Wich substances is most likely to form in a precipitation reaction?

Answers

Answer 1

Answer:

Answer:

A precipitation reaction refers to the formation of an insoluble salt when two solutions containing soluble salts are combined. The insoluble salt that falls out of solution is known as the precipitate, hence the reaction's name.

Explanation:

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Upon adding solid potassium hydroxide pellets to water the following reaction takes place: KOH(s) → KOH(aq) + 43 kJ/mol Answer the following questions regarding the addition of 14.0 g of KOH to water: Does the beaker get warmer or colder? Is the reaction endothermic or exothermic? What is the enthalpy change for the dissolution of the 14.0 grams of KOH?
1. Potassium (K) has an atomic mass of 39.0983 amu and only two naturally-occurring isotopes. The K-41 isotope (40.9618 amu) has a natural abundance of 6.7302%. What is the mass (in amu) of the other isotope
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3.What do we call materials
that let heat pass through
them easily?
Thermal conductors
Thermal insulators
Transparent

4.
Which of these is a good
thermal conductor?
Plastic
Wood
Steel

5.
Which of these is a good
thermal insulator?
Steel
Iron
Polystyrene

6.
To save on heating bills, do
you think the roof of a
building should be lined with...
a thermal conductor
a thermal insulator
nothing

7.
How does heat travel?
From cold things to hotter things
From hot things to colder things
Between things of the same temperature

Answers

Answer:

thermal conductors

steel

polystyrene

thermal insulator

between things of the same temp?

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When 1-iodo-1-methylcyclohexane is treated with NaOCH2CH3 as the base, the more highly substituted alkene product predominates. When KOC(CH3)3 is used as the base, the less highly substituted alkene predominates. Give the structures of the two products and offer an explanation.

Answers

Answer:

See explanation

Explanation:

In this case, we have 2 types of reactions. $CH_3CH_2ONa$ is a strong base but only has 2 carbons therefore we will have less steric hindrance in this base. So, the base can remove hydrogens that are bonded on carbons 1 or 6, therefore, we will have a more substituted alkene (1-methylcyclohex-1-ene).

For the $KOC(CH_3)_3$ we have more steric hindrance. So, we can remove only the hydrogens from carbon 7 and we will produce a less substituted alkene (methylenecyclohexane).

See figure 1

I hope it helps!

Unknown A melts at 113- 114oC. Known compounds 3-Nitroaniline and 4-Nitrophenol both melt at 112-114 oC. If A is mixed with 3-Nitroaniline and the melting point becomes broad and depressed, what must A be __________A) 3-Nitroaniline B) 4-Nitrophenol C) Both

Answers

Answer:

C) Both

Explanation:

Whenever we mix any pure form of a compound with some other form of a compound which is not in the other standard pure state, this results in the melting point of mixture to get dispersed and it becomes broad form.

Thus, when a known compound of 3-Nitroaniline mixes with both 3-Nitroaniline and 4-Nitrophenol, the melting point of the compound becomes depressed and board.

Thus the correct option is (C).

A 0.5-m3 rigid tank contains refrigerant-134a initially at 200 kPa and 40 percent quality. Heat is transferred now to the refrigerant from a source at 358C until the pressure rises to 400 kPa. Determine (a) the entropy change of the refrigerant, (b) the entropy change of the heat source, and (c) the total entropy change for this process.

Answers

Answer:

(a) $\Delta S_(ref)=3.876(kJ)/(K)$

(b) $S_(heat\ source)=-1.678(kJ)/(K)$

Explanation:

Hello,

(a) In this case, such refrigerant, we can notice that at the given conditions, the initial entropy from property tables (Cengel 7th ed) is:

$s_(initial)=s_f+xs_(fg)=0.15457+0.4*0.78316=0.4678(kJ)/(kg*K)$

Now, for the final condition, we first need to compute the initial specific volume as it remains the same (rigid tank) after the thermodynamic process:

