MATHEMATICS COLLEGE

9+9+3=21
1234+1234+1234= 30
9+1224+12=?

Answers

Answer 1
Answer:

Answer:

Mathematically,

9+1224+12 = 1245

But, Logically, here:

9+1224+12 = 21
Answer 2
Answer:

Answer:

9+1224+12=1245

Hope this helps

Related Questions

PLEASE ANSWER THIS QUESTION
-17 irrational number
Suppose you read online that children first count to 10 successfully when they are 32 months old, on average. You perform a hypothesis test evaluating whether the average age at which gifted children first count to 10 is different than the general average of 32 months. What is the p-value of the hypothesis test? Choose the closest answer.
Help me an plz dont put links while answering question
Assume a significance level ofα=0.05and use the given information to complete parts​ (a) and​ (b) below.Original​ claim:LessLessthan51​%of adults would erase all of their personal information online if they could. The hypothesis test results in a​ P-value of0.0148a. State a conclusion about the null hypothesis.​ (RejectUpper H 0H0or fail to rejectUpper H 0H0​.)Choose the correct answer below.A.RejectRejectUpper H 0H0because the​ P-value isless than or equal toless than or equal toalphaα.B.RejectRejectUpper H 0H0because the​ P-value isgreater thangreater thanalphaα.C.Fail to rejectFail to rejectUpper H 0H0because the​ P-value isgreater thangreater thanalphaα.D.Fail to rejectFail to rejectUpper H 0H0because the​ P-value isless than or equal toless than or equal toalphaα.b. Without using technical​ terms, state a final conclusion that addresses the original claim. Which of the following is the correct​ conclusion?A.The percentage of adults that would erase all of their personal information online if they could islesslessthan or equal to51​%.B.Thereisissufficient evidence to support the claim that the percentage of adults that would erase all of their personal information online if they could ismoremorethan51​%.C.The percentage of adults that would erase all of their personal information online if they could ismoremorethan51​%.D.Thereis notis notsufficient evidence to support the claim that the percentage of adults that would erase all of their personal information online if they could ismoremorethan51​%.

16x - 10y = 10
-8x - 6y = 6

Answers

Answer:

x=0 y=-1

Step-by-step explanation:

16x-10y=10

-8x-6y=6 *2  -16x-12y=12

16x-10y=10

-16x-12y=12

-22y=22 Add it together

y=-1

-8x-(6*(-1))=6

-8x+6=6

x=0

Bryan is a hotel manager.his salary is 7500. Every year his salary increases by 150 what will be his salary in 5 years

Answers

Answer:

Just add

8250

Step-by-step explanation:

5 x 150 = 750

then add that to 7500 = 8250

Help PLEASE!!!!!!!If BD bisects angle ABC, measure of DBC = 79 degrees, and measure of angle ABC= 9x-4, find the value of x.

Answers

The answer is 2^4 + 2 - 3 ^ 9 / 3^ 8 + 3

Determine the ration of the geometric sequence 1/10, -1/2, 5/2

Answers

Answer:

-5

Step-by-step explanation:

We just have to calculate (-1/2) / (1/10) = (-1/2) * 10 = -5.

True or False: The height is always twice the length of tue base edge of any triangular pyramid.

Answers

Answer:

true

Step-by-step explanation:

3n3n3p0mdo98rueu33

Heights of women (in inches) are approximately N(64.5,2.5) distributed. Compute the probability that the average height of 25 randomly selected women will be bigger than 66 inches.

Answers

Answer:

the probability that the average height of 25 randomly selected women will be bigger than 66 inches is 0.0013

Step-by-step explanation:

From the summary of the given statistical dataset

The mean and standard deviation for the sampling distribution of sample mean of 25 randomly selected women can be calculated as follows:

\mu_(\overline x) = \mu _x = 64.5

\sigma_(\overline x )= (\sigma)/(\sqrt n)

\sigma_(\overline x )= \frac{2.5}{\sqrt {25}}

\sigma_(\overline x )= (2.5)/(5)

\sigma_(\overline x ) = 0.5

Thus X \sim N (64.5,0.5)

Therefore, the probability that the average height of 25 randomly selected women will be bigger than 66 inches is:

P(\overline X > 66) = P ( (\overline X - \mu_\overline x)/(\sigma \overline x )>(66 - 64.5)/(0.5) })

P(\overline X > 66) = P ( Z>(66 - 64.5)/(0.5) })

P(\overline X > 66) = P ( Z>(1.5)/(0.5) })

P(\overline X > 66) = P ( Z>3 })

P(\overline X > 66) = 1- P ( Z<3 })

P(\overline X > 66) = 1- 0.9987

P(\overline X > 66) =0.0013

the probability that the average height of 25 randomly selected women will be bigger than 66 inches is 0.0013
Other Questions
Give a ballpark estimate of the number of seats in a typical major league ballpark
How do i simplify 81^5 = 3x
The length of a rectangular field is 4 m longer than its breadth. If the perimeter of the field is 44 m calculate:i) breadthii) the area of the field
To graph the function g(x) = (x – 5)2 – 9, shift the graph of f(x) = x2 5 units and 9 units.