MATHEMATICS HIGH SCHOOL

Mr. Ferrier invested $26,000. Some was invested in bonds that made a 5% profit, and the rest was put in stocks that made an 8% profit. How much did mr. Ferrier invest in bonds if his total profit on both types of investments was $1,420

Answers

Answer 1

Answer:

Answer:

$22000

Step-by-step explanation:

x*0.05+(26000-x)*0.08= 1420

0.05x - 0.08x + 2080= 1420

0.03x=2080 -1420

0.03x= 660

x= 660/0.03

x= 22000

$22000 = 5% bonds

$4000 = 8% stocks

Answer 2

Answer:

Answer:

bonds=22000

stock=4000

Step-by-step explanation:

let b for bonds , and s for stock

b+s=26000

0.05 b +0.08 s=1420

to solve (by elimination)

1- multiply first equation with 0.05 to eliminate b

0.05 b+0.05 s=1300

0.05b+0.08s=1420

subtract two equations:

0.05b+0.05s-0.05b-0.08s=1300-1420

-0.03s=-120

s=120/0.03=4000

b+s=26000

b=26000-4000=22000

check:0.05(22000)+0.08(4000)=1420

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Answers

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The total operating cost for the truck is $400 000 per year. The percentage breakdown of this total amount was:40%: Fixed costs (insurance, registration, wages)
30%: Fuel
20%: Finance
10%: Maintenance (service, repairs, tyres)

Suppose the fuel price increases from $1.50 to $1.60 per litre.

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Answers

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G(x) = 3x -1. Find x such that g(x)= 20.g(x)= 3x+1. Find x such that g(x)= 22.

g(x)= 2x-5. Find g(1/2) and g(a)=99.
g(x)=x+5/2. Find g(3), g(0), g(-3) and g(x)=0

Please solve this quickly. I need it right now. No silly answer will not be allowed.

Answers

Step-by-step explanation:

i. 3x-1=20

or, 3x= 21

x= 7

ii. 3x+1= 22

3x= 21

x= 7

iii. 2x-5=99

2x= 104

x=52

iv. g(3)= 3+5/2= 11/2

g(0)= 0+ 5/2=5/2

g(-3)= -3+5/2 = -1/2

x+5/2= 0

so, x= -5/2

I don't understand this help !

Answers

I hope this helps you

try using wolframalpha to help you on that one

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Answers

The equation given in the question is
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6x + 3 = 0
6x = - 3
x = - (3/6)
= - (1/2)
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Answers

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Hope I helped ;D

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