A box of oranges weighs 4 kg. If one orange weighs 80 g, how many oranges are in the box?

Answers

Answer 1
Answer:

Answer:

50 oranges

Step-by-step explanation:

Convert the measurements for them to be the same ie 4kg to g

1kg=1000g. 4kgx1000=4000g

4000g is the mass of all oranges

1 orange=80g

? =4000g that is 4000/80

=50 oranges

Answer 2
Answer:

Answer:

50 oranges

Step-by-step explanation:

Since each orange is measured in grams, we convert the 4 kg to g to start.

4 kg is equal to 4000 g.

Each orange weighs 80 g, so we divide 80g into 4000g.

80 divided by 4000 equals 50.

50 oranges are in the box.

I Hope This Helps!


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2x + 4y = 123x - 5y = 10
A. Write the equations in slope-intercept form. (Show your work.)
B. Graph the pair of linear equations.
C. Use the graph to estimate the solution to the system of equations.
Help??

Answers

A. The first equation in slope-intercept form is y = -0.5x + 3. The second equation in slope-intercept form is y = 0.6x - 2.

B. The graph of the two equations is attached below.

C. The solution of the system of equation is (4.545,0.727)

A. To write the equations in slope-intercept form (y = mx + b), where "m" represents the slope and "b" represents the y-intercept, we need to isolate "y" on one side of each equation.

1. 2x + 4y = 12

First, isolate "y" by subtracting 2x from both sides:

4y = -2x + 12

Next, divide both sides by 4 to get "y" by itself:

y = (-2x + 12) / 4

Simplify the equation:

y = -0.5x + 3

So, the first equation in slope-intercept form is y = -0.5x + 3.

2. 3x - 5y = 10

First, isolate "y" by subtracting 3x from both sides:

-5y = -3x + 10

Next, divide both sides by -5 to get "y" by itself:

y = (-3x + 10) / -5

Simplify the equation:

y = 0.6x - 2

So, the second equation in slope-intercept form is y = 0.6x - 2.

B. To graph the pair of linear equations, plot the y-intercept (where x = 0) and use the slope to find other points.

1. Graph the equation y = -0.5x + 3:

Plot the y-intercept at (0, 3).

Use the slope -0.5 to find another point; for example, if x = 2, then y = -0.5(2) + 3 = 2.

2. Graph the equation y = 0.6x - 2:

Plot the y-intercept at (0, -2).

Use the slope 0.6 to find another point; for example, if x = 3, then y = 0.6(3) - 2 = 0.

C. To estimate the solution to the system of equations, look for the point where the two lines intersect. This point represents the x and y values that satisfy both equations simultaneously. From the graph, we can interpret that the solution of the system of equation is (4.545,0.727)

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1)     This format that the two equations are in is called Standard Form, and it's formula is Ax+By=CSlope-Intercept Form is another form in which linear equations can be written. It's expressed as y=mx+b. See how in SIF (Slope intercept form), the "y" is isolated? All you have to do is isolate the "y" in both equations given to you.

2x+4y=12
-2x       -2x
4y=-2x+12
/4           /4
y=-1/2x+3

3x-5y=10
-3x       -3x
-5y=-3x+10
/-5         /-5
y=3/5x-2

2)     To graph SIF, you need to know what each aspect of the equation is. The formula is y=mx+b.

m stands for slope. A great way to remember it is rise/run (rise over run). Basically, the numerator in "m" is how far up you go to graph each point, and the denominator is how far left or right you go (remember, left is negative, right is positive). Let me give you an example. y=3/5x. In this formula, to graph each point, on the line, you'd go up 3, and to the right 5, then plot a point, then up 3, right 5, plot another one... you get it. What if the equation was y=3x though? The slope would be 3/1, or up 3, right one.

You know how to plot the points, but what coordinate do you startat? That's where the Y-Intercept comes into play. The Y-Intercept is basically where the line crosses the Y-axis. The b in the SIF formula is the y-intercept, and where you plot your very first coordinate on the line. If the SIF equation was y=1x+3, your first coordinate would be on the y axis, at an elevation of 3. Since the y-axis is at x=0, the coordinate would be (0,3). 

3)     Look at the graph now. Where do the lines cross? The x should be somewhere between 4 and 5, and the y is somewhere between 1.5 and 2. Therefor, your "estimation" should be something like (4.5,1.75)

I really hoped this helped you! It took a while to write so I'd appreciate if you'd choose the Brainliest answer -- thanks!


A model rocket is launched from a roof into a large field. The path of the rocket can be modeled by the equation y = -0.06x^2 + 10.1x + 5, where x is the horizontal distance, in meters, from the starting point on the roof and y is the height, in meters, of the rocket above the ground. How far horizontally from its starting point will the rocket land?

Answers

Answer:

The horizontal distance from the starting point when rocket lands is:

168.83 meters.

Step-by-step explanation:

We are given a function that models the height of the rocket when it is 'x' meters away from the starting point.

The function is:

y=-0.06x^2+10.1x+5

Now we are asked to find the horizontal distance from the starting point when the rocket will land.

i.e. we are asked to find 'x' ; when y=0

i.e.

Let y=0

-0.06x^2+1.01x+5=0\n\ni.e.\n\n6x^2-1010x-500=0

on solving the quadratic equation we obtain:

x=-0.49360\ and\ x=(125)/(6)=168.83

As the distance can't be negative.

Hence, the viable solution is:

x=168.83

Hello,

y=-0.06x²+10.1x+5
==>6x²-1010x-500=0
Δ=1010²+4*6*500=1032100=(1015,92...)²
x=(1010-1015.92...)/12 <0 exclude
or x=(1010+1015.92..)/12=168.826935... (m)



Whats the answer for 4(3) x 3

Answers

It is 12×3 = 36

4(3) = 12 and multiply with three i.e. 12×3=36

Franks electric bill for the month of March was $85.78. The electric company charged a flat monthly fee of $20.00 for service plus $0.14 per kilowatt-hour of electricity used. Approximately how many kilowatt-hours of electricity did frank use in March?

Answers

The power utilised by frank in the month of march is 470 kilowatts - per hour.

What is an expression?

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that Franks's electric bill for the month of March was $85.78. The electric company charged a flat monthly fee of $20.00 for service plus $0.14 per kilowatt-hour of electricity used.

The equation will be written as,

B = 20 + 0.14K

85.78 = 20 + 0.14k

k = ( 80.78 - 20 ) / 0.14

K = 65.78 / 0.14

K = 470 Kilowatt-hour

Therefore, the power utilised by frank in the month of march is 470 kilowatts - per hour.

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Answer:

I got 469.8 kilowatt-hours. I got this by taking the total of Frank's bill, which was $85.78, and subtracting the flat monthly fee of $20.00. I did this because I need to find out the number of kilowatt-hours Frank used. Then, I divided $65.78 by $0.14 since that is the price per kilowatt-hour and got about 469.8 kilowatt-hours used by Frank.

What is the slope of side AC?

Answers

Answer:

The slope is  ( d-b)/ ( c-a)

Step-by-step explanation:

To find the slope we can use the slope formula

m = ( y2-y1_/(x2-x1)

  = ( d-b)/ ( c-a)

What is 12-2x6 + 2/2 ?

Answers

12-2*6 + (2)/(2)= \n 12-12+1 = 0 + 1 = 1