What is the name of the body part that passes messagesfrom the sensory neurons to the brain?
o Lungs
O Nerve Cells
o Brain
o Stimulus please help me thanks

Answers

Answer 1

Answer: The answer would be nerve cells. Hope that helps you!

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Answers

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If an atom has 5 electrons outside of its nucleus, which combination of protons and neutrons would result in a neutral atom?

Answers

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What ion is present in all acid solutions?

Answers

Hydrogen is present in all acid solutions

Answer:

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Explanation:

What happened to the amount of carbon dioxide in the atmosphere from 2010–2017?

Answers

The amount of CO2 in the atmosphere has increased dramatically due to(mainly) excessive burning of fossil fuels.

Answer:

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How many liters of CO2 form at STP if 5.0 g ofCaCO3 are treated with excess hydrochloric acid?

Answers

Answer: STP

CaCO3 = 5 g

Convert gram to mol

100 g of CaCO3 = 1 mol

5 g of CaCO3 (n) = 5 g *(1 mol/100 g) = 0.05 mol

Gas law

PV =nRT

V = nRT/P

V = (0.05 mol * (0.08206 L atm /K mol) *273 K)/1 atm

V = 1.124 L

Explanation:

Final answer:

When 5.0 g of CaCO3 are treated with excess hydrochloric acid, it forms 1.118 L of CO2 gas at STP.

Explanation:

When 5.0 g of CaCO3 is treated with excess hydrochloric acid, it undergoes a chemical reaction and forms CO2 gas. To find the number of liters of CO2 formed at STP (standard temperature and pressure), we need to use the ideal gas law. The molar mass of CaCO3 is 100.09 g/mol, and 1 mol of CaCO3 produces 1 mol of CO2 gas. The volume of 1 mol of any gas at STP is 22.4 L. Therefore, we can calculate the number of moles of CaCO3, then convert it to moles of CO2 and finally to the volume of CO2 gas in liters.

Using the given information, we have:
Mass of CaCO3 = 5.0 g
Molar mass of CaCO3 = 100.09 g/mol
Moles of CaCO3 = Mass of CaCO3 / Molar mass of CaCO3
Moles of CO2 = Moles of CaCO3
Volume of CO2 at STP = Moles of CO2 * 22.4 L/mol

Plugging in the values, we get:
Moles of CaCO3 = 5.0 g / 100.09 g/mol = 0.04997 mol
Moles of CO2 = 0.04997 mol
Volume of CO2 at STP = 0.04997 mol * 22.4 L/mol = 1.118 L