MATHEMATICS HIGH SCHOOL

(Multiple Choice, 20 pts)Solve the rational equation 3 divided by x equals quantity 4 times x plus 3 divided by x squared, and check for extraneous solutions.

A. x = 0; x = 3 is an extraneous solution
B. x = 3; x = 0 is an extraneous solution
C. x = 0; x = −3 is an extraneous solution
D. x = −3; x = 0 is an extraneous solution

Answers

Answer 1

Answer:

Answer:

x = -3, x = 0 is a extraneous solution

Step-by-step explanation:

Step 1: Cross-multiply

3x² = 4x² + 3x

Step 2: Isolate x's

0 = x² + 3x

Step 3: Factor

0 = x(x + 3)

Step 4: Find roots

x = 0, -3

Step 5: Double check work

Plug in both to see if they both work. Only x = 0 should be extraneous. We now have our answer!

Answer 2

Answer:

Answer:

x = -3, x = 0 is a extraneous solution

Step-by-step explanation:

the person above is correct

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If h(x) = 5x − 3 and j(x) = −2x, solve h[j(2)] and select the correct answer below.17
23
−17
−23

Answers

sub 2 for x in j(x) and evalueate
then sub that result for x in h(x)

j(2)=-2(2)
j(2)=-4

now sub-4 for x in h(x)

h(-4)=5(-4)-3
h(-4)=-20-3
h(-4)=-23

answer is -23

9 students volunteer for a committee. How many different 6-person committees can be chosen?a. 1 b. 362,880 c. 60,480 d. 84

Answers

$9\cdot8\cdot7\cdot6\cdot5\cdot4=60,480\n\nAnswer:D$

396 divided by 9 =...?

Answers

Answer: 44

Step-by-step explanation: 396/9 = 44

Answer:

Step-by-step explanation:

You drop a ball from a height of 0.5 meter. Each curved path has 52% of the height of the previous path.a. Write a rule for the sequence using centimeters. The initial height is given by the term n = 1.
b. What height will the ball be at the top of the third path?

Answers

Answer:

$f(n)=0.5(0.52)^(n-1)$
0.14 m

Step-by-step explanation:

The initial height of the ball is 0.5 m

Each curved path has 52% of the height of the previous path, i.e the height of the ball after one bounce will be,

$=(52)/(100)* 0.5\n\n=0.52* 0.5\ m$

The height of the ball after 2 bounces will be,

$=(52)/(100)*(0.52* 0.5)$

$=0.52*0.52* 0.5$

$=0.52^2* 0.5\ m$

Hence the series becomes,

$0.5,0.5(0.52),0.5(0.52)^2,............$

This is the case of Geometric Progression.

But as it is given that the initial height will be given by n=1, so the rules for finding the height f(n) after n bounces would be,

$f(n)=0.5(0.52)^(n-1)$

Putting n=3, we can get the height of the ball of the third path,

$\Rightarrow f(3)=0.5(0.52)^(3-1)=0.5(0.52)^(2)=0.14\ m$

This is a geometric sequence. The first term is the max height of the first curved path, which is 0.5. The second one is 52% of that meaning that it is 0.52 times the first term. The third term is 0.52 times the second term. Thus, in this geometric sequence,

$a = 0.5$
$r = 0.52$

You will need to use the relation $a_n = a \cdot r^(n-1)$

The inner and outer Radii of a cylindrical pipe are 5 cm and 4 cm respectively. find the area of cross section of the pipe.

Answers

To do this find the area of the inner pipe, and then find the area of the outer pipe, then subtract the larger of the two from the smaller, and that is the area of the cross section

Answer:

28.3 cm²

Step-by-step explanation:

You find the area of the whole section which is 5²π = 25π.

Then you find the area of the empty part which is 4²π = 16π.

Then you subtract to get 9π which is 28.27433388......

= 28.3 cm²

What is the value of log 43? Use the calculator. Round your answer to the nearest tenth.