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Basic kinematics. Please help! Will give brainliest! Show all work!

Answers

Answer 1

Answer:

Answer: 3.5 m/s

Step-by-step explanation:

$v=(vf+vi)/(2)$

$v=(5+2)/(2)$

5+2=7

7/2= 3.5

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How do I prove this with the double angle law

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$sin(2x) = 2 sin x cos x \n \n cos(2x) = cos^2 x - sin^2 x$
After Substituting:
$(2 sin x cos x)/(1+cos^2 x - sin^2 x)$
Use pythagorean thm:
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Which one of these transformations move by sliding in any direction?A.Translation
B.Rotation
C.Reflection
D.Dilation

Answers

Answer:

D. Dilation, sorry if i'm wrong ;)

Step-by-step explanation:

Organisms A and B start out with the same population size. Organism A's population doubles every day. After 5 days, the population stops growing and a virus cuts it in half every day for 3 days. Organism B's population grows at the same rate but is not infected with the virus. After 8 days, how much larger is organism B's population than organism A's population? Answer the questions to find out. The expression showing organism A's decrease in population over the next 3 days is ( 1 2 ) ( 2 1 ) 3 . This can be written as (2–1)3. Write (2–1)3 with the same base but one exponent.

Answers

Answer:

The number of times organism B's population is larger than organism A's population after 8 days is 32 times

Step-by-step explanation:

The population of organism A doubles every day, geometrically as follows

a, a·r, a·r²

Where;

r = 2

The population after 5 days, is therefore;

Pₐ₅ = = 32·a

The virus cuts the population in half for three days as follows;

The first of ta·2⁵ he three days = 32/2 = 16·a

The second of the three days = 16/2 = 8·a

After the third day, Pₐ = 8/2 = 8·a

The population growth of organism B is the same as the initial growth of organism A, therefore, the population, P₈ of organism B after 8 days is given as follows;

P₈ = a·2⁸ = 256·a

Therefore, the number of times organism B's population is larger than organism A's population after 8 days is P₈/Pₐ = 256·a/8·a = 32 times

Which gives, the number of times organism B's population is larger than organism A's population after 8 days is 32 times.

Final answer:

Organism A's population at the end of 5 days is 2^5. After 5 days, a virus cuts it in half for 3 days. Organism B's population at the end of 8 days is 2^8. To find the difference, subtract organism A's population from organism B's population.

Explanation:

Organism A's population doubles every day for 5 days, so the population at the end of 5 days is 25. After 5 days, a virus cuts the population in half for 3 days, so we need to find (25) * (2-1)3. Using the rule of exponents, we can rewrite this expression as (25+(-1*3)), which simplifies to 2-4.

Organism B's population grows at the same rate but is not infected with the virus. After 8 days, the population is 28.

To find out how much larger organism B's population is than organism A's population, we need to subtract the population of organism A from organism B. So, 28 - 2-4 is the answer.

Learn more about Population growth and virus impact here:

brainly.com/question/32372080

#SPJ3

Two lines in the plane of a floor are

Answers

Answer:

never skew

Step-by-step explanation:

-3.6 divided by -0.75

Answers

Answer:

4.8

Step-by-step explanation:

the two negatives cancel each other

Answer:

4.8

Step-by-step explanation:

Since both numbers are in negative form and a division is supposed to occur, take away the negative so that the division can properly occur:

3.6 ÷ 0.75

Now simplify:

4.8

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Which statements about geometric sequences are correct? Check all that apply. In a geometric sequence, the ratio between each of the consecutive terms is the same, or constant. Multiply the common ratio by the last term to extend a geometric sequence.
The sequence 2, 8, 32, 128, . . . is geometric.
The sequence 5, 10, 15, 20, . . . is geometric.
The sequence 3, 18, 108, 648, . . . is geometric.

Answers

Answer:

1,2,3,5

Step-by-step explanation:

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