How do you figure out what is a trinomial?

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Answer 1
Answer:

Answer:

To factor trinomals in the form of x^2+bx+c, you have to find 2 integers, r and s, whose product is c, and whose sum is b. You have to rewrite the trinomial as x^2+rx+sx+c and then using the grouping and distribution of property to factor the polynomial. The result of the factors will be (x+r) and (x+s)

Step-by-step explanation:


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If Jim =5x - 8 and LM =2x -6,which expression represents JL?

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Answer:

The correct answer is A) 3x - 2

Step-by-step explanation:

In order to find this, take the value of JM and subtract the value of LM. This will give you JL.

JM - LM = JL

5x - 8 - (2x - 6) = JL

5x - 8 - 2x + 6 = JL

3x - 2 = JL

If f and t are both even functions, is f 1 t even? If f and t are both odd functions, is f 1 t odd? What if f is even and t is odd? Justify your answers.

Answers

If the f(x) and t(x) are even function then fo\ t\ (x) is an even function, if f(x) and t(x) are odd function then the function fo\ t\ (x) is an odd function and if f(x) is even and t(x) is odd then the function fo\ t\ (x) is an even function.

Further explanation:

An even functrion satisfies the property as shown below:

\boxed{f(-x)=f(x)}

An odd functrion satisfies the property as shown below:

\boxed{f(-x)=-f(x)}

Consider the given composite function as follows:

\boxed{fo\ t\ (x)=f\left(t(x))\right}

If both the function f(x) and t(x) are even function.

\begin{aligned}fo\ t\ (-x)&=f\left(t(-x))\right\n&=f\left(t(x))\right\n&=fo\ t\ (x)\end{aligned}

From the above calculation it is concluded that,

\boxed{fo\ t\ (-x)=fo\ t\ (x)}

This implies that the composite function fo\ t\ (x) is an even function.

If both the function f(x) and t(x) are odd function.

\begin{aligned}fo\ t\ (-x)&=f\left(t(-x))\right\n&=f\left(-t(x))\right\n&=-fo\ t\ (x)\end{aligned}

From the above calculation it is concluded that,

\boxed{fo\ t\ (-x)=-fo\ t\ (x)}

This implies that the composite function fo\ t\ (x) is an odd function.

If the function f(x) is even and t(x) is odd.

\begin{aligned}fo\ t\ (-x)&=f\left(t(-x))\right\n&=f\left(-t(x))\right\n&=fo\ t\ (x)\end{aligned}

From the above calculation it is concluded that,

\boxed{fo\ t\ (-x)=fo\ t\ (x)}

This implies that the composite function fo\ t\ (x) is an even function.

Find an equation for the line below.

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