Carbon monoxide (CO) reacts with hydrogen (H2) to form methane (CH4) and water (H20).CO(g) + 3H2(g) + CH4(g)+H20(9)
The reaction is at equilibrium at 1,000 K. The equilibrium constant of the reaction is 3.90. At equilibrium, the concentrations are as
follows.
[CO] = 0.30 M
[H2] = 0.10 M
[H20] = 0.020 M
What is the equilibrium concentration of CH, expressed in scientific notation?
0.0059
5.9 x 10-2
0.059
5.9 x 102

Answers

Answer 1

Answer:

Answer: The equilibrium concentration of $CH_4$ , expressed in scientific notation is $5.9* 10^(-2)M$

Explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients.

The given balanced equilibrium reaction is,

$CO(g)+3H_2(g)\rightleftharpoons CH_4(g)+H_2O(g)$

At eqm. conc. (0.30) M (0.10) M (x) M (0.020) M

The expression for equilibrium constant for this reaction will be,

$K_c=([CH_4]* [H_2O])/([CO]* [H_2]^3)$

Now put all the given values in this expression, we get :

$3.90=(x* (0.020))/((0.30)* (0.10)^3)$

By solving the term 'x', we get :

x = 0.059 M= $5.9* 10^(-2)M$

Thus, the concentrations of $CH_4$ at equilibrium is :

Concentration of $CH_4$ = (x) M = $5.9* 10^(-2)M$

The equilibrium concentration of $CH_4$ , expressed in scientific notation is $5.9* 10^(-2)M$

Answer 2

Answer:

Answer:B

Explanation:B

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