A horse runs around a circular track that is 350.0 m long. He runs clockwise fromthe start line back to the start line, then turns back and goes counterclockwise back
to the start line again. What is the horses displacement?

A. 0 m
B. 300.0 m counterclockwise
C. 300.0 m counterclockwise
D. 600.0 m

Answers

Answer 1

Answer:

Answer:

A 0m

Explanation:

The horse runs clockwise round the strack, then goes back to the start line ending up back at the same place when it started.

Answer 2

Answer: A. 0

As the horse goes back to the same “start line”.

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What net is required to push a sofa with a mass of 59 kilograms so that it accelerates at 9.75 meters/second^2 (assume a flat,frictionless surface.)

Answers

Newton's 2nd Law of Motion: Force = (mass) · (acceleration)

Do I need to go any further ?

I get 575.25 Newtons .

Oh ! Look at that ! Right there at the top, it says "Using Newton's Second Law". This might have suggested to you that maybe you could solve the problem by using Newton's Second Law.

Newton’s Third Law of Motion states that when one object exerts a force on a second object, the forces are __________________. A.
equal in magnitude and equal in direction

B.
equal in magnitude and opposite in direction

C.
opposite in magnitude and equal in direction

D.
opposite in magnitude and opposite in direction

Answers

b. equal in magnitude and opposite in direction

the answer of the question is A

Which two body systems work together closely to produce movement in human limbs

Answers

muscular and skeletal

muscular and skeletal , muscular works muscles and sketetal works mind and etc .

What has to happen for a feather and a ball to fall at the same rate?

Answers

Because the force of gravity is different for both of these objects, they will not fall at the same rate. To make both of these fall at the same rate, we need both to have the same mass so that the gravitational pull is equivalent also.

They will NOT fall at the same late.
A ball will fall much faster than a feather. A feather tends to float down, much as a ball, it immediately drops.

How is electron movement related to the bonding in sodium chloride? A) The atomic orbitals overlap and share electrons causing an ionic bond to form. B) Electrostatic sharing of electrons between atoms allows covalent bond formation. C) Electrons exchange creating ions to form an ionic bond by electrostatic attraction. D) Orbital overlap occurs between the atoms to exchange electrons to form the covalent bond.

Answers

Answer: Option (C) is the correct answer.

Explanation:

Sodium has atomic number 11 and its electronic distribution is 2, 8, 1. Whereas chlorine has atomic number 17 and its electronic configuration is 2, 8, 7.

Therefore, we can see that sodium has one extra electron and chlorine has deficiency of one electron.

So, in order to complete their octet sodium will give its one valence electron to the chlorine atom. Hence, there is exchange of electrons and thus it will result in the formation of ionic bond.

Thus, we can conclude that in sodium chloride electron movement is related to the bonding as electrons exchange creating ions to form an ionic bond by electrostatic attraction.

Answer:

Its C

Explanation: just had it on usatestprep

Sound waves produced by a source pass a point five times every second. Which of the following choices correctly describes the period and frequency of these waves? The frequency is 1/5 Hz, and the period is 1/5 second.

The frequency is 1/5 second, and the period is 5 Hz.

The period is 1/5 second, and the frequency is 5 Hz.

The period is 5 s, and the frequency is 5 Hz.

Answers

The period is 1/5 second, and the frequency is 5 Hz.

Explanation:

Let's start by reviewing some definitions about waves:

- The period of a wave is the time taken for the wave to make one complete cycle. It is indicated with T and it is measured in seconds (s)

- The frequency of a wave is the number of complete cycles made by the wave in one second. It is indicated with f and it is measured in Hertz (Hz). It is equal to the reciprocal of the period:

$f=(1)/(T)$

where f is the frequency and T is the period.

In this problem, we have a wave that passes a given point five time per second. This means that the number of oscillations per second is five, and so its frequency is:

$f=(5 cycles)/(1 sec)=5 Hz$