CHEMISTRY COLLEGE

You have a copper cylinder at room temperature (20ºC). You find that the diameter of the copper cylinder is 3.52 cm and the mass of the cylinder is 94.6754 g. What is the length (h) of the copper cylinder in mm? The density of copper is 8.96 g/cm3. (2 points) 4. You

Answers

Answer 1

Answer:

Answer:

10.8 mm

Explanation:

Step 1: Calculate the volume (V) of the copper cylinder

The cylinder has a mass of 94.6754 g and a density of 8.96 g/cm³. The volume of the cylinder is:

$94.6754 g * (1cm^(3) )/(8.96g) = 10.6 cm^(3)$

Step 2: Calculate the length (h) of the copper cylinder

The diameter (d) of the copper cylinder is 3.52 cm. We can calculate the length using the following expression.

$V = \pi * ((d)/(2))^(2) * h\nh = (4V)/(\pi * d^(2) ) = (4(10.6cm^(3) ))/(\pi * (3.52cm)^(2) ) = 1.08 cm$

Step 3: Convert the length to millimeters

We will use the relationship 1 cm = 10 mm.

$1.08cm * (10mm)/(1cm) = 10.8 mm$

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The following data is given to you about a reaction you are studying: Overall reaction: 2A  D Proposed mechanism: Step 1 A + B  C (slow) Step 2 C + A  D + B (fast) [A]o = 0.500 M [B]o = 0.0500 M [C]o = 0.500 M [D]o = 1.50 M This reaction was run at a series of temperatures and it was found that a plot of ln(k) vs 1/T (K) gives a straight line with a slope of -982.7 and a Y intercept of -0.0726. What is the initial rate of the reaction at 298K?

Answers

Answer : The initial rate of the reaction at 298 K is, $8.6* 10^(-4)M/s$

Explanation :

The Arrhenius equation is written as:

$K=A* e^{(-Ea)/(RT)}$

Taking logarithm on both the sides, we get:

$\ln k=-(Ea)/(RT)+\ln A$ ............(1)

where,

k = rate constant

Ea = activation energy

T = temperature

R = gas constant = 8.314 J/K.mole

A = pre-exponential factor

The equation (1) is of the form of, y = mx + c i.e, the equation of a straight line.

Thus, if we plot a graph of $\ln k$ vs $(1)/(T)$ then the graph shows a straight line with negative slope. That means,

Slope of the line = $-(Ea)/(R)$

And,

Intercept = $\ln A$

As we are given that:

Slope of the line = -982.7 = $-(Ea)/(R)$

Intercept = -0.0726 = $\ln A$

Now we have to calculate the value of rate constant by putting the value of slope, intercept and temperature (298K) in equation 1, we get:

$\ln k=-(982.7)/(298)+(-0.0726)$

$\ln k=-3.37$

$k=0.0344s^(-1)$

The value of rate constant is, $0.0344s^(-1)$

Now we have to calculate the initial rate of the reaction at 298 K.

As we know that the slow step is the rate determining step. So,

The slow step reaction is,

$A+B\rightarrow C$

The expression of rate law for this reaction will be,

$Rate=k[A][B]$

As we are given that:

[A] = 0.500 M

[B] = 0.0500 M

k = $0.0344s^(-1)$

Now put all the given values in the rate law expression, we get:

$Rate=(0.0344)* (0.500)* (0.0500)$

$Rate= 8.6* 10^(-4)M/s$

Therefore, the initial rate of the reaction at 298 K is, $8.6* 10^(-4)M/s$

Calculate the mass of the air contained in a room that measures 2.50 m × 5.50 m × 3.00 m (density of air = 1.29 g/dm3 at 25°C).

Answers

The mass of air in room as per given density is 53.2 kg.

To calculate the mass of air contained in a room, we can use the formula:

mass = density x volume

Here, the given density of air is 1.29 g/dm³ at 25°C. We can convert the dimensions of the room to decimeters (dm) by multiplying by 10:

Length = 2.50 m × 10 = 25 dm

Width = 5.50 m × 10 = 55 dm

Height = 3.00 m × 10 = 30 dm

Now, we can calculate the volume of the room by multiplying the three dimensions:

Volume = length x width x height

Volume = 25 dm x 55 dm x 30 dm

Volume = 41,250 dm³

Finally, we can use the formula to calculate the mass of air:

mass = density x volume

mass = 1.29 g/dm³ x 41,250 dm³

mass = 53,212.5 g or 53.2 kg

Therefore, the mass of air contained in the room is approximately 53.2 kg.

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Explanation:

please mark me as brainlest

If two or more elements or chemical compounds come into contact with one another and there is enough __________ present, a chemical change may take place.

Answers

Final answer:

A chemical change or reaction between elements or compounds may occur when there is enough energy present. This can be in the form of heat, light, or electricity. An example of this is the reaction between hydrogen and oxygen to form water, which requires a spark.

