Please Help me ASAP Just answers please ;)
Answers
Answer:
C
Step-by-step explanation:
< means exclusive, so open hole
≤ means inclusive, so closed dot
also, you can see that the values for y are going down, like 6, 4, 2. That's only in answer C.
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Classify the numbers as prime or composite
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Answers
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Answers
Answer:
Its B) 15x - 35
Answer:
15x + 35 is answer
Step-by-step explanation:
5x3=15
5x7=35
a. –11.81
b. –5.71
c. 5.71
d. 11.81
Answers
= 8.76 – 3.05
= 5.71
The answer is c.
Answers
The area and perimeter of an isosceles trapezoid with a 60° base angles and bases 9 and 13 is 38.105 squared units and 24 units respectively.
What is area and perimeter of the isosceles trapezoid?
The area of the isosceles trapezoid is the space occupied by it. It can be find out using the following formula,
Permiter of the isosceles trapezoid is the total length of the boundary by which it is enclosed. It can given as,
Here (a,b) are the base side (c) is the side of leg and (h) is the height.
The image of the given isosceles trapezoid is attached below. Let the value of leg is x units. Thus using right angle property the cos theta is,
And the height of this trapezoid is,
Thus the area of the solid is,
The perimeter of the solid is,
Thus, the area and perimeter of an isosceles trapezoid with a 60° base angles and bases 9 and 13 is 38.105 squared units and 24 units respectively.
Learn more about the area of the isosceles trapezoid here;
The other side of each right triangle is such that tan 60° = Heigth / 2
Then height = 2*tan60°.
The area of the trapezoid is height * (base 1 + base 2)/2
Then area = 2*tan (60°) * (13+9)/2 = 38.11
and the point P(-3,6) and then answer the following questions:
a. How would you find the line (B) that passes through point P and is perpendicular to line A? What is the equation of that line?
b. How would you find the length of the segment of line B from point P to line A?
c. How would you find the midpoint between point P and the intersection of line A and line B ?
Answers
Answer:
- y = -6/5x +12/5
- distance from P to A: (66√61)/61 ≈ 8.4504
- midpoint: (-18/61, 168/61) ≈ (-0.2951, 2.7541)
Step-by-step explanation:
a. The slope of the perpendicular line is the negative reciprocal of the slope of the given line, so is ...
m = -1/(5/6) = -6/5
Then the point-slope form of the desired line through (-3, 6) can be written as ...
y = m(x -h) +k . . . . . line with slope m through (h, k)
y = (-6/5)(x +3) +6
y = -6/5x +12/5 . . . equation of line B
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b. The distance from point P to the intersection point (X) can be found from the formula for the distance from a point to a line.
When the line's equation is written in general form, ax+by+c=0, the distance from point (x, y) to the line is ...
d = |ax +by +c|/√(a² +b²)
The equation of line A can be written in general form as ...
y = 5/6x -5/2
6y = 5x -15
5x -6y -15 = 0
Then the distance from P to the line is ...
d = |5(-3) -6(6) -15|/√(5² +(-6)²) = 66/√61
The length of segment PX is (66√61)/61.
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c. To find the midpoint, we need to know the point of intersection, X. We find that by solving the simultaneous equations ...
y = 5/6x -5/2
y = -6/5x +12/5
Equating y-values gives ...
5/6x -5/2 = -6/5x +12/5
Adding 6/5x +5/2 gives ...
x(5/6+6/5) = 12/5 +5/2
x(61/30) = 49/10
x = (49/10)(30/61) = 147/61
y = 5/6(147/61) -5/2 = -30/61
Then the point of intersection of the lines is X = (147/61, -30/61).
So, the midpoint of PX is ...
M = (P +X)/2
M = ((-3, 6) +(147/61, -30/61))/2
M = (-18/61, 168/61)
Final answer:
To find line B perpendicular to line A and pass through point P, calculate the negative reciprocal of line A's slope and use it in the line equation along with point P coordinates to find c. The segment length from point P to line A is calculated using the distance formula and involves finding the intersection point between lines A and B. The midpoint is calculated using the midpoint formula.
Explanation:
To answer this question, we need to understand that two lines are perpendicular if the product of their slopes is -1. Line A has a slope of 5/6. Therefore, the slope of line B, perpendicular to line A, is -6/5 (the negative reciprocal). The equation of a line is y = mx + c where m is the slope and c is the y-intercept. As line B passes through point P(-3,6), we can substitute these values into the line equation y = -6/5x + c to solve for c. This will give us the equation of line B.
To find the length of the segment from point P to Line A, we would first need to find the intersection point of Line A and B. Then use the distance formula, which is sqrt[(x2-x1)^2 + (y2-y1)^2].
The midpoint of two points, (x1,y1) and (x2,y2) is given by ((x1+x2)/2, (y1+y2)/2). This formula can be used to find the midpoint between point P and the intersection of line A and line B.
Learn more about Line Equations here:
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