Lionel computed the average rate of change in the depth of a pool over a two-week interval to be zero. Which statement must be true?The pool must have been empty for the entire interval.

The pool must have been the same depth at the start of the interval as it was at the end of the interval.

The pool must have been deeper at the end of the interval than it was at the start of the interval.

The pool must have been more shallow at the end of the interval than it was at the start of the interval.

Answers

Answer 1

Answer:

Answer: The pool must have been the same depth at the start of the interval as it was at the end of the interval.

Explanation:

The average rate of change is calculated as:

[final value - initial value] / time interval.

Then, the average rate of change does not take into account intermediates values, and you cannot draw any conclusion about such intermediate values.

In the given case you have:

average rate of change in depth = [final depth - initial depth] / 2 weeks.

0 = [final depth - initial depth] / 2 weeks.

⇒ 0 = final depth - initial depth

⇒ final depth = initial depth.

That is why the conclusion is the second statement of the answer choices: the pool must have been the same depth at the start of the interval as it was at the end of the interval.

In between the pool might have been deeper, more shallow, empty or change in any form, since the average rate of change does not tell the full history but only the net change.

Answer 2

Answer: "The pool must have been the same depth at the start of the interval as it was at the end of the interval" is the statement among the choices given in the question that must be true. The correct option among all the options that are given in the question is the second option. I hope the answer has helped you.

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Geoff planted dahlias in his garden. Dahlias have bulbs that divide and reproduce underground. In the first year, Geoff’s garden produced 8 bulbs. In the second year, it produced 16 bulbs, and in the third year it produced 32 bulbs. If this pattern continues, how many bulbs should Geoff expect in the sixth year?A. 64
B. 512
C. 128
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Answers

64 bulbs, you keep on adding 8 to the number of bulbs

I need full solution

Answers

Answer:

11= EC

Step-by-step explanation:

EC = 10 + 2 x + 19

= x + 20

So 2 x + 29 - x - 20 = 0

so x + 9 = 0

x = -9.

EC = x + 20 = -9+20 = 11.

Answer:

EC = 11 units

Step-by-step explanation:

first we find the value of x

10 + 2x + 19 = x + 20

2x - x = 20 - 10 - 19

x = -9

--------------------------------

check

10 + 2(-9) + 19 = -9 + 20

10 - 18 + 19 = -9 + 20

11 = 11

same value the answer is good

Now we find EC

EC = 10 + 2x + 19

EC = 10 + 2(-9) + 19 (remember PEMDAS)

EC = 10 - 18 + 19

EC = 11 units

There are 160 students in the band if there are 100 boys what is the REDUCED ratio of girls to boys?

Answers

6 out of every 10 student would be girls given that 100 of the students are boys awnser = 3/5

To find the ratio of boys to girls we do:
160-100=60
60:100
6:10
3:5
The ratio is 3 girls to 5 boys

Find the quotient.
48a 3 bc 2 ÷ 3abc
16a4b2c 3
16a2c
18a2c
16ac2

Answers

Answer: $16a^2c$

Step-by-step explanation:

Given division problem: $48a^3bc^2/48a^3bc^2$

It can be written as :

$(48a^3bc^2)/(3abc)$

Since, $48=3*16$

Divide 3 from numerator and denominator we get,

$(16a^3bc^2)/(abc)$

The division law of exponent says that

$(a^m)/(a^n)=a^(m-n)$

Therefore, $(16a^3bc^2)/(abc)=16a^(3-1)b^(1-1)c^(2-1)=16a^2b^0c^1=16a^2c$

Hence, $48a^3bc^2/48a^3bc^2=16a^2c$

48a^3 bc^2 / (3abc) = 16a^2c

Which statements are correct about quadrilaterals?Choose all answers that are correct.

A.
All squares are rhombuses.

B.
All rectangles are parallelograms.

C.
All rhombuses are trapezoids.

D.
All 4-sided shapes have at least one pair of parallel sides.

Answers

Hello,

A: True (4 sides equals in a square)

B: True all rectangle has a symetry centre

C: True (2 sides // in a rhombuse since is a parallelogram)

D:False

The sum of three consecutive even integers is 108. What is the largest number?a.34
b.35
c.37
d.38

Answers

Answer:

The largest of three numbers is 38.

Step-by-step explanation:

Given : The sum of three consecutive even integers is 108.

We have to find the largest of three consecutive even integer.

Consecutive integers are integer having a difference of one between each term . example 14 , 15, 16 ..

consecutive even integers are integers having a difference of two between them such that first term is in the form of 2n , where n is integers.

Consider the three consecutive even integers are 2n , 2n + 2 , 2n + 4

Also, given The sum of three consecutive even integers is 108.

that is 2n + 2n + 2 + 2n + 4 = 108

Simplify, we get,

6n + 6 = 108

Subtract 6 both side, we get,

6n = 102

Divide by 6 both side, we get,

n = 17

Thus, numbers are 2n = 2 × 17 = 34

2n + 2 = 34 + 2 = 36

2n + 4 = 34 + 4 = 38

Thus, The sum of three consecutive even integers is 108 then integers are 34, 36, 38 .

Thus, The largest of three numbers is 38.

Answer:

D is the answer

Step-by-step explanation:

took the test

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