There are a total of 20 lions, tigers and bears. If the number of tigers is 2 more than the number of lions and the number of bears is 1 more than the number of tigers, find the number of each.

Answers

Answer 1

Answer: Number of tiguers: x + 2
Number of Lions: x
Number of bears:(x+2)+1=(x+3)

We can suggest this equation:
(x+2) + (x)+(x+3)=20

3x+5=20
3x=20-5
3x=15
x=15/3
x=5.

Therefore:
Number of tiguers: x + 2=5+2=7
Number of Lions: x=5
Number of bears:(x+2)+1=(x+3)=5+3=8.

Answer: there are 7 tiguers, 5 lions and 8 bears.

Answer 2

Answer:

Final answer:

In the problem, if we denote the number of lions as x, the number of tigers as x+2, and the number of bears as x+3, and considering that the total of all these animals is exactly 20, we can form and solve a simple algebraic equation. We will find that there are 5 lions, 7 tigers, and 8 bears.

Explanation:

This is a problem of simple algebra. According to the problem, let's represent the number of lions as x, the total number of tigers as x + 2 (since it's two more than the lions), and the number of bears as x + 3 (1 more than the number of tigers).

The problem states the total number of all these animals as 20, so we can set up the following equation: x + x + 2 + x + 3 = 20.

Solving this algebra equation gives you:

3x + 5 = 20

Subtracting 5 from both sides gives us:

3x = 15

Dividing both sides by 3 gives us:

x = 5

So, the number of lions is 5, the number of tigers is 7 (5 + 2), and the number of bears is 8 (7 + 1).

Learn more about Algebra here:

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3×1+1×1/10+9×1/100+5×1/1000=(write the answer as a decimal)

PLS ANSWER QUICKLY

Answers

Answer:

3.195

Step-by-step explanation:

Answer:

To solve this equation, you need to multiply each term separately and then add them up.

3 × 1 = 3 1 × 1/10 = 1/10 9 × 1/100 = 9/100 5 × 1/1000 = 5/1000

Now we can add them all together:

3 + 1/10 + 9/100 + 5/1000 = 3 + 0.1 + 0.09 + 0.005

Simplifying the decimals, we get:

3 + 0.1 + 0.09 + 0.005 = 3.1 + 0.09 + 0.005

Adding the decimals gives:

3.1 + 0.09 + 0.005 = 3.195

Therefore, the solution to the equation is 3.195.

The sum of two numbers is 62 and their difference is 16.Which system of equations represents the word problem?

x + y = 62 and x - y = 16
x + y = 62 and 62-x = 16
x + 62 = y and x - 16 = y

Answers

x + y = 62 and x - y = 16 is your answer. hope this helps

x+y=62, x -y=16 Hope this helps you see ya

Which of the following statements is true?

Answers

Answer:

option C is correct.

Step-by-step explanation:

Checking equation A

$(9x^3 + 12x) + (16x^3 -4x+1)= 24x^3 +16x-1\n9x^3+16x^3+12x-4x+1=24x^3+16x-1\n25x^3+8x+1\neq 24x^3+16x-1$

Checking equation B

$(3x+2x^2-4)-(x^2+x-5)=2x+x^2-9\n3x-x+2x^2-x^2-4+5=2x+x^2-9\n2x+x^2+1\neq 2x+x^2-9$

Checking equation C

$(10x^3+2x^2-11)+(9x^2+2x-2)=10x^3+11x^2+2x-13\n10x^3+2x^2+9x^2+2x-11-2=10x^3+11x^2+2x-13\n10x^3+11x^2+2x-13=10x^3+11x^2+2x-13$

Checking equation D

$(-7x^2+12)-(5-4x^2)=11x^2-17\n-7x^2+4x^2+12-5=11x^2-17\n-3x^2+7\neq 11x^2-17$

Hence, only option C is correct.

Variable y varies directly with variable x, and y = 6 when x = 9. What is the value of x when y = 18?

Answers

Well, 18 is 6 x 3

Since y was multiplied by 3, we can multiply x by 3 to get its value

9 x 3 = 27

(9)(6)=(x)(18)
54=18x
3=x
hope this helps!

Whats the complete factored form of the polynomial 5b-15c???

Answers

All you need to do is pull out a 5 :)

5(b-3c)

To factore 5b - 15 c you have to find a least common multiple which happens to b 5

Divide all factors by 5

answer : b - 3c

how is using a graph to represent a proportional relationship like using a table?How is it different?

Answers

Answer:

I honestly am in fiith grade and I really don't know

Step-by-step explanation:

SORRY

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