you are measuring the mass of various shapes objecys and identifying their shaped ypu then record the qualitative and quanatitave data in a table is qualitataive wnd which is quatitaive

Answers

Answer 1
Answer: Quantitative data is always numerical, like measurements or counts of things. Qualitative data is categorical, like descriptions and names. The type of shape is qualitative, and the mass is quantitative.

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You have been given an orange liquid and told to describe its properties. What methods would you use to observe, measure, and describe the physical properties of this orange liquid without changing it?

Answers

From observing the liquid you can get the following information: the color, the state of matter, the smell  and the fluidity [that is, does it flow freely or it is viscous in nature].
By measuring, you can get the volume of the liquid using measuring cylinder. You can also determine the temperature of the liquid at the room temperature using thermometer.

When an amoeba engulfs a particle of food a blank is formed

Answers

food vacuole is your answer

You have 17 grams of water and you increase the temperature by 15 degrees Celsius how many joules did this take?a. 255
b. 1067
c. 1.13
d. 63

Answers

Answer: the correct answer is option(d).

Explanation:

Energy required ,Q= ?

Mass of water , m = 17 grams

Temperature difference or\Delta T = 15 °C

Specific heat value of water = 4.186 J/g °C

Q=mc\Delta T=17* 4.186 J/g^oC* 15^oC=1,067.43 J\approx 1,067 J

From the given value the , nearest value to to our calculated answer is 1067 J that option (b).

Hence, the correct answer is option (d).

Which one is a true statement about endothermic reactions?Question 2 options:

Energy is absorbed making it feel colder.


The reaction container always feels hot.


The reactants have less heat energy than the products.


More heat is given off than is put into the reaction.

Answers

Answer:

-The reactants have less heat energy than the products.

Explanation;

-An endothermic reaction is a reaction in which heat energy is absorbed from the surroundings. In such a reaction the energy of the reactants is less than the energy of the products and therefore the enthalpy change is positive, greater than zero.

The answer is Energy is absorbed making it feel colder. Endothermic reactions absorb heat from their environment (hence lowering the temperature of the nearby environment), unlike ectothermic reactions that release energy to their environment . The enthalpy of products in an endothermic reaction is higher than that of the reactant hence the change in enthalpy is positive.

N2 + 6e → 2N-3The reaction above represents which of the following?
a. Reduction
b. Decomposition
Oxidation
d. Acid-Base Netralization​

Answers

Answer:

The correct answer is reduction.

Explanation:

Nitrogen gas reacts with hydrogen gas and get reduced to form ammonia. In this reaction.This is important reaction of atmospheric nitrogen fixation.The reaction is carried out by many nitrogen fixing bacteria such as Azotobacter,Clostridium etc.

        N2+3H2+6e-  =  2NH3

Final answer:

The reaction N2 + 6e → 2N-3 represents reduction, where nitrogen gains electrons to form N-3 ions.

Explanation:

The reaction N2 + 6e → 2N-3 represents reduction. In this reaction, nitrogen (N2) gains electrons (e) to form N-3 ions. Reduction is a process in which an atom or ion gains electrons, resulting in a decrease in its oxidation state.

Learn more about Reduction here:

brainly.com/question/33512011

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Find the ΔH for the reaction below, given the following reactions and subsequent ΔH values: PCl5(g) → PCl3(g) + Cl2(g) P4(s) + 6Cl2(g) → 4PCl3(g) ΔH = -2439 kJ
4PCl5(g) → P4(s) + 10Cl 2(g) ΔH = 3438 kJ

Answers

The value of  ΔH will be 249.75 KJ.

To obtain the reaction :

PCl5(g) → PCl3(g) + Cl2(g)

We have to add the given reactions and then divide it by 4.

(i) adding the reactions

  P4(s) + 6Cl2(g) → 4PCl3(g) ΔH = -2439 kJ

 4PCl5(g) → P4(s) + 10Cl 2(g) ΔH = 3438 kJ

we get:

  4PCl5(g) → 4PCl3(g) + 4Cl2(g),  ΔH = 3438 - 2439

(ii) dviding by 4

  PCl5(g) → PCl3(g) + Cl2(g)  ,  ΔH = (3438 - 2439)/4

 ΔH = 249.75 kJ is the required enthapy.

Learn more about enthalpy:

brainly.com/question/12676996

Answer:

The value of \Delta H for the desired reaction will be 249.75 KJ.

Explanation:

The desired reaction is shown below

\textrm{PCl}_(5)\left ( g \right )\rightarrow \textrm{PCl}_(3)\left ( g \right )+\textrm{Cl}_(2)\left ( g \right )

The desired reaction can be obtained by adding the given reactions and then dividing both sides by 4.

P_(4)\left ( s \right )+6Cl_(2)\left ( g \right )\rightarrow 4PCl_(3)\left ( g \right ) \n4PCl_(5)\left ( g \right )\rightarrow P_(4)\left ( s \right )+10Cl_(2)\left ( g \right )

Net Enthalpy change for the desired reaction

\displaystyle (3438-2439)/(4) \textrm{ KJ} = 249.75 \textrm{ KJ}

\Delta H = 249.75 \textrm{ KJ}