MATHEMATICS HIGH SCHOOL

With regard to mathematics, what is an accepted statement of fact that is used to prove other statements?A)axiom
B)theroum
C)definition
D)undefined term

Answers

Answer 1
Answer: Answer – A. (Axiom)
 With regard to mathematics, the accepted statement of fact that is used to prove other statements is an axiom. An axiom refers to any mathematical statement that functions as a starting point from which other mathematical statements are logically derived.
Answer 2
Answer:

Answer:

With  regard to mathematics, an axiom is an accepted statement of fact that is used to prove other statements.

Step-by-step explanation:

As we know that an axiom - normally called postulate - is a statement which is considered to be true in order to serve as an initial point in order to establish further reasoning, from which we may be able to logically drive the other mathematical statements.

Therefore, with  regard to mathematics, an axiom is an accepted statement of fact that is used to prove other statements.

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John, Paul, and George have a combined age of 91. Paul is 14 years younger than John. George is 6 years older than John. How old is all three gentlemen?

Answers

Paul is 19, John is 33, and George is 39

Answer: john is 33, paul is 19, george is 39

Step-by-step explanation:

A skateboard company tracks the sales of their short boards and long boards. The company's records show the sales of short boards decrease every three months as represented by expression A, where t is the number of years that the boards have been for sale.expression a:624(o.94)^4t
The company's records show that the sales of long boards increase every four months as represented by expression B, where t is the number of years that the boards have been for sale.
expression b :725(1.12)^3t
Select the statements that give a correct interpretation of the above expressions.

Expression A grows at a rate of 5% every three months, while expression B decays at
a rate of 12% every four months.


Expression A has an initial value of 0.95, while expression B has an initial value of 1.12.

Expression A decays at a rate of 5% every three months, while expression B grows at
a rate of 12% every four months.

Expression A has an initial value of 624, while expression B has an initial value of 725.

Expression A decays at 5% every three years, while expression B grows at a rate of 12% every four years.

Answers

Answer:

Expression A decays at a rate of 5% every three months, while expression B grows at rate of 12% every four months

Expression A has initial value of 624, while expression B has initial value of 725

Step-by-step explanation:

plato correct
i really need help with this you have to choose all the ones that apply please help

Porfavor alguien me dice cuanto es esto 3×?=20​

Answers

Answer:

es imposible

Step-by-step explanation:

3x7=21

se va por uno

Answer:

6.66666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666

Step-by-step explanation:

Que no se te olvide el punto

What are the intercepts of f(x)=5x-45

Answers

The y-intercept of f(x) = 5x - 45 would be -45, as that is what is represented in the equation. The way to find the x-intercept would be to solve the equation when f(x) = 0.

     0 = 5x - 45
+ 45         + 45

   45 = 5x
    /5     /5
     9 = x

And there we have it.
The intercepts of f(x) = 5x - 45 are as follows:

y-intercept = -45
x-intercept = 9

Hope that helped =)

Which of these is a subset of rational number

Answers

Subsets of rational numbers are like whole numbers, integers, and fractions :) hope this helps
Subsets of rational numbers are like whole numbers, integers, and fractions i hope i am the brainliest i need it for the next rank

Evaluate the summation of 25 times 0.3 to the n plus 1 power, from n equals 2 to 10..

Answers

Answer:

\sum_(2)^(10)25(0.3)^(n+1)=0.9642375

Step-by-step explanation:

We have to evaluate the expression:

\sum_(2)^(10)25(0.3)^(n+1)

i.e. it could also be written as:

25\sum_(2)^(10)(0.3)^(n+1)

i.e. we need to evaluate:

25[(0.3)^3+(0.3)^4+(0.3)^5+(0.3)^6+(0.3)^7+(0.3)^8+(0.3)^9+(0.3)^(10)+(0.3)^(11)]

Hence, this could be written as:

=25* (0.3)^3[1+0.3^1+0.3^2+0.3^3+0.3^4+0.3^5+0.3^6+0.3^7+0.3^8]

Now, the series inside the parenthesis is a geometric series with first term as 1 and common ration as 0.3.

Hence, we could apply the summation of finite geometric series and get the answer.

We know that the sum of geometric series with n terms and common ratio less than 1  is calculated as:

S_n=a* ((1-r^n)/(1-r))

Here a=1 and r=0.3

Hence the sum of geometric series is:

S_9=1* ((1-0.3^9)/(1-0.3))\n\nS_9=1.4285

Hence, the final evaluation is:

=25* (0.3)^3* 1.4285\n\n=0.9642375

Hence,

\sum_(2)^(10)25(0.3)^(n+1)=0.9642375
We are asked to evaluate the summation of 25 times 0.3 to the n plus 1 power, from n equals 2 to 10. In this case, we use a calculator with summation powers so as to accurately get the answer. Using a calculator, the asnwer is equal to 0.9643. 
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