If x2=y3, what is the value of z does x3z=y9?

Answers

Answer 1
Answer:

If x² = y³ , for what value of z doesx^(3z) =  Y^(9)  ?

Answer:

z= 2

Step-by-step explanation:

To solve the question given, we will follow the steps below;

X^(3z) =  Y^(9)   -----------------------------------------------------------------(1)

but   applying the law of indices mᵃᵇ = (mᵃ)ᵇ

then

Y^(9)  = (Y^(3))^(3)

replace  Y^(9)  by  (Y^(3))^(3)  in equation (1)

X^(3z) =  Y^(9)

X^(3z) =   (Y^(3))^(3)   --------------------------------------------------------------------(2)

but  from the question x² = y³

replace y³ by x²  in equation (2)

X^(3z) =   (Y^(3))^(3)

X^(3z) =   (X^(2))^(3)

X^(3z) =   X^(6)

3z = 6

divide both-side of the equation by 3

3z/3 = 6/3

On the left-hand side of the equation, 3 at the numerator will cancel-out 3  at the denominator leaving us with just z while on the right-hand side of the equation 6 will be divided by 3

z= 2


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What is the volume of this prism?

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its 378 cubes¬!!!!!!

I REALLY NEED HELP ON THIS, PLEASE!!!!

Answers

1. 2d+3

2.
n\cdot 7\n7n

The following set of coordinates represents which figure? (−5 ,2), (−3, 4), (1, 0), (−1, −2) (6 points)

Answers

The Points make a rectangle so it'll be B.

I can give you the expression or you give me the chose.
expression is y=x-1

Explain why (–4x)^0 = 1, but –4x^0 = –4.

Answers

Any number raised to power zero = 1. 

Note that 0 raised to power 0 is not 1, it is undefined.

Therefore:

(-4x)⁰ = 1

For the second part  -4x⁰ = :

x⁰ = 1,    -4x⁰ = -4*(1) = -4

 This is true on the assumption that x is not equal to zero.

I hope this explains it.

In the diagram , m Find m help pls

Answers

Answer:

119°

Step-by-step explanation:

90 + 29

Sally found that a solution of x = 2 was extraneous for her function. What would be a possible denominator in Sally's function?

Answers

If you have a fraction, then the denominator (bottom) cannot equal 0, since it is impossible to divide by 0. Take a look at the function below.

y=(5)/(x-2)

If we plugged in 2 for x, we would end up with a denominator of 0, making x = 2 "extraneous."

(you can use this example to answer your question, with the denominator being x-2...any expression that evaluates to 0 when x = 2 would work)

x=2 should work

yay so only follow thw answer above