The volume V of an ideal gas varies directly with the temperature T and inversely with thepressure P. A cylinder contains oxygen at a temperature of 320 degrees Kelvin and a pressure of


25 atmospheres in a volume of 120 liters. Find the pressure if the volume is decreased to 110


liters and the temperature is increased to 335 degrees Kelvin.


Hint: Look at the equation V = k* Then use the initial values to solve for k. Then plug in the


values you know for the second set of values and solve for your unknown.

Answers

Answer 1
Answer:

Answer:

Pressure=22.55 atmospheres

Step-by-step explanation:

Let

V=volume of the ideal gas

P=pressure

T=temperature

Volume varies directly with temperature and inversely with pressure

V=kT/P

t=320°K

P=25 atmospheres

V=120 liters

V=kT/P

120=k*320/25

120=320k/25

120×25=320k

3000=320k

k=300/320

=9.375

k=9.375

V=110 liters

p=?

t=335°K

V=kT/P

110=9.375*335/p

110=3,140.625/p

110p=3,140.625

P=3,140.625/110

=28.55

P=22.55 atmospheres


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The 3rd degree Taylor polynomial for cos(x) centered at a = π 2 is given by, cos(x) = − x − π 2 + 1 6 x − π 2 3 + R3(x). Using this, estimate cos(88°) correct to five decimal places.

Answers

Final answer:

Cos(88°) can be estimated using the 3rd degree Taylor polynomial for cos(x) centered at a = π/2. The degrees need to be converted to radians, and by substituting into the polynomial, the cosine value to five decimal places is approximately 0.03490.

Explanation:

To estimate cos(88°) using the 3rd degree Taylor polynomial for cos(x) centered at a = π/2, we first need to convert 88 degrees to radians as cos(x) expects x in radians. 88 degrees is roughly 1.53589 radians. Now, substituting x = 1.53589 into the Taylor polynomial yields the estimate.

The given Taylor polynomial is represented as cos(x) = - (x - π/2) + 1/6 * (x - π/2)³. Substituting x with 1.53589, we get:

cos(1.53589) = - (1.53589 - π/2) + 1/6 * (1.53589 - π/2)³

To get the estimate correct to five decimal places, you calculate the above expression to get roughly 0.03490. Therefore, cos(88°) is approximately 0.03490.

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Final answer:

First, we convert the given angle 88° into radians, since standard trigonometrical functions take angles in radians. We then substitute this into the Taylor series given, keeping in mind the importance of the remainder term.

Explanation:

This problem deals with the concept of Taylor series approximation, which is a widely used method in mathematics to estimate the value of functions. The given Taylor polynomial approximates the cosine function. To estimate cos(88°), we first need to convert the angle from degrees to radians, because the standard trigonometric functions in mathematics take input in radians. Remember that 180° equals π radians. So 88° can be represented as (88/180)π radians.

Substitute this into the provided series − x − π/2 + 1/6 * (x − π/2)³ + R3(x). Be wary of the remainder term R3(x). This term ensures the correctness of the approximation on the interval of convergence. The closer x is to the center, the more accurate the approximation. In practical computations, you might need to take more terms into account to ensure sufficient accuracy to five decimal places in this case.

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Please help me solve this problem

Answers

Answer:A

Step-by-step explanation:

The dot means less than or equal to 2

Open dot means greater than 2

A classroom board is 36 inches wide and 24 inches tall. Cherylis putting ribbon along the outside edge of the board. How
many inches of ribbon will she need?
24 inches
36 inches
A 156 inches B 120 inches
C90 inches
D 60 inches

Answers

The amount of ribbon needed is 120 inches

what is perimeter?

The perimeter formula for a rectangle states that P = (L + W) × 2, where P represents perimeter, L represents length, and W represents width.

Given:

length = 24 inches

width = 36 inches

So, amount of ribbon needed

=2(36+ 24)

=2(60)

=120 inches

Hence, the amount of ribbon needed is 120 inches

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Answer:

option B

Step-by-step explanation:

NO LINKS OR ANSWERING WHAT YOU DON'T KNOW?1. Suppose y varies inversely with x, and y = 25 when x = 1/5. What is the value of y when x = 5?

a. 15
b. 5
c. 25
d. 1

2. Suppose y varies inversely with x, and y = a when x = a^2. What inverse variation equation related x and y?

a. y = a^2/x
b. y = a^3/x
c. y= a^3x
d. y = ax

3. Suppose y varies inversely with x, and y = 3 when x = 1/3. What is the inverse variation equation that relates x and y?

a. y = 1/x
b. y =x
c. y = 3x
d. y = 3/x

Answers

Answer:

1. D. 1

2. B. y=a³/x

3. A. y=1/x

Step-by-step explanation:

too long to give te explanations but they're there in the attachments

Assume that you plan to use a significance level of α = 0.05 to test the claim that p1 = p2. Use the given sample sizes and numbers of successes to find the pooled estimate. Round your answer to the nearest thousandth. n1 = 677 n2 = 3377
x1 = 172 x2 = 654

Answers

Answer:

The calculated  value Z = 3.775 > 1.96 at 0.05 level of significance

Null hypothesis is rejected

The Two Population proportion are not equal

Step-by-step explanation:

Given first sample size n₁ = 677

First sample proportion

                             p^(-) _(1) = (x_(1) )/(n_(1) ) = (172)/(677) = 0.254

Given second sample size n₂ = 3377

second sample proportion

                             p^(-) _(2) = (x_(2) )/(n_(2) ) = (654)/(3377) = 0.1936

Null Hypothesis : H₀ :  p₁ = p₂.

Alternative Hypothesis : H₁ :  p₁ ≠ p₂.

      Test statistic

                Z = \frac{p_(1) ^(-)-p^(-) _(2)  }{\sqrt{P Q((1)/(n_(1) ) +(1)/(n_(2) )) } }

where

        P = (n_(1) p_(1) + n_(2) p_(2)  )/(n_(1)+n_(2)  ) = (677 X 0.254+3377 X 0.1936)/(677+3377)

       P =  0.2036

      Q = 1 - P = 1 - 0.2036 = 0.7964

       

         Z = \frac{0.254- 0.1936 }{\sqrt{0.2036 X 0.7964((1)/(677 ) +(1)/(3377 )) } }

        Z =  3.775

Critical value ∝=0.05

Z- value = 1.96

The calculated  value Z = 3.775 > 1.96 at 0.05 level of significance

Null hypothesis is rejected

The Two Population proportion are not equal

B) In a sunny day, the length of the shadow of a pole 30m long is equal to theof the pole. After a while, it is found to be 51.96m long, find the altitude of the sun in both cases.​

Answers

When the shadow is 30 meters long, the angle of the sun is 45°.

When the shadow is 51.96 meters long, the angle of the sun is arctan(30/51.96) = 30°