Suppose a fast-pitch softball player does a windmill pitch, moving her hand through a circular arc with her arm straight. She releases the ball at a speed of 25.5 m/s (about 57.0 mph ). Just before the ball leaves her hand, the ball's radial acceleration is 1060 m/s2 . What is the length of her arm from the pivot point at her shoulder

Answer: 132.02 J

Explanation:

By definition, the kinetic energy is written as follows:

KE = 1/2 m v²

In our question, we know from the question, the following information:

m = 0.1434 Kg

v= 42.91 m/s

Replacing in the equation for KE, we have:

KE = 1/2 . 0.1434 Kg. (42.91)² m²/s² ⇒ KE = 132.02 N. m = 132.02 J

Answer:

Explanation:

object distance u = 38.5 cm ( negative )

focal length f = 17.5 cm ( negative )

mirror formula

1 / v + 1 / u = 1 / f

1 / v - 1 / 38.5 =  - 1 / 17.5

1 / v = -  1 / 17.5 + 1 / 38.5

= - 0 .03116

v = - 1 / .03116 = - 32 cm

Image will be formed in front of the mirror at 32 cm distance .

Final answer:

A pressure antinode in a sound wave is indeed a region of high pressure, while a pressure node is a region of low pressure. These definitions hold true for all types of waves.

Explanation:

That's true. In terms of sound waves, a pressure antinode is a region of high pressure, while a pressure node is a region of low pressure. This is true for all types of waves, not only sound waves. In essence, a wave moves through a medium (in case of a sound wave, that medium is typically air) by creating areas of high and low pressure - the high pressure areas are called antinodes, and the low pressure areas are called nodes.

Learn more about Sound Waves here:

brainly.com/question/31375531

#SPJ2

the final velocity of the apple after the collision is approximately 0.758m/s in the positive x-direction.

To solve this problem, we can use the principle of conservation of linear momentum. The total momentum before the collision should equal the total momentum after the collision.

Let's set up our coordinate system with the x-axis pointing to the right and the y-axis pointing upward. Astronaut 1 is tossing the apple in the positive x-direction, so the velocity of the apple (v1) will be positive. Astronaut 2 is tossing the orange in the negative x-direction, so the velocity of the orange (v2) will be negative.

The conservation of linear momentum equation is as follows:

m1∗v1+m2∗v2=m1∗vf1+m2∗vf2

Where:

m1 is the mass of the apple (0.110 kg)

v1 is the initial velocity of the apple (1.13 m/s)

m2 is the mass of the orange (0.150 kg)

v2 is the initial velocity of the orange (−1.25 m/s, as it's in the negative x-direction)

vf1 is the final velocity of the apple (which we need to find)

vf2 is the final velocity of the orange (−0.977 m/s)

Now, we can plug in these values and solve for vf1:

0.110kg∗1.13m/s+0.150kg∗(−1.25m/s)=0.110kg∗vf1+0.150kg∗(−0.977m/s)

0.1243kg∗m/s−0.1875kg∗m/s=0.110kg∗vf1−0.14655kg∗m/s

Now, let's isolate vf1:

0.1243kg∗m/s−0.1875kg∗m/s+0.14655kg∗m/s=0.110kg∗vf1

0.0834kg∗m/s=0.110kg∗vf1

Now, divide by 0.110kg to find vf1:

vf1=0.0834kg∗m/s/0.110kg=0.758m/s

So, the final velocity of the apple after the collision is approximately 0.758m/s in the positive x-direction.

Learn more about Collision of objects in space here:

brainly.com/question/39955305

#SPJ3

Answer:

The speed and direction of the apple is 1.448 m/s and 66.65°.

Explanation:

Given that,

Mass of apple = 0.110 kg

Speed = 1.13 m/s

Mass of orange = 0.150 kg

Speed = 1.25 m/s

Suppose we find the final speed and direction of the apple in this case

Using conservation of momentum:

Before:

In x direction,

In y direction = 0

After:

is velocity of the apple in the y direction

is the velocity of the apple in the x direction

Momentum again:

In x direction,

In y-direction,

We need to calculate the speed of apple

Put the value into the formula

We need to calculate the direction of the apple

Using formula of angle

Put the value into the formula

Hence, The speed and direction of the apple is 1.448 m/s and 66.65°.

The definition of standing wave and trigonometry allows to find the results for the questions about the waves are:

      1. For the standing wave its parts are: spatial  and

         temporal part

      2. The string moves with an oscillating motion  y = A’ cos wt.

      3. Thefirst displacement is zero for    

      4. the correct result is:

          A. The wave is traveling in the +x direction.

      5. The correct result is:

          D. Asin(kx+ωt)

Traveling waves are periodic movements of the media that transport energy, but not matter, the expression to describe it is:

       y₁ = A sin (kx -wt)

Where A is the amplitude of the wave k the wave vector, w the angular velocity and x the position and t the time.

1. Ask us to find the spatial and temporal part of the standing wave.

To form the standing wave, two waves must be added, the reflected wave is:

       y₂ = A sin (kx + wt)

The sum of a waves

       y = y₁ + y₂

       y = A (sin kx-wt + sin kx + wt)

We develop the sine function and add.

       Sin (a ± b) = sin a cos b ± sin b cos a

The result is:

       y = 2A sin kx cos wt

They ask that the function be unitary therefore

The amplitude  of each string

        A_ {chord} = A_ {standing wave} / 2

The spatial part is

          = A 'sin kx

The temporary part is:

          = A ’cos wt

2. At position x = 0, what is the displacement of the string?

          y = A ’cos wt

The string moves in an oscillating motion.

3. At what point the string is straight.

When the string is straight its displacement is zero x = 0, the position remains.

           y = A ’cos wt

For the amplitude of the chord to be zero, the cosine function must be zero.

           wt = (2n + 1)  

the first zero occurs for n = 0

          wt =  

           t =

4) The traveling wave described in the statement is traveling in the positive direction of the x axis, therefore the correct statement is:

         A. The wave is traveling in the +x direction.

5) The wave traveling in the opposite direction is

            y₂ = A sin (kx + wt)

The correct answer is:

            D.     Asin(kx+ωt)

In conclusion using the definition of standing wave and trigonometry we can find the results for the questions about the waves are:

     1. For the standing wave its parts are: spatial  and

         temporal part

      2. The string moves with an oscillating motion  y = A’ cos wt.

      3. Thefirst displacement is zero for    

      4. the correct result is:

          A. The wave is traveling in the +x direction.

      5. The correct result is:

          D. Asin(kx+ωt)

Learn more about standing waves here:  brainly.com/question/1121886