MATHEMATICS HIGH SCHOOL

Anybody know the answer ? Please help :(

Answers

Answer 1

Answer:

Answer:

A. y= -2x+6

Step-by-step explanation:

The intercept is at 6, to make the line, you go down 2, over 1.

// have a great day //

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If log28 = log4 +logx what is the value of x

Answers

log4 + logx = log4x 4x = 28 x = 7
Easy cheesy! :) hope I helped. all you had to do is to divide 28/4 which is 7x

Find value 40% of 25 is what number?

Answers

40% from 25 is:

25 * 40% =
= 25 * 40/100 =
= 25 * 4/10 =
= 25 * 0,4 =
= 10

Another way is to find 1% of 25 and then multiply it by 40:

25 * 40% =
= (25 / 100) * 40 =
= 0,25 * 40 =
= 10

If (x + 5)^2 = 35, what is the approximate positive value of x?0.92
2.65
3.16
5.48

Answers

Answer:

The approximate positive value of x is 0.92.

Step-by-step explanation:

Given,

$(x+5)^2 = 35$

$x+5 = \pm √(35)$

$x = \pm √(35)-5$

Thus,

$x = √(35)-5$ or $x=-√(35)-5$

By taking positive value,

$x = √(35)-5$

$x=5.91607978 - 5 = 0.91607978\approx 0.92$

⇒ First option is correct.

the approximate value of x = 0.92

Ex 3.7
12. find the area between the curve y=x³-2 and the y-axis between y= -1 and y=25

Answers

$y=x^3-2\nx^3=y+2\nx=\sqrt[3]{y+2}\n\n\int \limits_(-1)^(25)\sqrt[3]{y+2}\, dy=\n\int \limits_(-1)^(25)(y+2)^{\tfrac{1}{3}}\, dy=\n\left[\frac{(y+2)^{\tfrac{4}{3}}}{(4)/(3)} \right]_(-1)^(25)=\n$
$\left[(3)/(4)(y+2)^{\tfrac{4}{3}} \right]_(-1)^(25)=\n\left[(3)/(4)(y+2)\sqrt[3]{y+2} \right]_(-1)^(25)=\n(3)/(4)(25+2)\sqrt[3]{25+2}-\left((3)/(4)(-1+2)\sqrt[3]{-1+2}\right)=\n(3)/(4)\cdot27\sqrt[3]{27}-\left((3)/(4)\sqrt[3]{1}\right)=\n(3)/(4)\cdot27\cdot3-(3)/(4)=\n(3)/(4)(81-1)=\n(3)/(4)\cdot 80=\n3\cdot20=\n60$

Yeah, you'd have to use the inverse function to produce this result.

Let's get the inverse function first:

$y={ x }^( 3 )-2\n \n { x }^( 3 )=y+2\n \n x=\sqrt [ 3 ]{ y+2 }$

$\n \n \therefore \quad { f }^( -1 )\left( x \right) =\sqrt [ 3 ]{ x+2 }$

Now, we can solve the problem using:

$\int _( -1 )^( 25 ){ \sqrt [ 3 ]{ x+2 } } dx$

But to solve the problem more easily we make u=x+2, therefore du/dx=1, therefore du=dx.

When x=25, u=27.

When x=-1, u=1.

Now:

$\int _( 1 )^( 27 ){ { u }^{ \frac { 1 }{ 3 } } } du\n \n ={ \left[ \frac { 3 }{ 4 } { u }^{ \frac { 4 }{ 3 } } \right] }_( 1 )^( 27 )$

$\n \n =\frac { 3 }{ 4 } \cdot { 27 }^{ \frac { 4 }{ 3 } }-\frac { 3 }{ 4 } \cdot { 1 }^{ \frac { 4 }{ 3 } }\n \n =\frac { 3 }{ 4 } { \left( { 3 }^( 3 ) \right) }^{ \frac { 4 }{ 3 } }-\frac { 3 }{ 4 }$

$\n \n =\frac { 3 }{ 4 } \cdot { 3 }^( 4 )-\frac { 3 }{ 4 } \n \n =\frac { 3 }{ 4 } \left( { 3 }^( 4 )-1 \right)$

$\n \n =\frac { 3 }{ 4 } \cdot 80\n \n =60$

Answer: 60 units squared.

When you graph an inequality, you used a closed dot when you use which
symbols?

Answers

You should only use a closed dot for the symbols ≤ and ≥.

When you should use a closed dot?

There are two types of dots used when graphing inequalities, closed and open.

We use closed dots when the value where the dot is, is a solution.
We use open dots when the velue where the dot is, is not a solution.

So, for exampe in:

x > 3.

We would put an open dot at 3, because the value x = 3 is not a solution, but all the values at the right of the 3 are solutions.

In the other hand, for:

x ≥ 3

Now 3 is in fact a solution, so here we should use a closed dot.

Then, answering the question.

"When you graph an inequality, you used a closed dot when you use which symbols?"

The ≤ and ≥ symbols.

If you want to learn more about inequalities, you can read:

brainly.com/question/11234618

You use a closed dot with the greater than or less than with the line under the symbol or the greater than or equal to or the less than or equal to symbols. The line indicates a closed dot.

Find a value for k such that the following trinomial can be factored x^2-8x+k

Answers

Answer:

Step-by-step explanation:

x^2-8x+k is a quadratic expression of the form ax^2 + bx + c. Here a = 1, b = -8 and c = k. Focus on x^2-8x and complete the square as follows: Take half of the coefficient of x (that is, take half of -8) and square the result:

(-4)^2 = 16; if we now write x^2-8x+ 16, we'll have the square of (x - 4): (x -4)^2.

Thus, k = 16 turns x^2-8x+k into a perfect square.

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