Answer:The property which is not characteristic of enzymes is to be predicted. Concept Introduction: Enzymes are proteins. ... The important factors affecting enzyme activity are enzyme concentration, substrate concentration, temperature and pH.
Explanation: above is the explanation
Answer:
The correct statement is that a slow mutation rate makes it useful for determining evolutionary relationships between ancient species.
Explanation:
The rRNA or ribosomal RNA has an application as a molecular clock because of many factors. It exhibits a very slow mutation rate, that is, around one million years because of which it stays highly conserved in all the organisms. In the ribosomal RNAs of two organisms, the degree of mutations can be associated directly with the time they were originated in the past.
In supplementation, it possesses essential biological function because of which it can be witnessed in almost all the species.
Answer:
A slow mutation rate
The red blood cells are cohesive, meaning they want to stick together. if one cell moves along the capillary this cohesion will drag the neighboring cell with it. the cells are also adhesive to the capillary walls, so they stick along the tube lining as they are dragged through the capillary.
Only 10% of the energy consumed by an organism is available to be transferred to another trophic level due to the laws of thermodynamics and the inefficiency of energy transfer.
Only 10% of the energy consumed by an organism is available to be transferred to another trophic level due to the laws of thermodynamics and the inefficiency of energy transfer. This is known as the 10% rule.
The 10% rule states that energy is lost as heat during the process of respiration and metabolic activities, and only a fraction of the remaining energy is converted into biomass that is available as food for the next trophic level.
For example, if a primary producer (such as a plant) has 1,000 units of energy, only 100 units are passed on to the primary consumer (herbivore), and only 10 units are transferred to the secondary consumer (carnivore) in the next trophic level.
Transportation improvements
Commercial development
Industrial development
Final answer:
When crossing a heterozygous round, tall F1 pea plant with a homozygous wrinkled, short pea plant, the probability of the offspring being wrinkled and tall is 1/4.
Explanation:
In pea plants, we have two traits where round seed shape (R) is dominant to wrinkled seed shape (r), and tall height (T) is dominant to short height (t). When a homozygous round, tall plant (RRTT) is crossed with a homozygous wrinkled, short plant (rrtt), the resulting F1 generation will all have the genotype RrTt (heterozygous for both traits). If these F1 plants are then crossed back to the wrinkled, short strain (rrtt), we need to look at each trait separately to determine the phenotype ratios.
For the seed shape, the F1 plants (Rr) crossed with the wrinkled, short (rr) can produce offspring with either Rr or rr genotype. Therefore, the probability of having a wrinkled (rr) offspring is 1/2. For height, the F1 plants (Tt) crossed with the wrinkled, short (tt) can also produce offspring with either Tt or tt genotype. The probability of having a tall (Tt) offspring is 1/2 as well. To find the proportion of offspring that are wrinkled and tall, we multiply the probabilities of the independent events: 1/2 (chance of being wrinkled) × 1/2 (chance of being tall) which equals 1/4.
Therefore, the proportion of offspring that will be wrinkled and tall from this cross is 1/4.