Consider the sequence of steps to solve the equation: 3(x − 4) + 5x = 9x − 36 Given ⇒ 3(x − 4) + 5x = 9x − 36 Step 1 ⇒ 3x − 12 + 5x = 9x − 36 Step 2 ⇒ 3x + 5x − 12 = 9x − 36 Step 3 ⇒ 8x − 12 = 9x − 36 Step 4 ⇒ 8x − 8x − 12 = 9x − 8x − 36 Step 5 ⇒ 0 − 12 = x − 36 Step 6 ⇒ −12 = x − 36 Step 7 ⇒ −12 + 36 = x − 36 + 36 Step 8 ⇒ 24 = x + 0 Step 9 ⇒ 24 = x Which property yields Step 1?

Answers

Answer 1
Answer:

Answer:

Step-by-step explanation:

Distributive  property

a(b - c) = ab - ac

3(x-4) = 3*x - 3*4  

         = 3x - 12


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(n-3)(n-5)what's the equivalent

Answers

Lets expand the expression using the FOIL method
FOIL=First,Outer,Inner,Last

We'd start by multiplying the first numbers in each parenthesis by eachother:

(n-3)(n-5)
n*n=n
²

Now the outer two values...

(n-3)(n-5)
-5n

The inner two values

(n-3)(n-5)
-3n

And the last two values
(n-3)(n-5)
-3*-5=15

Now just put all of the expressions together...

n²-5n-3n+15
simplify
n²-8n+15

Answer=n²-8n+15

When a business opens, it has an initial value of $956K. Two years later, the company has a value of $1.26 million.By how many dollars has the company increased in value? Do not round.

By what percentage has the company increased in value? Round the percentage to one decimal place.

Answers

The value of the company has increased by 304k dollars.

What is a numerical expression?

A numerical expression is written in form of numbers and their operations.

Numerical expression can be formed from a given statement also.

According to the given question When a business opens, it has an initial value of 956k dollars. Two years later the company has a value of 1.26 million dollars.

We know 1 million is = 1000k.

∴ 1.26 million is = 1260 dollars.

So, by (1260 - 956)k = 304k dollars the company increased in value.

Read more about numerical expression at:

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How can you use functions and graphs to represent periodic data? will need mathematical example.

Answers

Hello,

Here is a example of a periodic function

What is the value of the system determinant for the following system of equations? 6x + y = 4 5x + y - 7 = 0

Answers

Answer:  The value of the determinant is 1.

Step-by-step explanation:  The given system of linear equation is as follows:

6x+y=4~~~~~~~~~~~~~~~~(i)\n\n5x-y-7=0\n\n\Rightarrow 5x-y=7~~~~~~~~~~~(ii)

The first column of the determinant gives the coefficients of 'x' and the second column gives the coefficients of y in the two equations.

Therefore, the determinant for the given system is

D=\begin{vmatrix} 6& 1\n  5& 1\end{vmatrix}=6* 1-5* 1=6-5=1.

Thus, the required value of the determinant is 1.

Can you help me with this question? This is tricky question

Answers

There's nothing tricky about it.

2\cdot2+2\cdot2+2-2\cdot2=4+4+2-4=6 \Rightarrow A
so pemdas
first multiplication

(2*2)+(2*2)+2-(2*2)=(4)+(4)+2-(4)=8+2-4=10-4=6
the answer is A

Find the first five terms of the sequence defined by each of these recurrencerelations and initial conditions.
a) an = 6an-1, a0 = 2
b) an = −2an-1, a0 = −1
c) an = an-1 – an-2, a0 = 2, a1 = −1

Answers

a) The first five terms of the sequence are 2, 12, 72, 432, 2592.
b) The first five terms of the sequence are -1, 2, -4, 8, -16.

c) The first five terms of the sequence are 2, -1, -3, -2, 1.

To find the first five terms of the sequence defined by each of these recurrence relations and initial conditions, we will use the given recurrence relation and initial conditions to find the next terms in the sequence.

a) an = 6an-1, a0 = 2

The first term is given as a0 = 2. We will use the recurrence relation to find the next terms.
a1 = 6a0 = 6(2) = 12
a2 = 6a1 = 6(12) = 72
a3 = 6a2 = 6(72) = 432
a4 = 6a3 = 6(432) = 2592

So, the first five terms of the sequence are 2, 12, 72, 432, 2592.

b) an = −2an-1, a0 = −1

The first term is given as a0 = -1. We will use the recurrence relation to find the next terms.
a1 = -2a0 = -2(-1) = 2
a2 = -2a1 = -2(2) = -4
a3 = -2a2 = -2(-4) = 8
a4 = -2a3 = -2(8) = -16

So, the first five terms of the sequence are -1, 2, -4, 8, -16.

c) an = an-1 – an-2, a0 = 2, a1 = −1

The first two terms are given as a0 = 2 and a1 = -1. We will use the recurrence relation to find the next terms.
a2 = a1 - a0 = -1 - 2 = -3
a3 = a2 - a1 = -3 - (-1) = -2
a4 = a3 - a2 = -2 - (-3) = 1

So, the first five terms of the sequence are 2, -1, -3, -2, 1.

Learn more about Recurrence

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