MATHEMATICS HIGH SCHOOL

We are given with height= 9 ft. Length=10 ft. Wall Brackets: 48-inch cost $12.95 68-inch cost $16.95 Distance from brackets from ends= 1 foot maximum . What is the total cost of the brackets, before tax?

Answers

Answer 1

Answer:

Answer:

$89.7

Step-by-step explanation:

We are given with

height = 9 feet

length = 10 feet

wall brackets:

48-in costing $12.95

60-in costing $16.95

distance of brackets from ends = 1 foot

maximum distance between brackets= 24 inches

The brackets are

48/12 = 4 feet

and

60/12 = 5 feet

One of each must be used to cover the height of the shelf

The length of the shelf is

60 inch

subtracting 1 in from each side for the allowance

60 - 2 = 58 in

Dividing by 24 inches

58/24 = 2.41 ~ 3

The total cost is

($12.95 + $16.95) * 3 = $89.7

The total cost of the brackets is $89.7

Related Questions

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The _______ is used to express absolute temperatures in the English system of measurement. A. Fahrenheit scale B. Rankine scale C. Celsius scale D. Kelvin scale
How tall is the table?
Please give an explanation

The following data show the height, in inches, of 11 different plants in a garden: 9 4 10 9 5 2 22 10 3 3 5 After removing the outlier, what does the mean absolute deviation of this data set represent?

Answers

The outlier is the obviously different data among the whole group of data points. In this case, the outlier is 22. When you find the mean, you only use the data points without the outlier. Therefore,

Mean = (9+4+10+9+5+2+10+3+3+5)/10 = 6

Then, the mean absolute deviation is

∑(x-mean)^2/n, where x is every single data point and n is the number of data points which is equal to 10

|9-6|+|4-6|+|10-6|+|9-6|+|5-6|+|2-6|+|10-6|+|3-6|+|3-6|+|5-6| = 28

Then,

Mean Absolute Deviation (MAD) = 28/10 = 2.8

This is the average distance of the data from the mean.

Answer:

I took the test, it is On average, the height of a plant varies 2.8 inches from the mean of 6 inches.

Step-by-step explanation:

Let W be a point between points U and V on . If UV = 13, UW = 2y – 9, and WV = y – 5, solve for y.

Answers

Answer:

The value of y is 9.

Step-by-step explanation:

Given : W be a point between points U and V also, UV = 13, UW = 2y – 9, and WV = y – 5

We have to solve for y.

Since, W is a point between points U and V .

Then distance of point W from U and distance of point from V is equal to the distance of UV.

Then, UW + WV = UV

Substitute , the values, we get,

Then 2y – 9 + y – 5 = 13

Solving for y , we get,

⇒ 3y - 14 = 13

⇒ 3y = 13 + 14

⇒ 3y = 27

⇒ y = 9

Thus, the value of y is 9.

you would do 9/2
9/2=4.5
2*4.5=9

A rectangle measure 11cm by 30cm.What is its area

Answers

well, 11*30 is equal to 330cm

330 cm. Area=11cm*30cm

Sammy owes his landlord $200 for rent and $30.45 for his portion of the utilities. Write an expression to represent the total amount that Sammy owes, and then find the amount.

Answers

Answer:

Expression: 200+30.45=x

Answer: 230.45

Step-by-step explanation:

Just add them together

Answer

Sammy owes $230.45.

Step-by-step explanation:

By total amount, they meant everything so $200 + $30.45 is really easy here. Just add them together! $200 + $30.45 = $230.45. That is your answer now have a good day my beautiful friends.

Help with line equations?

Answers

First question

$line:~~~~y=x+3$

$curve:~~~~x^2+y^2=29$

now we have to replace the y of curve by the y of line, therefore

$x^2+(x+3)^2=29$

$x^2+x^2+6x+9=29$

$2x^2+6x+9-29=0$

$2x^2+6x-20=0$

we can multiply each member by $(1)/(2)$

$\boxed{\boxed{x^2+3x-10=0}}$

Now we have to find the roots of this funtion

$x^2+3x-10=0$

Sum and produc or Bhaskara

Then we find two axis

$\boxed{x_1=2~~and~~x_2=-5}$

now we replace this values to find the Y, we can replace in curve or line equation, I'll prefer to replace it in line equation.

$y=x+3$

$y_1=x_1+3$

$y_1=2+3$

$\boxed{y_1=5}$

$y_2=x_2+3$

$y_2=-5+3$

$\boxed{y_2=-2}$

Therefore

$\boxed{\boxed{P_1(2,5)~~and~~P_2(-5,-2)}}$
_______________________________________________________________

The second question give to us

$y=ax+b$

$P_1(2,13)$

$P_2(-1,-11)$

We just have to replace the value then we'll get a linear system.

point 1

$13=2a+b$

point 2

$-11=-a+b$

then our linear system will be

$\begin{Bmatrix}2a+b&=&13\n-a+b&=&-11\end{matrix}$

I'll multiply the second line by -1 and I'll add to first one

$\begin{Bmatrix}2a+(a)+b+(-b)&=&13+(-11)\n-a+b&=&-11\end{matrix}$

$\begin{Bmatrix}3a&=&24\n-a+b&=&-11\end{matrix}$

$\begin{Bmatrix}a&=&8\n-a+b&=&-11\end{matrix}$

therefore we can replace the value of a, at second line

$\begin{Bmatrix}a&=&8\n-8+b&=&-11\end{matrix}$

$\begin{Bmatrix}a&=&8\nb&=&-11+8\end{matrix}$

$\boxed{\boxed{\begin{Bmatrix}a&=&8\nb&=&-3\end{matrix}}}$

then our function will be

$\boxed{\boxed{y=8x-3}}$

_________________________________________________________________

The third one, we have

$line:~~~~y=3x-4$

$curve:~~~~y=x^2-2x-4$

This resolution will be the same of our first question.

Let's replace the y of curve by the y of line

$3x-4=x^2-2x-4$

$0=x^2-2x-4-3x+4$

therefore

$\boxed{\boxed{x^2-5x=0}}$

now we have to find the roots of this function.

$x^2-5x=0$

put x in evidence

$x*(x-5)=0$

$\boxed{x_1=0~~and~~x_2=5}$

then

$y=3x-4$

$y_1=3x_1-4$

$y_1=3*0-4$

$\boxed{y_1=-4}$

$y_2=3x_2-4$

$y_2=3*5-4$

$y_2=15-4$

$\boxed{y_2=11}$

our points will be

$\boxed{\boxed{P_1(0,-4)~~and~~P_2(5,11)}}$

I hope you enjoy it ;)

To make curtains for a living room window for a customer, you will need three pieces of fabric in the following lengths: 3 feet, 3 feet, and 5 feet. What is the total length of fabric you will need? A. 8

Answers

Total length of fabric is: 3 + 3 + 5 = 11 feets

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