PLEASE HELP CHEM BABES I HAVE BEEN CRYING FOR A WHILE NOW 1. Calculate the mass of nitrogen dioxide (NO2) present in a 0.831 L container if the pressure is 100 kPa at a temperature of 27 oC. R = 8.31 kPa x L / mol x K. (K = oC + 273).

2. A 33.2 L tank contains 280 g of compressed helium. If the pressure inside the tank is 700.0 kPa, what is the temperature of the compressed gas? You must convert the mass of helium into moles using the molar mass of He. The conversion factor will be 1 mol / molar mass of helium. R = 8.31 kPa x L / mol x K

Answers

Answer 1

Answer:

Answer: See below

Explanation:

1. To calculate the mass, you know you can convert by using molar mass. Since mass is in grams, we can use molar mass to convert moles to grams. This calls for the Ideal Gas Law.

Ideal Gas Law: PV=nRT

We manipulate the equation so that we are solving for moles, then convert moles to grams.

n=PV/RT

P= 100 kPa

V= 0.831 L

R= 8.31 kPa*L/mol*K

T= 27°C+273= 300 K

Now that we have our values listed, we can plug in to find moles.

$n=((100kPa)(0.831L))/((8.31kPa*l/molK)(300K))$

$n=0.033mol$

We use the molar mass of NO₂ to find grams.

$0.033mol*(46.005g)/(1mol )=1.52 g$

The mass is 1.52 g.

2. To calculate the temperature, we need to use the Ideal Gas Law.

Ideal Gas Law: PV=nRT

We can manipulate the equation so that we are solving for temperature.

T=PV/nR

P= 700.0 kPa

V= 33.2 L

R= 8.31 kPa*L/mol*K

n= 70 mol

Now that we have our values, we can plug in and solve for temperature.

$T=((700kPa)(33.2L))/((70mol)(8.31 kPa*L/molK))$

$T=40K$

The temperature is 40 K.

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What particle is emitted in alpha radiation

A _____ change occurs when a substance changes phase.
physical
chemical
nuclear

Answers

A physical change occurs when a substance changes phase.

For example, boiling pure water (H₂O) is physical change of substance (from liquid to gaseous state). In physical change, the bonds between oxygen and hydrogen can not be separated.

Sublimation of iodine (from solid to gas state) is also physical change.

Physical property can be observed and measured without any changes in molecular composition. The same substance is present before and after the change.

Final answer:

A physical change occurs when a substance changes phase. In this process, a substance may change from one state of matter to another but its foundational substance remains the same.

Explanation:

A physical change takes place when a substance alters its phase. This means that it shifts from one state of matter (solid, liquid, gas) to another. It's crucial to remember that although the physical characteristics of the substance may change, its substance does not. Let's take an example of water, it can exist as solid (ice), liquid (water), and gas (steam) but in all these states it remains H2O. Therefore, when a substance changes phase, it undergoes a physical change, not a chemical or a nuclear change.

Learn more about Phase Change here:

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ANSWER ASAP PLEASE Which of the following objects is the most dense?
Object A: mass = 50 g, volume = 5 cm³
Object B: mass = 50 g, volume = 10 cm³
Object C: mass = 10 g, volume = 50 cm³
Object D: mass = 5 g, volume = 50 cm³

Answers

Density is equal to mass divided by volume so the densest object will be the object that has the largest mass in the smallest area. In this case object A is the densest with a density of 10g/cm^3. I hope this helps. Let me know if anything is unclear.

Calculate the density of a sample of liquid with a volume of 130 ml and a mass of 585 g.

Answers

Answer:

4.5 g/ml

Explanation:

Density is the ratio of the mass of the liquid to the volume of the liquid. The unit of mass, volume and density are g, ml and g/ml respectively.

Density is directly proportional to the mass of the substance and is inversely proportional to the volume.

Given,

Mass of the liquid = 585 g

Volume of the liquid = 130 ml

Density = $(mass)/(volume)$ = $(585 g)/(130 ml)$ = 4.5 g/ml

The density of the sample of liquid with a volume of 130 mL and mass 585 g is $\boxed{4.5\;{\text{g/mL}}}$

Further explanation:

The property is a unique feature of the substance that differentiates it from the other substances. It is classified into two types:

1. Intensive properties:

These are the properties that depend on the nature of the substance. These don't depend on the size of the system. Their values remain unaltered even if the system is further divided into a number of subsystems. Temperature, refractive index, concentration, pressure, and density are some of the examples of intensive properties.

