A ball rolls with a speed of 4.0 m/s across a level table that is 1.0 m above the floor. Upon reaching the edge of the table, itfollows a parabolic path to the floor. How many meters along the floor is the landing spot from the table?

Answers

Answer 1
Answer:

Answer: 1.81m

Explanation:

Given the following:

Horizontal speed = 4m/s

Height of table = 1m

Taking the vertical component of the motion:

Using:

S = ut + 0.5 at^2

Where, S = height of table, a = acceleration due to gravity (9.8m/s^2), t = time and u = Initial Velocity in vertical direction = 0

1 = 0(t) + 0.5(9.8)t^2

1 = 4.9t^2

t^2 = 1 / 4.9

t^2 = 0.204081

t = sqrt(0.204081)

t = 0.452s

For Horizontal :

Gravitational acceleration is absent, therefore distance can be calculated using:

Distance = Velocity × time

Distance = 4m/s × 0.452s

Distance = 1.808 m

Distance = 1.81m


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Answers

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Answers

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Gravitational potential energy is an energy acquired by an object due to a change in its height when it is present in a gravitationalfield. It is denoted by P or U. and it its expressed in joule.  Gravitational potential energy is given by U = mgh where m is the mass of the object, g is acceleration due to gravity and h is the height.

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Answers

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Answers

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Answers

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