A 30 W engine generates 3600 J of energy. How long did it run for?

Answers

Answer 1
Answer:

Answer:

so the time taken will be 120 seconds

Explanation:

power=30W

work done=3600J

time=?

as we know that

power=(work done)/(time taken)

evaluating the formula

power×time taken=work done

time taken=(work done)/(power)

time taken=(3600J)/(30W)

Time taken=120seconds

i hope this will help you :)


Related Questions

Given a double slit apparatus with slit distance 1 mm, what is the theoretical maximum number of bright spots that I would see when I shine light with a wavelength 400 nm on the slits
Beverage can is thrown upward and then falls back down to the floor. As usual, a y axis extends upward (positive direction). Which of the following best describes the acceleration of the can during its free flight?a) -9.8 m/s^2, then momentarily zero, then +9.8 m/s^2b) +9.8 m/s^2 throughoutc) -9.8 m/s^2 throughoutd) zero throughoute) +9.8 m/s^2, then momentarily zero, then -9.8 m/s^2
A car travels 13 km in a southeast direction and then 16 km 40 degrees north of east. What is the car's resultant direction?
If the solution described in the introduction is cooled to 0 ∘c, what mass of kno3 should crystallize? enter your answer numerically in grams.
Tell uses of cancave mirror and convex mirror.​

What is 902 in proper scientific notation?

Answers

Hope it help you 9.02x10^2

A long copper cylindrical shell of inner radius 5 cm and outer radius 8 cm surrounds concentrically a charged long aluminum rod of radius 1 cm with a charge density of 7 pC/m. All charges on the aluminum rod reside at its surface. The inner surface of the copper shell has exactly opposite charge to that of the aluminum rod while the outer surface of the copper shell has the same charge as the aluminum rod. Find the magnitude and direction of the electric field at points that are at the following distances from the center of the aluminum rod: (a) 0.5 cm,
(b) 1.5 cm,
(c) 2.5 cm,
(d) 3.5 cm,
(e) 7 cm.

Answers

Answer:

a. 0

b. 8.4N/C

c. 5.04N/C

d. 3.6 N/C

e. 1.8N/C

Explanation:

The following data are given

inner cylindrical radius,r=5cm

outer cylindrical radius R=8cm

Charge density,p=7pc/m

radius of rod= 1cm

a. at distance 0.5cm from the center of the rod, this point falls on the rod itself and since the charge spread out on the surface of the rod, there wont be any electric field inside the rod itself

Hence E=0 at 0.5cm

b. at 1.5cm i.e 0.015m

the electric field is expressed as

E=(2*charge density)/(4\pi E_(0)r)\nE=(2*7*10^(-12) *9*10^(9))/(0.015)\nE=8.4N/C

The direction of the field depends on the charge on the rod

c. at 2.5cm i.e 0.025m

the electric field is expressed as

E=(2*charge density)/(4\pi E_(0)r)\nE=(2*7*10^(-12) *9*10^(9))/(0.025)\nE=5.04N/C

The direction of the field depends on the charge on the rod

d. at 3.5cm i.e 0.035m this point is still within the rod and the inner cylinder

the electric field is expressed as

E=(2*charge density)/(4\pi E_(0)r)\nE=(2*7*10^(-12) *9*10^(9))/(0.035)\nE=3.6N/C

The direction of the field depends on the charge on the rod

e. at 7cm which is a point outside the rod and the cylinder, the electric field is

E=(2*charge density)/(4\pi E_(0)r)\nE=(2*7*10^(-12) *9*10^(9))/(0.07)\nE=1.8N/C

The direction of the field depends on the charge on the rod

Someone please help with these 2

Answers

Answer:

Explanation:

The formula that you are working with is F = m*a

Since mass is one part of the formula if you increase the mass, you are going to increase the force.

The second one is much more difficult to answer because it is basically incomplete. This is one way to interpret it. If you start at a certain speed and increase during a known time period then effectively you are defining acceleration which is "a" in the formula.

Without those modifications, there is no answer.

A uniform piece of wire, 20 cm long, is bent in a right angle in the center to give it an L-shape. How far from the bend is the center of mass of the bent wire?

Answers

Answer:TL;DR: 3.535 cm

Explanation:

Xcm = ΣxMoments/ΣMasses = (10*0 + 10*5)/(10+10) = 50/20 = 2.5 cm

by symmetry,

Ycm = 2.5 cm

The distance D from the point Xcm,Ycm to the origin is D = √(2.5²+2.5²) = 3.535 cm

Final answer:

The center of mass of the bent wire is approximately 11.18 cm from the bend.

