Marcus is picking songs to play during a slideshow. The songs are each 3\dfrac123 2 1 ​ 3, start fraction, 1, divided by, 2, end fraction minutes long. The slideshow is 31\dfrac1231 2 1 ​ 31, start fraction, 1, divided by, 2, end fraction minutes long.

Answers

Answer 1
Answer:

Answer:

number of songs = 9 songs

Step-by-step explanation:

According to Marcus the the song are each 3 start fraction , 1 divided by 2 end fraction minutes long. This can be expressed mathematically as 3 1/2 minutes long.

The slide show is 31, start fraction , 1 divided by, 2 end fraction minutes.  This can be expressed also as 31 1/2 minutes long.  The slide show contains the entire song.

Recall each song is 3 1/2 minutes long . The whole number fraction can be converted to improper fraction as 7/2 minutes long.

The whole slides show can be converted to improper fractions as 63/2 minutes long.

The number of song in the slideshow can be solved when we divide the total time in the slideshow by the time of each song.

number of songs = 63/2 ÷ 7/2

number of songs = 63/2 × 2/7

number of songs = 63/7

number of songs = 9 songs


Related Questions

The marked price of a shirt is 7200 a discount of 15% is on sales what is sale price​plz and fastttt
According to the EPA, about 40 million U.S. tons of hazardous waste is produced each year. If individual household waste makes up 1.6 million tons of this waste, what percent of the total hazardous amount produced is household waste? A. 0.04% B. 0.03% C. 0.25% D. 2.5% E. 4%
What is the solution of the equation below?x/6=x-4/2
What is the nth term for 3,4.5,6,7.5
(2a^(3))^(-3) -------- (3b(-2))

In which quadrant is the number -14 – 5i located on the complex plane? a.I b.II C.III D IV​

Answers

I believe It’s c.III (quadrant 3)

What are the real or imaginary solutions of the polynomial equation? x^3 = 216

Answers

x^3 = 216
this means that
x = 216^1/3
x = 6 (real solution)

x = -3 -3^(3/2)i (imaginary solution)
x = -3 +3^(3/2)i (imaginary solution)


x³ = 216 
∛x³ = ∛216
x = 6

g(p)=(p-2 )and g(x)=(p^3+4p^2-2) evaluate g(p)*h(p) by modeling or by using the distributive property.

Answers

Given that g(p)=p-2 and

h(p)=p^3+4p^2-2

Now we have to evaluate g(p)*h(p) by modeling or by using the distributive property.

We know that g(p)*h(p) means just multiply expressions of g(p) with h(p)

which can be shown as following:

g(p)*h(p)=(p^3+4p^2-2)(p-2)


Apply distributive property

g(p)*h(p)=p(p^3+4p^2-2)-2(p^3+4p^2-2)


g(p)*h(p)=p^4+4p^3-2p-2p^3-8p^2+4


g(p)*h(p)=p^4+2p^3-2p-8p^2+4


g(p)*h(p)=p^4+2p^3-8p^2-2p+4

Hence final answer is g(p)*h(p)=p^4+2p^3-8p^2-2p+4

What is the area of it

Answers