Find the lateral area of a regular pentagonal pyramid that has a slant height of 14 in. and a base side length of 6 in. A) 210 in^2 B) 240 in^2 C) 42 in^2 D) 420 in^2

Answers

Answer 1
Answer: The question ask to choose among the following choices that contains the value of the lateral area of a regular pentagonal pyramid that has a slant height of 14 in and a base side length of 6 in. Base on my calculation, the answer would be A. 210 inch^2. I hope this would help 
Answer 2
Answer:

The lateral area of a regular pentagonal pyramid has a slant height of 14 in is 210 inch^2.

We have given that ,

The lateral area of a regular pentagonal pyramid that has a slant height of 14 in. and a base side length of 6 in.

What is the pentagonal pyramid?

A pentagonal pyramid is a pyramid with a pentagonal base upon which are erected five triangular faces that meet at a point. Like any pyramid, it is self-dual. The regular pentagonal pyramid has a base that is a regular pentagon and lateral faces that are equilateral triangles.

The question ask to choose among the following choices that contain the value of the lateral area of a regular pentagonal pyramid that has a slant height of 14 in and a base side length of 6 in.

Base on my calculation, the answer would be A.

210 inch^2.

To learn more about the pyramid visit:

brainly.com/question/218706

#SPJ5


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What would you have to do to change 10 cubic feet into cubic inches? A. Multiply by 46,656 B. Divide by 1,728 C. Multiply by 1,728 D. Divide by 46,656

Answers

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If l || m, find the value of x.

Answers

Answer:

15

Step-by-step explanation:

(5x + 9)° = 84° (alternate angles)

5x + 9 = 84

5x = 84 - 9

5x = 75

x = 75/5

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A model is made of a car. The car is 8 feet long and the model is 10 inches long. What is the ratio of the length of the car to the length of the model?

Answers

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URGENT PLZ HELP: Graph y = tanx for -pi/4 ≤ x ≤ x/4.
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Answers

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Find b, given that a = 20, angle A = 30°, and angle B = 45° in triangle ABC

Answers

Answer:

b = 20√2

Step-by-step explanation:

Given: ΔABC

           a = 20 , m∠A =  30° and m∠B = 45°

To find: value of b.

We use Sine result, which state that

(a)/(sin\,A)=(b)/(sin\,B)

Substituting given values we, get

(20)/(sin\,30^(\circ))=(b)/(sin\,45^(\circ))

we know thatsin\,30^(\circ)=(1)/(2)\:and\:sin\,45^(\circ)=(1)/(√(2)), we get

(20)/((1)/(2))=(b)/((1)/(√(2)))

20{*2}=b*√(2)

b*√(2)=40

b=(40)/(√(2))

b=20√(2)

Therefore, b = 20√2

The side b is opposite to the angle B, applying the law of the sines, we have:

(a)/(sinA) = (b)/(sinB)
(20)/(sin30^0) = (b)/(sin45^0)
(20)/( (1)/(2) ) = (b)/( ( √(2) )/(2) )
20* ( √(2) )/(2) = b* (1)/(2)
(20 √(2) )/(2) = (b)/(2)
2*b =2*20 √(2)
2b = 40 √(2)
b = (40 √(2) )/(2)
\boxed{b = 20 √(2) }