A differential equation is given along with the field or problem area in which it arises. Classify it as an ordinary differential equation​ (ODE) or a partial differential equation​ (PDE), give the​ order, and indicate the independent and dependent variables. If the equation is an ordinary differential​ equation, indicate whether the equation is linear or nonlinear.

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Answer 1
Answer:

The question is incomplete. Here is the complete question.

A differential equation is given along with the field of problem area which it arises. Classify it as an ordinary differential equation (ODE) or a partial different equation (PDE), give the order, and indicate the independent and dependent variables. If the equation is an ordinary differential equation, indicate whether the equation is linear or nonlinear.

x(d^(2)y )/(dx^(2) ) + (dy)/(dx) + xy = 0 (aerodynamics, stress analysis)

Answer and Step-by-step explanation: The differential equation described above is anOrdinaryDifferentialEquation, because it has a definite set of variables: x and y.

It is of SecondOrder, since the highest derivative is of order 2: (d^(2)y )/(dx^(2) )

The differential equation is written as derivative of a function y in terms of x, which means: IndependentVariable is X and DependentVariable is Y.

As it is an ODE, the equation is Nonlinear, because y'' or (d^(2)y )/(dx^(2) ) is multiplied by a variable.

Answer 2
Answer:

Final answer:

This question pertains to classifying and understanding differential equations in mathematics, specifically identifying whether it is an ordinary differential equation, determining its order, and identifying independent and dependent variables.

Explanation:

In mathematics, a differential equation is a mathematical equation that relates a function with its derivatives. An Ordinary Differential Equation (ODE) is a differential equation containing one or more functions of one independent variable and the derivatives of those functions. The term order of a differential equation is defined as the highest power of the derivative in the equation.

As an example, if we have an equation like dy/dx = x*y, it would be an ODE since it involves only one independent variable, 'x', and the dependent variable is 'y'. The order is one since the highest order derivative is dy/dx, and the equation is nonlinear because it does not meet the criteria for a linear ODE, which stipulates that the dependent variable and its derivatives are to the first power and are not multiplied together.

Learn more about Differential Equations here:

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A new company is in the process of evaluating its customer service. The company offers two types of sales: (1) Internet sales and (2) store sales. The marketing research manager believes that the Internet sales are more than 10 percent higher than store sales. The alternative hypothesis for this problem would be stated as:

What of the following functions is graphed belowbeing timed help quickly will mark brainliest !!!​

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The correct answer is C

Tell whether the following set is an empty set or not. A = {A quadrilateral having 3 obtuse angles}

Answers

Answer:

It is not an empty set

Step-by-step explanation:

Obtuse angles are angles greater than 90 and less than 180.

There are quadrilaterals having 3 obtuse angles and they are possible.

If we imagine 3 obtuse angles of 91 degrees (obtuse angle), the 4th angle will be

360-91-91-91

=> 87 degrees

So, This quadrilateral can be constructed!

And also with 92, 93, 94 and so on!

So, Set A is not an empty set!

Answer:

It is not an empty set

Step-by-step explanation:

A quadrilateral with 3 obtuse angles is possible.

A obtuse angle has a measure of more than 90 degrees and less than 180 degrees.

Let’s say three angles are measuring 91 degrees in a quadrilateral.

91 + 91 + 91 + x = 360

x = 87

The measure of the fourth angle is 87 degrees which is less than 360 degrees and is a positive integer, so it is possible.

The nicotine content in cigarettes of a certain brand is normally distributed with mean (in milligrams) μ and standard deviation σ=0.1. The brand advertises that the mean nicotine content of their cigarettes is 1.5, but you believe that the mean nicotine content is actually higher than advertised. To explore this, you test the hypotheses H0:μ=1.5, Ha:μ>1.5 and you obtain a P-value of 0.052. Which of the following is true? A. At the α=0.05 significance level, you have proven that H0 is true. B. This should be viewed as a pilot study and the data suggests that further investigation of the hypotheses will not be fruitful at the α=0.05 significance level. C. There is some evidence against H0, and a study using a larger sample size may be worthwhile. D. You have failed to obtain any evidence for Ha.

Answers

Answer:

Step-by-step explanation:

This is a test of a single population mean since we are dealing with mean.

From the information given,

Null hypothesis is expressed as

H0:μ=1.5

The alternative hypothesis is expressed as

Ha:μ>1.5

This is a right tailed test

The decision rule is to reject the null hypothesis if the significance level is greater than the p value and accept the null hypothesis if the significance level is less than the p value.

p value = 0.052

Significance level, α = 0.05

Since α = 0.05 < p = 0.052, the true statement would be

At the α=0.05 significance level, you have proven that H0 is true. B.

The weights of a certain brand of candies are normally distributed with a mean weight of 0.8547 g and a standard deviation of 0.0511 g. A sample of these candies came from a package containing 463 ​candies, and the package label stated that the net weight is 395.2 g.​ (If every package has 463 ​candies, the mean weight of the candies must exceed StartFraction 395.2 Over 463 EndFraction 395.2 463equals=0.8535 g for the net contents to weigh at least 395.2 ​g.) a. If 1 candy is randomly​ selected, find the probability that it weighs more than 0.8535 g. The probability is .​(Round to four decimal places as​ needed.)

Answers

Answer:

There is a 69.15% probability that it weighs more than 0.8535 g.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = (X - \mu)/(\sigma)

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that

The weights of a certain brand of candies are normally distributed with a mean weight of 0.8547 g, so \mu = 0.8547.

We have a sample of 463 candies, so we have to find the standard deviation of this sample to use in the place of \sigma in the Z score formula. We can do this by the following formula:

s = (\sigma)/(√(463)) = 0.0024

Find the probability that it weighs more than 0.8535

This is 1 subtracted by the pvalue of Z when X = 0.8535

So

Z = (X - \mu)/(s)

Z = (0.8535 - 0.8547)/(0.0024)

Z = -0.5

Z = -0.5 has a pvalue of 0.3085.

This means that there is a 1-0.3085 = 0.6915 = 69.15% probability that it weighs more than 0.8535 g.

WHAT IS THE SLOPE OF THE LINE6X + 3Y = 18?
Can anyone actually help me work it out please

Answers

Answer:

6x + 3y = 18 \n \n y = - 2x + 6 \n \n x = 3

3y=6x=18 the equation must look like this y=mx+b where m is the slope in this case it is 2 and b is the y-intercept 18 hope it helps

just divide every term by 3 to isolate y

GraceRosalia

Emily and Miranda are standing outside. Emily is 5 feet tall and casts a shadow of 28 inches. Miranda's shadow is 29.4 inches long. Approximately how tall is Miranda?

Answers

Answer:

5.25ft

Step-by-step explanation:

i got the question right so thats it

Answer:

5 1/4

Step-by-step explanation:

5 1/4 to decimal form is 5.25