of an electricity but cannot be pulled into wires.

Answer:

The correct answer is metal.

Explanation:

Other Questions

What is the change in temperature in a 128g sample of titanium if it absorbs 2808J of heat energy at a temperature of 2°C? The specific heat of titanium is 0.523J/ g °c.

An experiment produced 0.10 g CO2, with a volume of 0.056 L at STP. If the accepted density of CO2 at STP is 1.96 g/L, what is the approximate percent error?

True or False a gas that ignites a glowing splint is oxygen

I need help with number 6