Explanation:

In order to find the center of mass of the bent wire, we need to divide it into two segments: the horizontal segment and the vertical segment. The length of each segment is half of the total length of the wire, which is 20 cm, so each segment is 10 cm long.

The center of mass of the horizontal segment is located exactly at its middle point, which is 5 cm from the corner. The center of mass of the vertical segment is also located at its middle point, which is 10 cm from the corner. Since the horizontal and vertical segments are orthogonal, the distance from the bend to the center of mass of the bent wire is the hypotenuse of a right triangle with legs of length 5 cm and 10 cm. Using the Pythagorean theorem, we can calculate the distance:

d = sqrt(5^2 + 10^2) = sqrt(25 + 100) = sqrt(125) = 11.18 cm

Therefore, the center of mass of the bent wire is approximately 11.18 cm from the bend.

Which of the following describes the net force acting on an object?The sum of all forces acting on an object
The gravitational force minus any contact forces acting on an object
The difference between the normal force and the gravitational force acting on an object
The sum of all the forces acting on an object in the same direction

Answers

The sum of all forces acting on an object in the same direction is described for the net force acting on an object.

What is a Net force?

  • When the forces are acting in the same direction of movement of the object it can be said as sum of the two individual forces will be equal to the "Net Force" .
  • The net force is the combined force of all individual forces acting on an object.
  • If the object with the forces in the opposite direction, then the net force will not be equal to the sum of the forces.

Example : If two forces (2 kids pushing in the same direction to move the object big box) act on an object (big box) in the same direction, then the net force is equal to the sum of the two forces. If the kids pushed in the opposite direction, the net force will not occur.

Hence, Option D is the correct answer.

Learn more about Net force,

brainly.com/question/6000441

#SPJ6

Answer:

The sum of all the forces acting on an object in the same direction.

A friend tells you that a lunar eclipse will take place the following week, and invites you to join him to observe the eclipse through a high-powered telescope he owns. You are curious what the eclipse might look like from different perspectives in space. If the moon has a diameter of 2,159.14 miles, what is the maximum distance that it could be observed by the naked eye with enough detail that you could distinguish it from other celestial bodies (assuming that you have 20/20 vision)

Answers

Answer:

y = 80.2 mille

Explanation:

The minimum size of an object that can be seen is determined by the diffraction phenomenon, if we use the Rayleigh criterion that establishes that two objects can be distinguished without the maximum diffraction of a body coincides with the minimum of the other body, therefore so much for the pupil of the eye that it is a circular opening

          θ = 1.22 λ/ d

in a normal eye the diameter of the pupils of d = 2 mm = 0.002 m, suppose the wavelength of maximum sensitivity of the eye λ = 550 nm = 550 10⁻⁹ m

         θ = 1.22 550 10⁻⁹ / 0.002

         θ = 3.355 10⁻⁴ rad

Let's use trigonometry to find the distance supported by this angle, the distance from the moon to the Earth is L = 238900 mille = 2.38900 10⁵ mi

       tan θ = y / L

       y = L tan θ

       y = 2,389 10⁵ tan 3,355 10⁻⁴

       y = 8.02 10¹ mi

       y = 80.2 mille

This is the smallest size of an object seen directly by the eye

Final answer:

An individual with 20/20 vision can observe the moon from a maximum distance of around 6200 km or 3850 miles. Beyond this distance, it might be difficult to distinguish the moon from other celestial objects without using a telescope. The use of a telescope can expand this range significantly.

Explanation:

The detailed observation of a lunar eclipsed, when viewed without any form of optical aid like a telescope, is contingent on many factors, one of which is the human eye's angular resolution—the eye's ability to differentiate between two separate points of light. For an average human eye with 20/20 vision, the angular resolution is approximately 0.02 degrees.

To calculate the maximum distance at which the moon could be observed clearly with the eye, the formula for small angle approximation can be used, which in this context is: Distance = Size / Angle = (2159.14 miles) / (0.02 degrees in radians). This calculates to a distance of approximately 6200 km or 3850 miles.

Beyond this distance, distinguishing the moon from other celestial bodies might be challenging using just the eye. Utilizing a high-powered telescope would significantly extend this range by magnifying the image, allowing clearer detail over much greater distances.

Learn more about Observing Moon here:

brainly.com/question/34031036

#SPJ3