Andrew has a cell phone plan that provides 300 free minutes each month for a flat rate of $19. For any minutes over 300, Andrew is charged $0.39 per minute. Which of the following piecewise functions represents charges based on Andrew's cell phone plan?

Answers

Answer 1
Answer:

Answer:

f(x)=\left\{\begin{array}{l}19,\ \ x\le 300\n \n19+0.39(x-300),\ \ x>300\end{array}\right.

Step-by-step explanation:

Andrew has a cell phone plan that provides 300 free minutes each month for a flat rate of $19. For any minutes over 300, Andrew is charged $0.39 per minute.

Let x be the number of minutes Andrew uses per month and f(x) be the charges based on Andrew's cell phone plan.

If x\le 300, then f(x)=19.

If x>300, then first 300 minutes are free and each minute of next (x-300) minutes costs $0.39, therefore

f(x)=19+0.39(x-300).

Hence,

f(x)=\left\{\begin{array}{l}19,\ \ x\le 300\n \n19+0.39(x-300),\ \ x>300\end{array}\right.

Answer 2
Answer:

Answer:

         19, x≤ 300

         19+.39(x-300),  x>300

Step-by-step explanation:

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A company’s sales of garden tractors increased about 106% from 2007 to 2008. Th e number of tractors sold in 2007 was
347. How many tractors were sold in 2008?

Answers

Answer:

715 garden tractors.    

Step-by-step explanation:

We have been given that a company’s sales of garden tractors increased about 106%  from 2007 to 2008. The number of tractors sold in 2007 was  347.

So the number of tractors sold during 2008 will be 347 plus 106% of 347.

\text{Number of tractors sold during 2008}=\text{Number of tractors sold in year 2007+ Increase in number of tractors in 2008}

\text{Number of tractors sold during 2008}=347+((106)/(100)* 347)

\text{Number of tractors sold during 2008}=347+(1.06* 347)

\text{Number of tractors sold during 2008}=347+367.82

\text{Number of tractors sold during 2008}=714.82\approx 715

Therefore, 715 garden tractors were sold in 2008.

Write these expressions in exponential form. Example: 12 to the power of 2 x 12 to the power of 6= 12 to the power of 2 +61. 11 to the power of 16 x 11 to the power of 1=

2. a to the power of 6 x a to the power of 8 =

3. (-2) to the power of 12 x (-2) to the power of 1=

4. 1.1 to the power of 7 x 1.1 to the power of 9 =

5. 3 to the power of 4 x 5 to the power of 2 =

Answers

Step-by-step explanation:

1. 11 to the power of 16 x 11 to the power of 1

  • 11^(16)*11^1=11^(16+1)=11^{17

2. a to the power of 6 x a to the power of 8

  • a^6*a^8=a^(6+8)=a^(14)

3. (-2) to the power of 12 x (-2) to the power of 1

  • (-2)^(12)*(-2)^1=(-2)^(12+1)=(-2)^(13)

4. 1.1 to the power of 7 x 1.1 to the power of 9

  • 1.1^7*1.1^9=1.1^(7+9)=1.1^(16)

5. 3 to the power of 4 x 5 to the power of 2

Assumed it is both 3 or 5, we take 3

  • 3^4*3^2=3^(4+2)=3^6

The diameter of the Starbucks venti(large) lid is 3.3 inches. The tall(small) gas a diameter of 2.6 inches. What is the difference in the circumference of the two cups?

Answers

Answer:

  0.7π ≈ 2.2 inches

Step-by-step explanation:

The circumference is computed from ...

  C =  πd

Then the difference in circumferences for two different diameters is ...

  C_2-C_1=\pi d_2-\pi d_1 = \pi(d_2-d_1)\n\n=\pi(3.3-2.6)=0.7\pi \quad\text{inches}

  0.7π ≈ 2.2

The difference in circumference of the two lids is about 2.2 inches.

Carlos Martin received a statement from his bank showing a balance of $56.75 as of March 15th. His checkbook shows a balance of $87.37 as of March 20. The bank returned all the cancelled checks but two. One check was for $5.00 and the other was for $13.25. How much did Carlos deposit in his account between the March 15 and the March 20? A. $125.87
B. $11.22
C. $162.37
D. $48.87

Answers

The answer is D. $48.87. — $56.75 - $5.00 - $13.25 = $38.50$87.37 - $38.50 = $48.87Carlos deposited $48.87.

Answer:The answer is D. $48.87. — $56.75 - $5.00 - $13.25 = $38.50 $87.37 - $38.50 = $48.87 Carlos deposited $48.87.

Step-by-step explanation:

How do you convert 0.125 into a ratio

Answers

Start by writing the ratio of:

0.125/1 (since a number divided by 1 is itself)

Then multiply the numerator and denominator by 10, 100, or 1000, etc. until the numerator becomes an integer: (in this case multiplying by 1000 does the trick)

(0.125*1000)/(1*1000)
125/1000

Now simplify by dividing by common factors. For this problem, 5 is a common factor of both the numerator and denominator:

(125/5)/(1000/5)
25/200

Do this again with another common factor if possible. For this problem, 25 is another common factor:

(25/25)/(200/25)
1/8

Now there are no more common factors between the numerator and denominator. When this is the case, the fraction can be considered to have been simplified:

Answer is: 1/8

Answer:

Start by writing the ratio of:

0.125/1 (since a number divided by 1 is itself)

Then multiply the numerator and denominator by 10, 100, or 1000, etc. until the numerator becomes an integer: (in this case multiplying by 1000 does the trick)

(0.125*1000)/(1*1000)

125/1000

Now simplify by dividing by common factors. For this problem, 5 is a common factor of both the numerator and denominator:

(125/5)/(1000/5)

25/200

Do this again with another common factor if possible. For this problem, 25 is another common factor:

(25/25)/(200/25)

1/8

Now there are no more common factors between the numerator and denominator. When this is the case, the fraction can be considered to have been simplified:

Answer is: 1/8

Step-by-step explanation:

Circle the division problem that does not belong with the other three. Explain.Write one that does belong 621/6 384/3 719/7 514/5

Answers

Answer:

384/3

Step-by-step explanation:

^^Is the only one that equals a whole number the rest have decimals