A cylindrical package to be sent by a postal service can have a maximum combined length and girth (perimeter of a cross section) of 141 inches. Find the dimensions of the package of maximum volume that can be sent. (The cross section is circular.)

Answers

Answer 1
Answer:

Answer:

Length = 47 in

Radius = 47/π in

Step-by-step explanation:

Let 'h' be the length of the package, and 'r' be the radius of the cross section.

The length and girth combined are:

L+G=141=h+2\pi r\nh=141-2\pi r

The volume of the cylindrical package is:

V=A_b*h\nV=\pi r^2*h

Rewriting the volume as a function of 'r':

V=\pi r^2*h\nV=\pi r^2*(141-2\pi r)\nV=141\pi r^2-2\pi^2 r^3

The value of 'r' for which the derivate of the volume function is zero yields the maximum volume:

V=141\pi r^2-2\pi^2 r^3\n(dV)/(dr)=282\pi r-6\pi^2r^2=0\n 6\pi r=282\nr=(47)/(\pi) \ in

The length is:

h=141-2\pi r=141-2\pi*(47)/(\pi)\nh=47\ in

The dimensions that yield the maximum volume are:

Length = 47 in

Radius = 47/π in


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Answers

Answer:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

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The surface of a mountain is modeled by the equation h(x, y) = 5000 - 0.001x² - 0.004y². A mountain climber is at the point (500, 300, 4390). In what direction should the climber move in order to ascend at the greatest rate?

Answers

Answer:

i-2.4j

Step-by-step explanation:

Given that,

The surface of a mountain is modeled by the equation as follows :

h(x,y)=5000 -0.001x^2-0.004y^2

A mountain climber is at the point (500, 300, 4390).

We need to find the direction in which he should move in order to ascend at the greatest rate.

To find direction, first finding the gradient of h as follows :

\nabla h(x,y)=-0.002xi-0.008yj

Now put x = 500 and y = 300

So,

\nabla h(x,y)=-0.002(500)i-0.008(300)j\n\n\nabla h(x,y)=i-2.4j

The direction of the climber is i-2.4j