What is the product(s) in this combination reaction?
MgO + CO2

Answers

Answer 1

Answer: This is a synthetic reaction:
Mg O + C O2 → Mg C O3
The product is Magnesium Carbonate.

Answer 2

Answer:

Answer : The product formed in the combination reaction is, magnesium carbonate, $(MgCO_3)$

Explanation :

Combination reaction : It is a chemical reaction in which multiple substances or reactants combine to form a single product.

The balanced chemical reaction will be,

$MgO+CO_2\rightarrow MgCO_3$

This reaction is a combination reaction in which the magnesium oxide react with the carbon dioxide to give magnesium carbonate as a product.

Hence, the product formed in the combination reaction is, magnesium carbonate, $(MgCO_3)$

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Which ion was formed by providing the second ionization energy to remove an electron? Ca2+ N3– Fe3+ S2–

Answers

Answer:

Ca²⁺

Explanation:

Ionization energy is defined as the minimum amount of energy required to knock out the electron from valence shell of an atom in its gaseous state. While, second Ionization energy is defined as the amount of energy required to knock out the second electron from an ion containing +1 charge in gaseous state.

Among given options Ca²⁺ is the correct choice because the calcium has lost two electrons i.e. first electron was removed by providing first ionization energy i.e.

Ca + 1st IE → Ca¹⁺ + 1 e⁻

and second electron is was removed by providing second ionization energy i.e.

Ca ¹⁺ + 2nd IE → Ca²⁺ + 1 e⁻

$\boxed{{\text{C}}{{\text{a}}^{{\text{2 + }}}}}$ is formed by providing the second ionization energy to remove an electron.

Further Explanation:

The energy that is needed to remove the most loosely bound valenceelectrons from the isolated neutral gaseous atom is known as the ionization energy. It is denoted by IE. The value of IE is related to the ease of removing the outermost valence electrons. If these electrons are removed so easily, small ionization energy is required and vice-versa. It is inversely proportional to the size of the atom.

Ionization energy is further represented as first ionization, second ionization and so on. When the first electron is removed from a neutral, isolated gaseous atom, the energy needed for the purpose is known as the first ionization energy, written as ${\text{I}}{{\text{E}}_{\text{1}}}$ . Similarly, when the second electron is removed from the positively charged species (cation), the ionization energy is called the second ionization energy $\left( {{\text{I}}{{\text{E}}_{\text{2}}}} \right)$ and so on.

The neutral atom corresponding to ${\text{C}}{{\text{a}}^(2 + )}$ is calcium. If second ionization energy is supplied to calcium atom, it results in the removal of two electrons and thus ${\text{C}}{{\text{a}}^(2 + )}$ is formed. So ${\text{C}}{{\text{a}}^(2 + )}$ can be formed by providing second ionization energy. to the neutral atom.

The neutral atom corresponding to ${{\text{N}}^(3 - )}$ is nitrogen. If second ionization energy is supplied to nitrogen, it results in the formation of ${{\text{N}}^(2 + )}$ , not ${{\text{N}}^(3 - )}$ . So ${{\text{N}}^(3 - )}$ cannot be formed by providing the second ionization energy to the neutral atom.

The neutral atom corresponding to ${\text{F}}{{\text{e}}^(3 + )}$ is iron. If second ionization energy is supplied to the iron atom, it results in the formation of ${\text{F}}{{\text{e}}^(2 + )}$ , not ${\text{F}}{{\text{e}}^(3 + )}$ . So ${\text{F}}{{\text{e}}^(3 + )}$ cannot be formed by providing the second ionization energy to the neutral atom.

The neutral atom corresponding to ${{\text{S}}^(2 - )}$ is sulfur. If second ionization energy is supplied to the sulfur atom, it results in the formation of ${{\text{S}}^(2 + )}$ , not ${{\text{S}}^(2 - )}$ . So ${{\text{S}}^(2 - )}$ cannot be formed by providing the second ionization energy to the neutral atom.

Therefore, the only ion that can be formed by supplying the second ionization energy is ${\text{C}}{{\text{a}}^(2 + )}$ .

Learn more:

1. Which is the oxidation-reduction reaction:

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Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Periodic classification of elements

Keywords: second ionization energy, Ca2+, N3-, Fe3+, S2-, IE1, IE2, first electron, second electron, neutral atom., nitrogen, calcium, iron, sulfur.

An electron has a charge ofA. –1 and the same mass as a proton
B. +1 and the same mass as a proton
C. –1 and a smaller mass than a proton
D. +1 and a smaller mass than a proton

Answers

The correct answer is C. An electron has a charge of -1 and a smaller mass than a proton. Proton has the same mass with the neutron. The ratio between the mass of a proton and an electron is about 2000. An electron has an equal value but negative charge with the proton.

NEED HELP! ASAP 30 POINTS!!
Fill the blanks

Answers

Answer:

Explanation:

In ions, protons are never taken or given. Only the number of electrons are changed

Br^1- gains 1 electron, so the number of electrons increases from 35 to 36. No protons are taken away, to the number of protons and the atomic number of Br1- is still 35, and the number of neutrons is still 45.

Which compound is insoluble in water?
(1) KOH (3) Na3PO4
(2) NH4Cl (4) PbSO4

Answers

Ans: 4) PbSO4

Different compounds are soluble in water to a different extent, some of them are completely insoluble in water. Solubility rules help in identifying the water soluble and insoluble compounds.

Based on the rules:

1) Salts of group IA (Li, Na, K, Rb and Cs) are soluble in water

2) Salts containing NH4+ ions are water soluble

3) All phosphates (PO4³⁻) are insoluble except those containing group IA elements and (NH4)₃PO4

4) All sulfates, SO4²⁻ salts are generally soluble with the exception of Ca2+, Sr2+, Ba2+, Hg₂²⁺, Hg2+, Pb2+ and Ag+

Therefore, among the given examples:

1) KOH contains group 1A (K) therefore soluble

2) Na3PO4 contains group IA element (Na), therefore soluble

3) NH4Cl contains NH4+ ion, therefore soluble

4) Sulfate of lead (Pb) is insoluble

The compound that is insoluble in water is:

(4) PbSO4 (Lead(II) sulfate)

What is Lead(II) sulfate

Lead(II) sulfate (PbSO4) is generally considered insoluble in water. It forms a precipitate when mixed with water, indicating low solubility. In contrast, the other compounds listed are soluble in water:

(1) KOH (Potassium hydroxide) is soluble in water and dissociates into potassium ions (K+) and hydroxide ions (OH-).

(2) NH4Cl (Ammonium chloride) is soluble in water and dissociates into ammonium ions (NH4+) and chloride ions (Cl-).

(3) Na3PO4 (Sodium phosphate) is soluble in water and dissociates into sodium ions (Na+) and phosphate ions (PO43-).

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A substance that undergoes radioactive decay is _____ than what it turns into

Answers

...."heavier". *The definition of radioactive decay shall do its explanation.

Mark and Ann took a two week hiking trip through Yosemite National Park. While hiking through the park they witnessed two large blocks of rock break away from Glacier Point. What is the initial transfer of energy that accelerates the rock down the side of the mountain?