$v_(initial)=v_f+xv_(fg)=0.0007533+0.4*(0.099867-0.0007533)=0.0404(m^3)/(kg)$

Then, at 400 kPa we evaluate the given volume that is also between the liquid and vapor specific volume, thus, we calculate the quality at the end of the process:

$x_f=(0.0404-0.0007907)/(0.051201-0.0007907) =0.786$

With it, we compute the final entropy:

$s_(final)=0.24761+0.785*0.67929=0.781(kJ)/(kg*K)$

Finally, entropy change for the refrigerant turns out:

$m_(ref)=(0.5m^3)/(0.0404(m^3)/(kg) )=12.4kg \n\n\Delta S_(ref)=12.4kg *(0.781(kJ)/(kg*K)-0.4678(kJ)/(kg*K) )\n\n\Delta S_(ref)=3.876(kJ)/(K)$

(b) In this case, by using the first law of thermodynamics we compute the acquired heat by the refrigerant from the heat source by computing the initial and final internal energy respectively (no work is done):

$Q=\Delta U$

$u_(initial)=38.28+0.4*186.21=112.764(kJ)/(kg)\n \nu_(final)=63.62+0.786*171.45=198.40(kJ)/(kg)$

Hence:

$Q=12.4kg*(198.40-112.764)(kJ)/(kg) =1059.1kJ$

Finally, the entropy change of the heat source (which release the heat, therefore it is negative):

$S_(heat\ source)=(1059.1kJ )/((358+273.15)K) \n\nS_(heat\ source)=-1.678(kJ)/(K)$

$\Delta S _(tot)=3.876(kJ)/(K)-1.678(kJ)/(K)\n\n\Delta S _(tot)=2.198(kJ)/(K)$

Which has thermodynamic agreement as it is positive

Regards.

Final answer:

The entropy changes in this process can be partially calculated using principles from thermodynamics. However, without the exact heat transfer, not all values can be determined.

Explanation:

The calculation of the entropy change in this thermodynamic process involves principles from thermodynamics and requires steps to determine the initial and final states of the refrigerant. First, we would need to find the entropy at the initial and final states using the refrigerant properties table for refrigerant-134a and the provided information (200 kPa and 40% quality initially, 400 kPa finally). The entropy change of the refrigerant is the difference between the final and initial entropy.

Next, the entropy change of the heat source is calculated as the heat transfer divided by the absolute temperature of the source. However, the problem does not provide the amount of heat transferred from the source, making it impossible to determine this value directly.

Finally, in an isolated system, the total entropy change of the process is the sum of the entropy changes of the refrigerant and the heat source. Here, the precise values cannot be calculated due to a lack of specific data including exact heat transfer.

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Which of the following Ph levels would indicate the weakest base?15

8

6

2

Answers

Answer:

Explanation:

7 is neutral any anything above it is basic and anything below is acidic which means 8 would be the lowest base

Answer:

The pH of a weak base falls somewhere between 7 and 10.

Explanation:

Like weak acids, weak bases do not undergo complete dissociation; instead, their ionization is a two-way reaction with a definite equilibrium point

All voltmeters have two probes attached to make a measurement explain why you cannot make a voltmeter with a single probe to measure the voltage of a wire

Answers

As voltages is a potential in relation to a reference, one probe must be on the reference or "zero" planes and the other must be on the point being measured.

Why does a voltmeter not accurately read voltage?

because the voltmeter uses some of the main circuit's current. Main present in the circuit diminishes as a result, and the voltmeter's reading of the potential difference does not correspond to its true value.

Why are there two probes on a voltmeter?

Nothing is measured at a specific point by the voltmeter. It gauges the voltage (V) differential between two circuit locations. Thus, a multimeter has two leads rather than one.

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wo reactions and their equilibrium constants are given. A + 2 B − ⇀ ↽ − 2 C K 1 = 2.57 2 C − ⇀ ↽ − D K 2 = 0.226 A+2B↽−−⇀2CK1=2.572C↽−−⇀DK2=0.226 Calculate the value of the equilibrium constant for the reaction D − ⇀ ↽ − A + 2 B .