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Answer the question ready fast right now​
answer the question ready fast right now​ - 1

Answers

Answer 1
Answer:

Answer:

<eba and <hbi are congruent angles

Step-by-step explanation:

They are vertical angles, therefore congruent

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Maria, Zach y Jill comparten una pizza. Maria come la mitad de la pizza, Zach come 4/6 y Jill come 3/12 de la pizza. ¿Quién come más?

An ice cream cone is filled with vanilla and chocolate ice cream at a ratio of 2:1. If the diameter of the cone is 2 inches and the height is 6 inches, approximately what is the volume of vanilla ice cream in the cone? (round to nearest tenth) A) 1.0 in3 B) 2.1 in3 C) 4.2 in3 D) 6.3 in3

Answers

Answer:

D. 6.3 in^3

Step-by-step explanation:

V= 1/3 (3.14)(r^2)(h)

V= 1/3 (3.14) (1^2)(6)

V=6.3 in^3

Answer:

c

Step-by-step explanation: it was on usa test prep and the answer that was there was wrong.

fruit-o-rama sells dried pineapple for$0.25 per ounce. mags spent a total of $2.65 on pineapple. How many ounces did she buy?

Answers

If you divide what she spent (2.65) buy the price per ounce (0.25) , you should come up with 10.6 ounces, which is the amount she bought.

Hope this helps :)
Divide the amount paid by the cost per ounce to find the number of ounces.

($2.65) / ($0.25/oz) = 10.6 oz

Answer: She bought 10.6 ounces

A student committee of 4 is formed by randomly drawing people (without replacement) from a collection of 4 sophomores, 4 juniors and 3 seniors. What is the probability the committee thus formed will have at least one representative from all three groups of students?

Answers

Answer: 0.04848

Step-by-step explanation:

Given : There are 4 sophomores, 4 juniors and 3 seniors.

Total choices = 4+4+3 = 11

Number of people needed to be chosen for committee = 4

Number of ways to select 3 people out of 11 (without replacement)=  ^(11)P_4

=(11!)/((11-4)!)\ \ \ \ [^nP_r=(n!)/((n-r)!)]

=(11*10*9*8*7!)/(7!)\n\n= 7920

 

 

Number of ways to select at least one representative from all three groups of students =  ^4P_2* ^4P_1* ^3P_1+^4P_1* ^4P_2* ^3P_1+^4P_1* ^4P_1* ^3P_2

=(4!)/(2!)*4*3+4(4!)/(2!)*3+4*4*(3!)/(2!)\n\n= 144+144+96=384

Required probability = (384)/(7920)=0.04848

Hence, the probability the committee thus formed will have at least one representative from all three groups of students = 0.04848

 

 

What sample size, including the 20 observations in the initial study, would be necessary to have a confidence of 95.44 percent that the observed time was within 4 percent of the true value?

Answers

Completed question:

An initial time study resulted in an average observed time of 2.2 minutes per cycle, and a standard deviation of .3 minutes per cycle. The performance rating was 1.20. What sample size, including the 20 observations in the initial study, would be necessary to have a confidence of 95.44 percent that the observed time was within 4 percent of the true value?

Answer:

47

Step-by-step explanation:

When doing a statistic study, a sample of the total amount must be taken. This sample must be done randomly, and, to be successful, the sample size (n) must be determined, by:

n = ((Z_(\alpha/2)*S )/(E))^2

Where Z(α/2) is the value of the standard normal variable associated with the confidence, S is the standard deviation, and E is the precision. The confidence indicates if the study would have the same result if it would be done several times. For a confidence of 95.44, Z(α/2) = 2.

The standard deviation indicates how much of the products deviate from the ideal value, and the precision indicates how much the result can deviate from the ideal. So, if it may vary 4% of the true value (2.2), thus E = 0.04*2.2 = 0.088.

n = [(2*0.3)/0.088]²

n = 46.48

n = 47 observations.

At the U.S. Open Tennis Championship a statistician keeps track of every serve that a player hits during the tournament. The statistician reported that the mean serve speed was 100 miles per hour (mph) and the standard deviation of the serve speeds was 15 mph. Assume that the statistician also gave us the information that the distribution of serve speeds was mound- shaped and symmetric. What percentage of the player's serves were between 115 mph and 145 mph

Answers

Answer:

15.74% of the player's serves were between 115 mph and 145 mph

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = (X - \mu)/(\sigma)

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 100, \sigma = 15

What percentage of the player's serves were between 115 mph and 145 mph

This is the pvalue of Z when X = 145 subtracted by the pvalue of Z when X = 115.

X = 145

Z = (X - \mu)/(\sigma)

Z = (145 - 100)/(15)

Z = 3

Z = 3 has a pvalue of 0.9987

X = 115

Z = (X - \mu)/(\sigma)

Z = (115 - 100)/(15)

Z = 1

Z = 1 has a pvalue of 0.8413

0.9987 - 0.8413 = 0.1574

15.74% of the player's serves were between 115 mph and 145 mph

Final answer:

A total of 27% of the player's serves at the U.S. Open Tennis Championship were between 115mph and 145mph. This was found using the Empirical Rule which applies to a normal distribution of serve speeds.

Explanation:

This problem is a classic example of the use of the Empirical Rule in statistics. The Empirical Rule, also known as the 68-95-99.7 rule, applies to a normal distribution, which is a bell-shaped curve (mound-shaped and symmetric) as mentioned in the problem. This rule states that approximately 68% of the data falls within one standard deviation from the mean, 95% within two standard deviations, and 99.7% within three standard deviations.

Given that the mean serve speed is 100 mph and the standard deviation is 15 mph, serves of 115 mph are one standard deviation above the mean and serves of 145 mph are three standard deviations above the mean. Therefore, we are looking for the percentage of serves between these two values. According to the Empirical Rule, this would be 95% (coverage for up to 2 standard deviations) minus 68% (coverage for up to 1 standard deviation), which equals 27%. So, 27% of the player's serves were between 115 mph and 145 mph.

Learn more about Empirical Rule here:

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Find three consecutive numbers whose sum is 612

Answers

Answer: 203, 204, 205

Step-by-step explanation:

Consecutive numbers are numbers that are right next to each other. An example would be 1,2,3 or 67,68,69. Since this problem is asking for three consecutive numbers where the sum is equal to 612, we need to find the numbers that will be greater than 200.

Since we know that the sum is 612, we know that the numbers will be in the 2 hundreds. All we need to do is find 3 numbers that equal to 12.

3+4+5=12

Now that we have the three numbers, let's add 200.

203+204+205=612

Therefore, the three numbers are 203, 204, 205.

Answer: 203, 204, 205

Step-by-step explanation:

Let's say the number is x.

So the three consecutive numbers are: x, x + 1, and x+ 2

3x + 3 = 612

3x = 609

x = 203

Plug in x.

203, 204, and 205
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