MATHEMATICS COLLEGE

50 pts Alessandro wrote the quadratic equation -6=x^2+4x-1 in standard form. What is the value of c in his new equation? c= -6 c= -1 c= 5 c= 7

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation: c on edg

Answer 2

Answer:

Answer: c=5

Step-by-step explanation:

C on edg got 100%

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Subtract breaking apart 143-79

Answers

Step-by-step explanation:

A two-digit number, such as 79, contains a tens place and a ones place.

That is because 79 is also equal to 70 + 9.

The tens place is thus the 7, since since 7 × 10 = 70

and the ones place is the 9.

So lets Subtract breaking apart 143 - 79.

Break 79 down into its parts:

70 + 9.

Subtract 70 from the original number:

143 - 70 = 73

Subtract 9 from the answer:

73 - 9 = 64

Therefore, 64 is the final answer.

What is the 100th term in the pattern with the formula n+7

Answers

To find it, put 100 where n is in the formula and evaluate
.. n + 7
for n = 100
.. 100 +7
.. = 107

The 100th term is 107.

Which one of these transformations move by sliding in any direction?A.Translation
B.Rotation
C.Reflection
D.Dilation

Answers

Answer:

D. Dilation, sorry if i'm wrong ;)

Step-by-step explanation:

Solve for x
Logx-log(x+13)=1

Step by step explanation please

Answers

Answer:

Step-by-step explanation:

Applying logarithm rule

Log A - Log B= Log(A/B). Division rule

Now, Logx-log(x+13)=1

Log(x/(x+13))=1

Assume that the log is a natural log whose base is 10.

Then apply logarithm law

Log10 base 10=1

Comparing this to Log(x/(x+13))=1

This implies that

x/(x+13)=10

x=10(x+13)

x=10x+130

x-10x=130

-9x=130

x=130/-9

x=-14.444

The perimeter of a rectangular field is 74 yards. The length of the field is 27 yards. What is the width in yard of the field

Answers

The width of the yard whose length is 27 yards and perimeter is 74 yards is evaluated to be 10 yards

How to find the perimeter of a rectangle?

For a rectangle with length and width L and W units, we get:

Perimeter of the rectangle = $2(L + W) \: \rm units$

For this case, let we assume that:

The width of the considered rectangular field = W yards

Then, as we're provided that:

Perimeter of the rectangular field = 74 yards
Length of the rectangular field = 27 yards.

Putting these in the formula for perimeter of a rectangle, we get;

$Perimeter = 2( L + W)\n74 = 2(27 + W)\n\n\text{Dividing both the sides by 2}\n\n(74)/(2) = (2(27+W))/(2)\n\n37 = 27 + W\n\n\text{Subtracting 27 from both the sides}\n\n37 - 27 = W\nW = 10 \: \rm yards$

Thus, the width of the yard whose length is 27 yards and perimeter is 74 yards is evaluated to be 10 yards

Learn more about perimeter of a rectangle here:

brainly.com/question/14073514

Answer:

width = 10 yds

Step-by-step explanation:

perimeter = 2L + 2W

74 = 2(27) + 2W

74 = 54 + 2W

subtract 54 from both sides of the equation:

2W = 20

divide both sides by 2:

W = 10

A preliminary sample of holiday shoppers revealed that the standard deviation of the amount of money they are planning to spend on gifts during the coming holiday season is $80. How many holiday shoppers should be sampled in order to estimate the average amount of money spent on gifts by all holiday shoppers with a margin of error of $7 and with a 99% confidence

Answers

Answer:

$n=((2.58(80))/(7))^2 =869.407 \approx 870$

So the answer for this case would be n=870 rounded up to the nearest integer

Step-by-step explanation:

Information given

$\sigma = 80$ represent the deviation

ME = 7 represent the margin of error

Solution

The margin of error is given by this formula:

$ME=z_(\alpha/2)(\sigma)/(√(n))$ (a)

And on this case we have that ME =7 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=((z_(\alpha/2) \sigma)/(ME))^2$ (b)

The critical value for 99% of confidence interval now can be founded using the normal distribution. The significance level would be $\alpha=0.01$ and $\alpha/2 =0.05$ . The critical value would be $z_(\alpha/2)=2.58$ , replacing into formula (b) we got:

$n=((2.58(80))/(7))^2 =869.407 \approx 870$

So the answer for this case would be n=870 rounded up to the nearest integer

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