MATHEMATICS MIDDLE SCHOOL

My question is a complex numbers question: square root -6 times square root -24 the answer is -12, but I don't know how to solve it

Answers

Answer 1
Answer:

Answer:

see below

Step-by-step explanation:

sqrt( -6) * sqrt(-24)

We know that sqrt(a b) = sqrt(a) sqrt(b)

sqrt(6) sqrt(-1)  * sqrt(24) sqrt(-1)

We know that sqrt(-1) = i

sqrt(6) i  * sqrt(24) i

We know that sqrt(a) sqrt(b) = sqrt(ab)

sqrt(6*24) i*i

sqrt(144) i^2

12 i^2

We know that i^2 = -1

12 (-1)

-12

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PLEASE HELP I WOULD REALLY APPRECIATE IT!
Factors of -96 that add up to -10
4 hundredths equal how many thousandths

23% of 432 students equals how many students?

Answers

Multiply 23% by 432.
change 23% into a decimal which simply is 0.23
0.23*432=99.36
since it's students, and u can't have part of a student round it off and say 99 students.

Yara just received a 6% raise in salary. Before the raise, she was making $52,000 per year. How many more will Yara earn next year?

Answers

raise:\ 6\%*52000=(6)/(100)*52000=0,06*52000=3120\n\n 52000+3120=55120\$\n\n Next\ year\ she\ will\ earn\ 55120\$.

Answer:

its $3,120

Step-by-step explanation:

Simplify -sin^2x-cos^2x-tan^2x+cot^2x+sec^2x-csc^2x+2

Answers

 

\displaystyle\n\text{simplify: } -\sin^2x-\cos^2x-\tan^2x+\cot^2x+\sec^2x-\csc^2x+2\n\n\text{We use the formulas:}\n1)~~\sin^2x+\cos^2x=1\n\n2)~~\tan x=(\sin x)/(\cos x) ~~~~~~~3)~~\cot x= (\cos x)/(\sin x)\n \n4)~~\sec x=(1)/(\cos x) ~~~~~~~~5)~~\csc x=(1)/(\sin x)\n \n\text{Answer:}\n\n-\sin^2x-\cos^2x-\tan^2x+\cot^2x+\sec^2x-\csc^2x+2=\n\n=-(\sin^2x+\cos^2x)- (\sin^2x)/(\cos^2x)+(\cos^2x)/(\sin^2x)+\sec^2x-\csc^2x+2=


\displaystyle\n=-1- (\sin^2x)/(\cos^2x)+(\cos^2x)/(\sin^2x)+ (1)/(\cos^2x)- (1)/(\sin^2x) +2=\n\n=-(\sin^2x )/(\cos^2x)+(\cos^2x)/(\sin^2x)+ (1)/(\cos^2x)- (1)/(\sin^2x) +2-1=\n\n=(-\sin^4x+\cos^4x)/(sin^2x\cos^2x)+(\sin^2x-\cos^2x)/(\sin^2x\cos^2x)+1=\n\n=(\cos^4x-\sin^4x)/(\sin^2x\cos^2x)-(\cos^2x-\sin^2x)/(\sin^2x\cos^2x)+1=\n\n=((\cos^2x+\sin^2x)(\cos^2x-\sin^2x))/(\sin^2x\cos^2x)-(\cos^2x-\sin^2x)/(\sin^2x\cos^2x)+1=


\displaystyle\n=((1)\cdot(\cos^2x-\sin^2x))/(\sin^2x\cos^2x)-(\cos^2x-\sin^2x)/(\sin^2x\cos^2x)+1=\n\n=\underbrace{(\cos^2x-\sin^2x)/(\sin^2x\cos^2x)-(\cos^2x-\sin^2x)/(\sin^2x\cos^2x)}_(=~0)\,+\,1=0+1=\boxed{\boxed{\bf1}}

Answer: actually it is very complicated to explain but the answer is 1

Three times a number increased by 7 gives the same result as four times the number increased by 5? Heeellllpppp

Answers

If we were to write this as a mathematical equation, it would look something like this:

3x + 7 = 4x + 5

In order to solve, we would need to isolate the variable. We can do this by subtracting 3x from both sides, after doing which, we are left with this:

7 = x + 5

Then, we subract 5 from both sides to isolate the variable

2 = x

That number you are looking for is 2.

Let's check out work by substituting 2 in for the unknown number in the original problem:

3(2) + 7 = 4(2) + 5

6 + 7 = 8 + 5

13 = 13

And we can see that the numbers do indeed check out.

Your answer is 2.
Hope that helped! =)

What are the operations to get
1,a) 4-25, 5-32, 6-39, 7-46
2,a) 25-15, 30-18, 35-21

Answers

Both are doing the same operation which is subtraction.

I just want to clarify how to find this, i havn't done this in a while.

Answers

you could either use a calculator on the internet or do it manually:

512
128 * 4
32 * 4 * 4
8 * 4 * 4 * 2 * 2
8 * 8 * 4 * 2


8 * 8 * 8 = 512

\sqrt[3]{512} = 8
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