What is sodium bicarbonate an example of? a buffer an acid a liquid a base
Answers
Answer:
base
Explanation:
carbonic acid - H2CO3 - is a weak acid. Therefore, HCO3 itself is its conjugate base. The Na(sodium) ion is neutral.
This means that NaHCO3 is a base. (a weak one)
Related Questions
What is the structure of beeswax that contains 16 carbon of carboxylic acid and 30 carbon of alcohol?
ANYONE KNOW THIS ILL GIVE YOU BRAINLIEST..... the question is a variety of energy transformations occur in different situations which statement involves change from chemical to electromagnetic to mechanical to sound energy..... The pic are the answer choices
When an atom of the unstable isotope Na-24 decays, it becomes an atom of Mg-24 because the Na-24 atom spontaneously releases:(1) an alpha particle (2) a beta particle (3) a neutron(4) a positron
Which is the metric root for length?a. gramb. literc. meterd. second
Answers
Methane and ethane demonstrate the law of definite composition and the law of multiple proportions as these both compounds have the exact atoms but in different ratios.
As for methane, it can be seen that every methane molecule contains 4 hydrogen atoms and 1 carbon atom. Where masses of carbon and hydrogen are in ratio - 12 g C / 4 g H -- reduce to 3g C/ 1 g H .
Ethane contains 2 carbon atoms and 6 hydrogen atom and their mass ratio will be - 24 g C / 6 g H -- reduce to 4 g C/ 1 g H .
So both ethane and methane demonstrate the law of definite composition and the law of multiple proportions.
Law of definite composition: The elements which are present in the compound is combined in the same proportion by mass.
Law of multiple proportion: When two or more compounds are formed by the combination of two elements then the mass ratio of one element is combined with the fixed mass of the other element.
In case of methane, it consist of one carbon atoms and four hydrogen atoms implies that has definite composition. In terms of mass, in methane, carbon and hydrogen atoms are combined in a definite ratio i.e. 12 g C/ 4 g H. Thus, methane has definite composition.
Now, carbon and hydrogen combines to give a class i.e. hydrocarbon. In this case, for every constant mass of carbon the ratio of hydrogen will always reduce to 4/3 ratio for the formation of ethane (hydrocarbon). Thus, law of multiple proportion followed.
Similarly, in case of ethane, this compound also consist of exact atoms but in different ratios.
In case of ethane, it consist of two carbon atoms and six hydrogen atoms implies that has definite composition. In terms of mass, in ethane, carbon and hydrogen atoms are combined in a definite ratio i.e. 24 g C/ 6 g H. Thus, methane has definite composition.
Now, carbon and hydrogen combines to give a class i.e. hydrocarbon. In this case, for every constant mass of carbon the ratio of hydrogen will always reduce to a specific ratio for the formation of methane (hydrocarbon). Thus, law of multiple proportion followed.
Answers
Answer: 2Na + 2H₂O → 2NaOH + H₂
According to the equation, 2 moles of Na react with 2 moles of H₂O to produce 1 mole of H₂ gas.
To calculate the number of moles of Na in 120 g, we need to know the molar mass of Na, which is 22.99 g/mol. We can set up a conversion factor:
120 g Na * (1 mol Na / 22.99 g Na) = 5.22 mol Na
Since the reaction ratio is 2 moles of Na to 1 mole of H₂, we can set up another conversion factor:
5.22 mol Na * (1 mol H₂ / 2 mol Na) = 2.61 mol H₂
Now, to convert moles of H₂ to grams of H₂, we need to know the molar mass of H₂, which is 2.02 g/mol. Again, we set up a conversion factor:
2.61 mol H₂ * (2.02 g H₂ / 1 mol H₂) = 5.27 g H₂
Therefore, when 120 g of Na reacts with water, approximately 5.27 grams of hydrogen gas will be produced.
Note: Remember to round your final answer to an appropriate number of significant figures based on the given data.
Explanation:
Final answer:
To find the grams of hydrogen produced, we need to calculate the moles of Na, determine the moles of H2O using the mole ratio, and convert the moles of H2 to grams.
Explanation:
To determine how many grams of hydrogen are produced when 120 g of Na is available, we first need to calculate the moles of Na using its molar mass. Then, we use the balanced chemical equation to determine the mole ratio between Na and H₂O. Finally, we convert the moles of H₂ to grams. Here are the steps:
1. Calculate the moles of Na:
moles of Na = (mass of Na) / (molar mass of Na)
2. Determine the moles of H₂O using the mole ratio:
moles of H₂O = (moles of Na) x (moles of H₂O / moles of Na)
3. Convert the moles of H₂ to grams:
grams of H₂ = (moles of H₂) x (molar mass of H₂)
Using these steps and the given values, we can calculate the grams of hydrogen produced from 120 g of Na.
Learn more about Moles and Stoichiometry here:
#SPJ11
Answers
Answer:1 Liter (L) is equal to 1000 milliliters (mL). To convert liters to mL, multiply the liter value by 1000. For example, to convert 2 liters to mL, multiply 2 by 1000, that makes 2000 mL is 2 L.
Explanation:
b. will be easily separated.
c. lose their own properties.
Answers
(2) pressure (4) chemical energy
Answers
Answer: The correct answer is Option (1).
Explanation:
Average kinetic energy is defined as the average of the kinetic energies that is associated to the particles of the sample which are in random motion.
Temperature is the measure of the average kinetic energy of the particles. Formula used for calculating the average kinetic energy is given by:
where,
K = kinetic energy
R = Gas constant
= Avogadro's constant
T = temperature
Kinetic energy is directly proportional to the temperature of the particle.
As the temperature increases, the kinetic energy of the particles also increases and vice-versa.
Hence, the correct answer is option 1.
Uniform
Heterogeneous
Solutes
Homogenous
Answers
Answer: Heterogenous
Explanation:
A heterogenous mixture is one where the composition of matter is not uniform throughout.
Some examples of heterogenous mixtures include: chocolate chip cookies, salad dressing, strawberry yogurt