MATHEMATICS COLLEGE

What are the angle measurements of 1,2,3,4,5 &6?

Answers

Answer 1

Answer:

Answer:

I:40,ii:65,iii:75,iv:40,v:75,vi:15

Step-by-step explanation:

75+65+i=180

140+i=180

i=180-140

i=40

i=iv=40(alternative angle)

65+40+v=180(straight line angle)

105+v=180

v=180-105

v=75

v=iii=75(alternative angle)

90+75+vi=180

165+vi=180

vi=180-165

vi=15

40+75+ii=180

115+ii=180

ii=180-115

ii=65

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Solve this equation using the inverse operation: x + 8 = -5

WHO WANTS BRANLIEST?!?!?!?!?!?!?!?

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Answer:

I Do

Step-by-step explanation:

HELP PLS MATH HELP ASAP CORRECT ANSWER ONLY PLS

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Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

3(2)+2=8

3(3)+2=11

3(4)+2=14

3(5)+2=17

3(6)+2=20

Sum=70

Is {(98,6),(99,0),(100,7)} a function?

Answers

Answer:

Yes , this is the function

Step-by-step explanation:

Because every domain has their only one image

A young sumo wrestler decided to go on a special high-protein diet to gain weight rapidly. When he started his diet, he weighed 79.5 kilograms. He gained weight at a rate of 5.5 kilograms per month. Let y represent the sumo wrestler's weight (in kilograms) after x months. Which of the following could be the graph of the relationship? graph of an increasing linear function in quadrant 1 with a positive y-intercept (Choice B) B graph of an increasing linear function in quadrants 1 and 4 with a positive x-intercept and negative y-intercept (Choice C) C graph of a decreasing linear function in quadrants 1 and 4 with a positive x-intercept and positive y-intercept (Choice D) D graph of a decreasing linear function in quadrant 4 with a negative y-intercept

Answers

Answer:

(Choice A) A graph of an increasing linear function in quadrant 1 with a positive y-intercept.

Step-by-step explanation:

The weight of the sumo wrestler starts at a positive value of 79.5 kilograms, and we are given that the sumo wrestler gains a linear amount of weight per month at 5.5 kilograms per month.

If we were to graph this relationship, the sumo wrestler's weight would be represented on the y-axis, and the amount of time on the x-axis.

So the initial weight would occur at (0, 79.5) which is the positive y-intercept.

And since his weight is increasing at 5.5 kilograms per month, the slope of the linear function is positive.

Hence, the graph of the linear increasing function in quadrant 1 with a positive y-intercept.

Cheers.

A doctor at a local hospital is interested in estimating the birth weight of infants. How large a sample must she select if she desires to be 90% confident that her estimate is within 4 ounces of the true mean

Answers

Answer:

The minimum sample size needed is $n = ((1.96√(\sigma))/(4))^2$ . If n is a decimal number, it is rounded up to the next integer. $\sigma$ is the standard deviation of the population.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = (1 - 0.9)/(2) = 0.05$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.05 = 0.95$ , so Z = 1.645.

Now, find the margin of error M as such

$M = z(\sigma)/(√(n))$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

How large a sample must she select if she desires to be 90% confident that her estimate is within 4 ounces of the true mean?

A sample of n is needed, and n is found when M = 4. So

$M = z(\sigma)/(√(n))$

$4 = 1.96(\sigma)/(√(n))$

$4√(n) = 1.96√(\sigma)$

$√(n) = (1.96√(\sigma))/(4)$

$(√(n))^2 = ((1.96√(\sigma))/(4))^2$

$n = ((1.96√(\sigma))/(4))^2$

The minimum sample size needed is $n = ((1.96√(\sigma))/(4))^2$ . If n is a decimal number, it is rounded up to the next integer. $\sigma$ is the standard deviation of the population.

An office building loses a third of its heat between sundown and midnight and an additional half of the original amount of heat between midnight and 4 AM. If five-eighths of the remaining heat is lost between 4 AM and 5 AM, what proportion of the total heat loss occurs between 5 AM and sunrise?