Solve algebraically
x-4y=-10
x+y=5

Answers

Answer 1
Answer:

Answer:

if x+y=5, then x=5-y

so x-4y=-10

5-y-4y=-10

5-5y=-10

-5y=-15

y=3

x=5-y

x=5-3

x=2

x=2; y=3


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What two numbers have a sum of 9 and a product of -10

Answers

Answer:

-2

Step-by-step explanation:

20 is 12.5$ of what number?

Answers

Asumming you mean "20 is 12.5% of what number?", the answer is 160.

What additional information would you need to prove that ΔABC ≅ ΔDEF by SSS? 1.AC=DF
2.AC=FD
3.AF=CD
4.FA=CD

Answers

For the answer to the question above asking What additional information would you need to prove that ΔABC ≅ ΔDEF by SSS? 
The answer to your question is 
AB = DE & BC = EF, so the only sides missing are AC = DF, 

so Side AC is congruent to side DF is the answer.

I hope my answer helped you. Have a nice day!

Answer: AC=DF

Step-by-step explanation:

Took the test!

If you are really clever, you can convert between units used. If you want toknow how fast the ball is travelling in the above question in km/hr we must
first convert metres to km and seconds into hours.
Metres to kilometres = 22,metres ÷ 1000 (1000 metres in a kilometre)
.022 km
Seconds to hours = 0.6s+ 3600 (60 seconds in a minute x 60 minutes in an hour)
60min
⇒ Calculate the speed of the ball in km/hr (remember km + hours)
⇒ An aeroplane travels from Brisbane to Melbourne in 2 hours. The
distance travelled is 1700km. What was its speed in km/hr and m/s?
⇒ A student walks 8km in 2 hours. What was its speed in km/hr and
m/s?

Answers

Let's calculate the speed in km/hr and m/s for both scenarios:

**Scenario 1: Ball Travel**

You've already provided the conversions for meters to kilometers and seconds to hours, which are correct.

Distance (in km) = 22 meters / 1000 = 0.022 km
Time (in hours) = 0.6 seconds / 3600 = 0.000167 hours

Now, calculate the speed:
Speed (in km/hr) = Distance / Time = 0.022 km / 0.000167 hours ≈ 131.74 km/hr

**Scenario 2: Aeroplane Travel**

Distance (in km) = 1700 km
Time (in hours) = 2 hours

Now, calculate the speed:
Speed (in km/hr) = Distance / Time = 1700 km / 2 hours = 850 km/hr

To convert this speed to m/s, remember that 1 km/hr is approximately 0.27778 m/s:
Speed (in m/s) ≈ 850 km/hr × 0.27778 m/s/km/hr ≈ 236.11 m/s

**Scenario 3: Student Walking**

Distance (in km) = 8 km
Time (in hours) = 2 hours

Now, calculate the speed:
Speed (in km/hr) = Distance / Time = 8 km / 2 hours = 4 km/hr

To convert this speed to m/s:
Speed (in m/s) ≈ 4 km/hr × 0.27778 m/s/km/hr ≈ 1.1111 m/s

So, in summary:

**Scenario 1: Ball Travel**
- Speed in km/hr: Approximately 131.74 km/hr

**Scenario 2: Aeroplane Travel**
- Speed in km/hr: 850 km/hr
- Speed in m/s: Approximately 236.11 m/s

**Scenario 3: Student Walking**
- Speed in km/hr: 4 km/hr
- Speed in m/s: Approximately 1.1111 m/s

What is the range of f(x)=lxl-6?

Answers

if the domian is 1 then range is -5

For what values of the variables must ABCD be a parallelogram?

Answers

okfirst things first. In all parallelograms, you now that opposite anglesare numerically equal to each other and that the sum off all fourangles must add up to 360.

Therefore based off the picture, angles B and D are equal to each other, and A and C are equal to each other.

(2x-10) = (y+20) B = D
y=2x-30

Now B = 2x -10 and D = 2x-30+20 = 2x-10

Now A = C

Since A = 2x+ 10, we can assume C = 2x + 10

Now we need to find the value of x

so our angle A, B, C, and D add up to 360 so the "master equation" is:

(2x - 10) + (2x - 30 + 20) + (2x + 10) + (2x + 10) = 360
2(2x -10) + 2(2x + 10) = 360
4x - 20 + 4x + 20 = 360
8x = 360
x = 45

Now that we know what x is, we can go back to the angles B and D

remember B = 2x - 10 and D = y + 20

and earlier we stated that y=2x-30
therefore y = 2(45) - 30
Y = 60

Now if you wanted to double check, all you have to do is plug in the xand y values into the equations and add up all the angles together andthey should add up to 360.

I know I kinda went into too many details, but I'd rather explain itinto too much detail rather than too few details and shortcuts that youwouldn't be able to follow and understand.

I hope this was helpful =D

Final answer:

ABCD is a parallelogram if either both pairs of opposite sides are parallel, both pairs of opposite sides are equal, or one pair of opposite sides is both parallel and equal.

Explanation:

In mathematics, a quadrilateral ABCD is considered a parallelogram if it meets one of these three conditions:

  • Both pairs of opposite sides are parallel (AB || DC and AD || BC).
  • Both pairs of opposite sides are equal (AB = DC and AD = BC).
  • One pair of opposite sides is both parallel and equal (AB = DC and AB || DC).

So, the values of the variables you have in your problem have to satisfy at least one of these conditions to make ABCD a parallelogram.

Learn more about Parallelogram here:

brainly.com/question/31342904

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