2. Extensive properties:

These are the properties that depend on the amount of the substance. These are additive in nature when a single system is divided into many subsystems. Mass, energy, size, weight, and length are some of the examples of extensive properties.

Density is a characteristic property of the substance. It is defined as the mass per unit volume. It is generally represented by $\rho$ .

The formula to calculate the density of the liquid is,

${\mathbf{Density of liquid}}\left({\mathbf{\rho}}\right){\mathbf{=}}\frac{{{\mathbf{Mass of liquid}}\left({\mathbf{M}}\right)}}{{{\mathbf{Volume of liquid}}\left({\mathbf{V}}\right)}}$ …… (1)

The mass of liquid (M) is 585 g. The volume of liquid (V) is 130 mL.

Substitute 585 g for the mass of liquid and 130 mL for the volume of liquid in equation (1).

$\begin{gathered}{\text{Density of liquid}}\left(\rho\right)=\frac{{{\text{585 g}}}}{{{\text{130 mL}}}}\n=\boxed{4.5\;{\text{g/mL}}}\n\end{gathered}$

So the density of the liquid with a volume of 130 mL and mass 585 g is ${\mathbf{4}}{\mathbf{.5}}\;{\mathbf{g}}{\text{/}}{\mathbf{mL}}$ .

Learn more:

1. Calculation of volume of gas: brainly.com/question/3636135

2. Determine how many moles of water produce: brainly.com/question/1405182

Answer details:

Grade: Middle School

Subject: Chemistry

Chapter: Density

Keywords: density, mass, volume, 130 ml, liquid, intensive, extensive, characteristic property, 585 g, substance, amount, nature, same, additive.

A 3.50 g sample of an unknown compound containing only C , H , and O combusts in an oxygen‑rich environment. When the products have cooled to 20.0 °C at 1 bar, there are 4.41 L of CO2 and 3.26 mL of H2O . The density of water at 20.0 °C is 0.998 g/mL.

Answers

Explanation:

First, calculate the moles of $CO_(2)$ using ideal gas equation as follows.

PV = nRT

or, n = $(PV)/(RT)$

= $(1 atm * 4.41 ml)/(0.0821 Latm/mol K * 293 K)$ (as 1 bar = 1 atm (approx))

= 0.183 mol

As, Density = $(mass)/(volume)$

Hence, mass of water will be as follows.

Density = $(mass)/(volume)$

0.998 g/ml = $(mass)/(3.26 ml)$

mass = 3.25 g

Similarly, calculate the moles of water as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $(3.25 g)/(18.02 g/mol)$

= 0.180 mol

Moles of hydrogen = $0.180 * 2$ = 0.36 mol

Now, mass of carbon will be as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

0.183 mol = $(mass)/(12 g/mol)$

= 2.19 g

Therefore, mass of oxygen will be as follows.

Mass of O = mass of sample - (mass of C + mass of H)

= 3.50 g - (2.19 g + 0.36 g)

= 0.95 g

Therefore, moles of oxygen will be as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $(0.95 g)/(16 g/mol)$

= 0.059 mol

Now, diving number of moles of each element of the compound by smallest no. of moles as follows.

C H O

No. of moles: 0.183 0.36 0.059

On dividing: 3.1 6.1 1

Therefore, empirical formula of the given compound is $C_(3)H_(6)O$ .

Thus, we can conclude that empirical formula of the given compound is $C_(3)H_(6)O$ .

Besides water, what is the product of a Neutalization Reaction between HClO3 and Sr(OH)2?a. SrClO3
b. Sr-1(ClO3)+2
c. Sr2CIO3
d. Sr(ClO3)2

Answers

Answer:

The answer to your question is letter d. Sr(ClO₃)₂

Explanation:

Data

Reactants HClO₃ and Sr(OH)₂

This is a neutralization reaction because the reactants are a base (Sr(OH)₂) and an acid (HClO₃).

The products in a neutralization reaction are always water and a salt.

Balanced chemical reaction

Sr(OH)₂ + HClO₃ ⇒ H₂O + Sr(ClO₃)₂

A hydrocarbon molecule is considered to be saturated when the molecule contains

Answers

The best phrase to complete the sentence is "single bonds". A hydrocarbon molecule is considered to be saturated when the molecule contains single bonds. Alkanes are a saturated type of hydrocarbon. They only consists of hydrogen and carbon atoms in single bonds. The general formula is CnH2n+2. C4H10 is the molecular formula for butane. It is an example of a saturated hydrocarbon.

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