MATHEMATICS MIDDLE SCHOOL

Compute the permutations and combinations. 10C10 10 0 1

Answers

Answer 1

Answer:

Answer:

wait plse

Step-by-step explanation:

i know the answere i am quite busy will answer u later

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Show how to write 0.1313... as a fraction.

Answers

Answer:

13/99

Step-by-step explanation:

13/99

you can always just put the recurring part over the corresponding amounts of 9

for example the recurring part is 2 digits so then there would be 2 9's (99)

idk i hope that makes sense

This should help with the question that you asked

Kevin can travel 22 1/2 miles and one third of an hour what is his average speed in miles per hour

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22.5 * 3 = 67.5

67.5 mph

Complete the table of values

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Both problems give you a function in the second column and the x-values. To find out the values of a through f, you need to plug in those x-values into the function and simplify!

You need to know three exponent rules to simplify these expressions:
1) The negative exponent rule says that when abase has a negative exponent, flip the base onto the other side of thefraction to make it into a positive exponent. For example, $3^(-2) =(1)/(3^(2) )$ .
2) Raising a fraction to a power is the same as separately raising the numerator and denominator to that power. For example, $((3)/(4)) ^(3) = ( 3^(3) )/(4^(3) )$ .
3) The zero exponent rule says that any numberraised to zero is 1. For example, $3^(0) = 1$ .

Back to the Problem:
Problem 1
The x-values are in the left column. The title of the right column tells you that the function is $y = 4^(-x)$ . The x-values are:
1) x = 0
Plug this into $y = 4^(-x)$ to find letter a:
$y = 4^(-x)\ny = 4^(-0)\ny = 4^(0)\ny = 1$

2) x = 2
Plug this into $y = 4^(-x)$ to find letter b:
$y = 4^(-x)\n y = 4^(-2)\n y = (1)/(4^(2)) \n y= (1)/(16)$

3) x = 4
Plug this into $y = 4^(-x)$ to find letter c:
$y = 4^(-x)\n y = 4^(-4)\n y = (1)/(4^(4)) \n y= (1)/(256)$

Problem 2
The x-values are in the left column. The title of the right column tells you that the function is $y = ((2)/(3))^x$ . The x-values are:
1) x = 0
Plug this into $y = ((2)/(3))^x$ to find letter d:
$y = ((2)/(3))^x\ny = ((2)/(3))^0\ny = 1$

2) x = 2
Plug this into $y = ((2)/(3))^x$ to find letter e:
$y = ((2)/(3))^x\n y = ((2)/(3))^2\n y = (2^2)/(3^2)\ny = (4)/(9)$

3) x = 4
Plug this into $y = ((2)/(3))^x$ to find letter f:
$y = ((2)/(3))^x\n y = ((2)/(3))^4\n y = (2^4)/(3^4)\n y = (16)/(81)$

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Answers:
a = 1
b = $(1)/(16)$
c = $(1)/(256)$
d = 1
e = $(4)/(9)$
f = $(16)/(81)$

The sales price for a DVD player was $89. After tax, Jenna paid a total of $95.46. Write and solve and equation to find the amount of the tax.

Answers

95.46 = 89 +T
**subtract 89 from both sides
$6.46 = T

Find an equation in standard form for the hyperbola with vertices at (0, ±4) and asymptotes at y = ±1 divided by 3.x.

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The transverse axis is parallel to the y-axis (the positive part of this equation.
(h, k) is the center ... (0, 0)
a = distance from the center to the vertices along the transverse axis
b = distance from the center to the endpoints of the conjugate axis
c = distance from the center to the foci along the transverse axis
Given: a = 10
The relationship between a, b, and c is
10² + b² = c²

The slope of the asymptotes is ±5/4
a = is a multiple of 5
b = is a multiple of 4 ... be careful not to always assume that a=5 and b = 4.
For this problem a = 10
hence, b = 8

10² + 8² = c²
164 = c²
2√41 = c

Summary
center = (0, 0)
a² = 100
b² = 64
c² = 164
transverse axis x = 0
equation of the hyperbola

[y²/10²] - [x²/8²] = 1

Remember, the slope of the asymptotes tell you the ratio of a and b, and not necessarily the actual values of a and b.

I hope this helps!

Answer:

y^2/16 - x^2/36 = 1

3x + 7y =47
-4x +7y =19

Answers

3x+7y=47
-1(-4x+7y=19)

Distribute the -1 and add the equations together...you'll get:

7x=28
x=4

Plug X=4 back in...
12+7y=47
7y=35
y=5

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