Which is the solubility product expression for Na3PO4(s)?A. [Na] +3(PO4)3-

B. [Na +3] / [PO43-]

C. [Na +] }[PO43-)

D. [Na] +3/[PO4) 3 -

Answers

Answer 1
Answer:

Final answer:

The solubility product expression for Na3PO4(s) is [Na+]^3[PO4^3-], which denotes the ion concentration in the solution after the dissolution of sodium phosphate. therefore, option A is correct

Explanation:

The solubility product expression for Na3PO4(s) would be written as [Na+]^3[PO4^3-]. The solubility product, Ksp, is the equilibrium constant for the dissolution of a sparingly soluble substance. The solubility product expression depends on the stoichiometry of the dissolution reaction. Sodium phosphate, Na3PO4, dissociates in water into 3 sodium ions, Na+, and 1 phosphate ion, PO4^3-. Therefore, the solubility product expression is [Na+]^3[PO4^3-], where [Na+] and [PO4^3-] represent the molar concentration of these ions in the solution.

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Answer 2
Answer:

Final answer:

The solubility product expression of Na3PO4 is not among the given options because Na3PO4 is soluble in water and for soluble compounds, we don't write a solubility expression.

Explanation:

The solubility product expression is typically written for an ionic compound that is sparingly soluble in water. The solubility product expression of Na3PO4 is not among the options you've provided because every ionic compound has its own specific solubility product expression. Na3PO4 is soluble, so we don't write a solubility expression for it. In general, for a reaction where a solid dissolves in water such as A3B (s) ↔ 3A+ (aq) + B3- (aq), the solubility product expression would be [A+]^3 [B3-].

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Answers

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78% Nitrogen (N2)
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What is this section of the periodic table called​

Answers

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Explanation:

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which type of relationship exists when a certain type of trees roots need a fungus present in order to grow normally

Answers

This is a symbiotic relationship called commensalism if the tree root is the only one to benefit.

Mrs. Jacobson is pushing a fridge to the right with a force of 100 N. The force pushing itto the left is 15 N. What is the net (leftover) force on the fridge?
85 N to the right
85 N to the left
115 N to the right
115 N to the left

Answers

Answer:

A

Explanation:

Let's illustrate this; see the attachment.

We see that Mrs. Jacobson is pushing to the right with a force of 100 N and there is another opposite force pushing with a force of 15 N. Since these are in opposite directions, we can say that the force opposite to Mrs. Jacobson is pushing the fridge -15 N to the right (instead of 15 N to the left).

The net force would then be:

100 N + (-15 N) = 85 N to the right

The answer is A.

Answer:

85 N to the right

Explanation:

Convention: rightwards positive

Force applied by Mrs. Jacobson:

+100

Force applied by the fridge:

-15

Net force

+100 - 15

+85

Balance the chemical equation. ___Mg + ___Fe2O^3 -> ___MgO + ___Fe

Answers

Answer:

3Mg + Fe₂O₃ → 3MgO + 2Fe.

Explanation:

  • To balance the equation, you should apply the law of conservation of mass for the equations.
  • The law of conservation of mass states that the no. of each atom is equal in both sides (reactants and products).
  • The balanced equation is:

3Mg + Fe₂O₃ → 3MgO + 2Fe.

That 3.0 mole of Mg react with 1.0 mole of Fe₂O₃ to produce 3.0 moles of MgO and 2.0 moles of Fe.

  • The no. of all atoms is the same in both of reactants and products side.

Mg (3), Fe (2), and O (3).