Explanation:

If two or more elements or chemical compounds come into contact with one another and there is enough energy present, a chemical change may take place. This is because a chemical reaction, which represents a chemical change, requires energy to break the bonds of the reactants and form new bonds in the products. This energy can be in various forms such as heat, light, or electricity.

For example, the reaction between hydrogen and oxygen to form water is a chemical change that requires energy in the form of a spark. On the other hand, an exothermic reaction, such as the combustion of gasoline, releases energy in the form of heat and light.

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Answer:

energy

Explanation:

"If two or more elements or chemical compounds come into contact with one another and there is enough energy present, a chemical change may take place." this was on a science lesson, it's correct.

A disaccharide forms when: two monosaccharides join by dehydration synthesis. two starches join by hydrolysis. two starches join by dehydration synthesis. a starch and a monosaccharide join by dehydration synthesis. two monosaccharides join by hydrolysis.

Answers

Answer:

two monosaccharides join by dehydration synthesis

Explanation:

A disaccharide is formed when two monomers join together by a loss of water molecule.

Final answer:

A disaccharide is formulated when two monosaccharides join through dehydration synthesis. A water molecule is dropped, and a glycosidic bond is formed between the two sugar elements. Sucrose, lactose, and maltose are crucial disaccharides for humans.

Explanation:

A disaccharide forms when two monosaccharides join by dehydration synthesis. This reaction involves a hydroxyl group (-OH) of one monosaccharide combining with a hydrogen atom of another monosaccharide. As a result, a molecule of water (H₂O) is released, and a covalent bond, specifically known as a glycosidic bond, forms between the two sugar molecules. Disaccharides critical for humans include sucrose (table sugar), lactose (milk sugar), and maltose (malt sugar). However, the human body cannot directly use these. They must first be split into their constituent monosaccharides via a separate process known as hydrolysis in the digestive tract.

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What would be the effect on the observed melting point of sample were poorly packed?

Answers

if a sample is packed poorly, the sample will not heat evenly and will take longer to melt.

How many grams of NaCl are produced when 0.548 moles of Na react with excess Cl2 according to the reaction above?2Na + Cl2 --> 2NaCl

Answers

Answer:

$\boxed {\boxed {\sf 32.0 \ g \ NaCl}}$

Explanation:

To solve this problem, we must use stoichiometry: the calculation of reactants and products in a chemical reaction using ratios.

1. Analyze the Reaction

$2Na+Cl_2 \rightarrow 2 NaCl$

Check the coefficients, which indicate the moles required for the reaction. 2 moles of sodium (Na) and 1 mole of chlorine (Cl₂) produces 2 moles of sodium chloride (NaCl).

2. Set Up Ratios.

We are asked to find the grams of NaCl produced when 0.548 moles of Na react with excess chlorine.

We need 2 ratios: 1 for finding the moles of NaCl produced and 1 for converting to grams.

The first ratio is found using the coefficients. Since there is excess chlorine, we only need to focus on the sodium and sodium chloride. According to their coefficients, 2 moles of Na produce 2 moles of NaCl. This is the first ratio.

$\frac { 2 \ mol \ Na }{2 \ mol \ NaCl}$

The second ratio uses the molar mass. Since we are solving for the grams of NaCl, we have to find its molar mass.

First, locate these values on the Periodic Table for the individual elements.

Na: 22.989769 g/mol
Cl: 35.45 g/mol

There is 1 of each atom in 1 molecule, so we can add these values.

NaCl: 58.439769 g/mol

Use this value as the second ratio.

$\frac {58.439769 \ g \ NaCl}{1 \ mol \ NaCl}$

3. Calculate

Make 1 expression using the 2 ratios and the initial value of moles.

$0.548 \ mol \ Na * \frac { 2 \ mol \ Na }{2 \ mol \ NaCl} * \frac {58.439769 \ g \ NaCl}{1 \ mol \ NaCl}$

Flip the ratios so the correct units cancel out.

$0.548 \ mol \ Na * \frac { 2 \ mol \ NaCl }{2 \ mol \ Na} * \frac {58.439769 \ g \ NaCl}{1 \ mol \ NaCl}$

Multiply. Note that the moles of Na (units) cancel and the moles of NaCl (units). cancel.

$0.548 * \frac { 2 }{2 } * \frac {58.439769 \ g \ NaCl}{1}$

$\frac {0.548 *2* 58.439769 \ g \ NaCl}{2}$

$\frac {64.049986824 \ g \ NaCl}{2} =32.024993412 \ g\ NaCl$

The original value of moles has 3 significant figures, so our answer must have the same. For the number we found, that is the tenth place.

32.02499341232

The 2 in the hundredth place tells us to leave the 0.

$32.0 \ g \ NaCl$

0.548 moles of sodium react with excess chlorine to produce 32.0 grams of sodium chloride.

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