The chemical formula for potassium bromide is KBr.A chemist determined by measurements that 0.0250 moles of potassium bromide participate in a chemical reaction. Calculate the mass of potassium bromide that participates.

Round your answer to 3 significant digits.

Answers

Answer 1
Answer:

A chemist determined by measurements that 0.0250 moles of potassium bromide participate in a chemical reaction is 0.002 moles

What are moles?

The moles are the smallest unit of an atom ion molecule or substance which is used to count the number which is taking part in a chemical reaction and is equal to 2.303 ×10²³ moles of that.

To calculate the participant in a chemical reaction number of moles is 0.0250 moles so the mass will be,

                number of moles = mass/ molar mass

substituting the value,

               0.0250 moles = mass / 119.002

               mass = 119.002  ×  0.0250 moles

                mass = 0.002 moles

Therefore, 0.002 moles determined by measurements that 0.0250 moles of potassium bromide participate in a chemical reaction.

Learn more about moles, here:

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Answer 2
Answer:

My solution

39.0983+126.90447=166.00277

x/166.002277=.06

x=9.96g

Explanation:


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What effect does salt have on most metals?

Answers

the combination of moisture, oxygen and salt ,especially sodium chloride, damages metal worse than rust does. This combination corrodes, or eats away at, the metal, weakening it and causing it to fall apart.

Benzene is a starting material in the synthesis of nylon fibers and polystyrene (styrofoam). Its specific heat capacity is 1.74 J/g·°C. If 16.7 kJ of energy is absorbed by a 225-g sample of benzene at 20.0°C, what is its final temperature?

Answers

Answer: The final temperature of the sample is 62.66°C

Explanation:

To calculate the amount of heat absorbed, we use the equation:

Q=mc\Delta T

where,

Q = heat absorbed = 16.7 kJ = 16700 J   (Conversion factor:  1 kJ = 1000 J)

m = Mass of the sample = 225 g

c = specific heat capacity of sample = 1.74J/g.^oC

\Delta T = change in temperature = T_2-T_1=(T_2-20.0)

Putting values in above equation, we get:

16700=225g* 1.74J/g.^oC* (T_2-20)^oC\n\nT_2=62.66^oC

Hence, the final temperature of the sample is 62.66°C

True or False: Observations are just things that you see

Answers

Answer:

False

Explanation:

"Observations is the action of observing something or someone carefully or in order to gain information" - google dictionary. This definition does not completely match the definition given, so the answer is false.

I hope this helps!

Answer: true

Explanation: the action or process of observing something or someone carefully or in order to gain information that is the real definition

At 25.0 ⁰C the henry's law constant for hydrogen sulfide(H2S) gas in water is 0.087 M/atm. Caculate the mass in grams of H2S gas that can be dissolved in 400.0 ml of water at 25.00 C and a H2S partial pressure of 2.42atm.

Answers

Answer: The mass of hydrogen sulfide that can be dissolved is 2.86 grams.

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the gas.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_(H_2S)=K_H* p_(liquid)

where,

K_H = Henry's constant = 0.087M/atm

p_(H_2S) = partial pressure of hydrogen sulfide gas = 2.42 atm

Putting values in above equation, we get:

C_(H_2S)=0.087M/atm* 2.42atm\n\nC_(H_2S)=0.2105M

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}* 1000}{\text{Molar mass of solute}* \text{Volume of solution (in mL)}}

We are given:

Molarity of solution = 0.2105 M

Molar mass of hydrogen sulfide = 34 g/mol

Volume of solution = 400.0 mL

Putting values in above equation, we get:

0.2105M=\frac{\text{Mass of hydrogen sulfide}* 1000}{34g/mol* 400.0mL}\n\n\text{Mass of }H_2S=(0.2105* 34* 400)/(1000)=2.86g

Hence, the mass of hydrogen sulfide that can be dissolved is 2.86 grams.

What is the speed of a rocket in units of meter/ second if its travels at a speed of 1000 km/minutes?

Answers

Answer:

1,080 m

Explanation:

In the important industrial process for producing ammonia (the Haber Process), the overall reaction is: N2(g) + 3H2(g) → 2NH3(g) + 24,000 calories A yield of ammonia, NH3, of approximately 98% can be obtained at 200°C and 1,000 atmospheres of pressure. How many grams of N2 must react to form 1.7 grams of ammonia?

Answers

Answer:

Mass of N2 required = 1.429 g

Explanation:

The given reaction is:

N2(g) + 3H2(g) → 2NH3(g)

Mass of NH3 formed = 1.7 g

Molar mass of NH3 = 17 g/mol

Moles(NH3) = (Mass)/(Molar mass) = (1.7)/(17) = 0. 1

Based on the reaction stoichiometry:

1 mole of N2 forms 2 moles of NH3

Therefore, moles of N2 required to produce 0.1 moles of NH3 is:

= (1 mole(N2)*0.1moles(NH3))/(2 moles(NH3)) =0.05 moles(N2)

Molar mass of N2 = 28 g/mol

Mass of N2 required = moles*molar mass = 0.05*28 = 1.4 g

This is the theoretical mass corresponding to a 100% yield. Since the yield of NH3 is 98%, the corresponding mass of N2 required would be:

=(1.4)/(0.98) =1.429 g

28g N2/(17 x 2 x 0.98) g NH3


1.7 g NH3 x 28g N2/(17 x 2 x 0.98) g NH3 =

47.6 / 33.32 = 1.43 g N2