4. Find the value of k, if x = 2, y=1 is a solution of the equation 2x + 3y=k.​

Answers

Answer 1
Answer:

Answer:

k=7

Step-by-step explanation:

first, plug in the given values

2x+3y=k --> 2(2)+3(1)=k

-->4+3=k

-->7=k

k=7


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Answers

We are asked to determine the set of real numbers that contain the factors of 12. 12 is considered as a composite number in which the factors are not only 1 and 12. Factors are considered as numbers in which 12 is divisible by them. In this case, the answer is B. {1, 2, 3, 4, 6, 12}. 

Which answer is equal to ( sqrt 7)^3?
A.7 3/2
B.7 2/3
C.7 1/6
D.7 1/3

Answers

(√(7))^(3)
√(7)√(7)√(7)
√(7 * 7 * 7)
√(49 * 7)
√(343)
√(49 * 7)
√(49)√(7)
7√(7)
(7)^{(3)/(2)}

The answer is A.
Try D As your Answer.

If the base of a rectangle is 12cm and the area is 250.8cm2 what is the height of the rectangle

Answers

250.8cm^2/12cm= 20.9cm.
the height of the rectangle is 20.9 cm
250.8cm^2/12cm = 20.9cm
the height of the rectangle is 20.9cm

What is 25 over 169 square as a fraction

Answers

Step-by-step explanation:To express 25/169 as a fraction squared, you simply square both the numerator and the denominator

(25/169)^2 = (25^2) / (169^2) = 625 / 28,561

So, 25/169 squared as a fraction is 625/28,561.

Square root of-100x^4y^13

Answers

Answer:

10x^2y^6√y

Step-by-step explanation:

1. First, let's factor out any perfect squares from the expression under the square root. In this case, we can factor out 100, which is a perfect square:

√(100 * x^4 * y^13)

2. Taking the square root of 100 gives us 10:

10 * √(x^4 * y^13)

3. Now, let's simplify the expression under the square root. Remember that the square root of a product is equal to the product of the square roots:

10 * √(x^4) * √(y^13)

4. The square root of x^4 is x^2:

10 * x^2 * √(y^13)

5. Finally, let's simplify the square root of y^13. Since 13 is an odd number, we can write it as the product of a perfect square and an additional factor:

10 * x^2 * √(y^12 * y)

6. The square root of y^12 is y^6:

10 * x^2 * y^6 * √y

Therefore, the simplified expression for the square root of -100x^4y^13 is:

10x^2y^6√y

(2^2b^-2)^-3
Math help plz

Answers

Answer:

(b^6)/(64)

Step-by-step explanation:

We need three rules. Raising a power to a power. Raising a product to a power. Raising a number to a negative exponent.

Rule 1:

To raise a power to a power, multiply powers.

(a^m)^n = a^(mn)

Rule 2:

To raise a product to a power, raise every factor of the product to the power.

(a^xb^yc^z)^n = a^(xn)b^(yn)c^(zn)

Rule 3:

To raise a number to a negative power, follow this formula.

a^(-n) = (1)/(a^n)

Your problem.

(2^2b^(-2))^(-3) =

You have a product raised to a power, so raise each factor to the power.

= (2^2)^(-3)(b^(-2))^(-3)

Now raise each power to a power by multiplying exponents.

= 2^(2 * (-3))b^(-2 * (-3))

= 2^(-6)b^(6)

Now we follow the rule of a negative exponent.

= (1)/(2^6) * b^6

= (b^6)/(2^6)

= (b^6)/(2 * 2 * 2 * 2 * 2 * 2)

= (b^6)/(64)

Answer: (b^6)/(64)